Transcript for:
இரசாயன தீர்மானம் மற்றும் அதன் விளைவுகள்

okay good evening good evening guys good evening everyone good evening i welcome you all again to the neet elite after two days yeah is that hope you guys are doing great having the good time well let me know in the chat box if i'm audible and visible to everyone right here let me know let me know in the chat box if i'm audible and visible to every single guy right here i'm doing great guys i'm doing great well people from past two days i couldn't take the session on this channel because i was busy solving the je question papers on the je channel yeah okay that's why i was not able to come over here but from now onwards these are going to be regular sessions right here yeah okay priya i'm doing wonderful how are you doing how are you doing let me know good evening kelvin hi pranish jaithan atomic structure will do also well yeshwanth has come up with a quote character cannot be developed in ease and quite only through experience of trial and suffering uh can the soul be strengthened okay ambition inspired and the success that's wonderful that's wonderful bro that's great okay well people i think in the last session we did the inductive effect i hope you remember that yes okay well in the tonight session what we are going to do is we are going to talk about the resonance and the resonance effect in detail okay we are going to talk about what this resonance is all about okay what this resonance effect is but let me tell you this resonance effect cannot be finished in a single session so after this there will be one more session on this resonance effect over here and the questions which we'll be doing in the next session yeah right okay well before starting this session let me introduce myself as you all must be knowing now my name is wasim bhatt and i'm your chemistry master teacher writer okay all right for the ones who have no idea about the neat 2021 crash course which we have started on the actual vedanta platform well people what all benefits you guys are going to get if you'll enroll yourself in this neat 2021 crash course people first thing you are going to get trained by the teachers of your choice in your physics chemistry as well as biology apart from that we are going to cover your whole syllabus before the need 2021 examination right there is no no need to worry about the test series no need to worry about the mock test everything is included right here in this crash course and at the same time you'll be getting the separate sessions by means of which you'll be getting to know how to solve the questions in lesser time about the time management everything will be done in this crash course everything is included right here in this crash course and at the same time it's going to be a two-way learning interactive platform wherein you can ask your doubts anytime to your master teachers right okay well people how to get enrolled in this how to get enrolled in this how to take this crash course you just need to click on the vedantu app after clicking on the vedantu app you need to click on the uh neat crash course after clicking on the neet crash course what you guys are supposed to do is just use the coupon code as wscc if you want me to personally train you for the neet 2021 in chemistry right okay and after using this coupon code you'll be getting the additional 20 off and after the 20 off you are just getting this crash course for 8k yeah okay well there is the link in the description box of the video as well you can enroll yourself in from there as well okay there's a link you need to click on that link use the code get enrolled from there as well okay either you click on the vedantu app or you can click on the link which is there in the description box of the video yes i'm doing wonderful hi antoni good evening good evening uh rumel uh chemical contacts is completed i guess or there was one session pending that was arena's equation i guess i don't remember exactly i'll let you know i'll get i'll check it out yeah oh it's not updated in the playlist all right i'll talk to the team they'll they'll do that they'll do they'll do that okay all right so for the ones who have not liked the video yet do like the video share and subscribe the channel at the same time so that everyone gets benefited out of these sessions right uh okay so let me know in the chat box if you guys are super duper excited for the tonight's session which is going to be the resonance effect yes let me know in the chat box with the thumbs ups let me see the josh of the session first then we'll then we'll see it yeah then we'll start let me know in the chat box let me know in the chat box let me know in the chat box yes he's doing good now he's doing good okay people are super duper excited yes no harish definitely bro we'll be covering everything organic inorganic everything physical is almost dusted right yeah yes angie i'm done with the dinner as well yes yes yes absolutely it's it's it's 11 right now 11 10. okay so people let's get to know something called us resonance right here okay first thing why this concept of resonance was given let me make you understand why this concept of resonance was given then only we'll get to know what this resonance is all about and i want you guys to take a note of everything whatever we'll be drawing on the screen whatever i'll be writing on the screen i want you guys to take a note of every single thing right here okay uh ashish bro this is the english channel i'm not supposed to talk in hindi so yeah i'm really sorry bro this is particularly for the ones who cannot understand hindi yeah okay all right so what i was telling right here is what was the need to give the concept of resonance yes remember guys whenever we cannot draw the true structure of the molecule whenever we cannot draw the true structure of the molecule or whenever a single structure of a molecule cannot explain all the properties of it okay whenever we cannot draw the true structure of the molecule or i can say something like this whenever a single structure of a molecule cannot explain all the properties of the molecule that actually means that molecule will be exhibiting resonance okay got it whenever we cannot draw the true structure of the molecule whenever a single structure of the molecule cannot explain all the properties of it remember at that time a molecule exhibits resonance yes point number one right which i've told you right here okay now people if we talk about benzene if we talk about benzene right if we talk about benzene if i'll ask you what is the structure of benzene most of you people will give me either this as the structure of benzene or they'll be giving me this one as the structure of benzene they'll be giving me this one as the structure of benzene right some people will say this is the structure of benzene some people will say this is the structure of benzene right but people if you would have studied benzene carefully we know in case of benzene all the bond lengths are identical we know in case of benzene all the bond lengths are identical right all the bond lengths are identical correct and one more thing about benzene one more thing about benzene benzene does not show the properties of the alkene okay let's not talk about that first let's talk about this single thing right here first okay see if i talk about benzene right here we know in case of benzene all the bond lengths are identical they are equal right and what we have drawn right here we have drawn two structures of benzene some people among you have said this is the structure of benzene some people among you have said this is the structure of benzene right but we know in case of benzene all the bonds bond lengths are equal right if i'll consider this structure right here as for this structure between these two carbon atoms right here there's a single bond between these two carbon atoms right here there's a double bond between these two carbon atoms again single bond again double bond right and we know strength of the double bond is greater than the strength of the single bond we know that right so definitely bond length in case of double bond should be less than the bond length in case of a single bond right so as for this structure as for this structure as per the structure will all the bond lengths be same no way right but we know but we know but we know in case of what but we know in case of benzene all the bond links are same right but as per this structure all the bond lengths are not same similarly as for this structure all the bond links are not same right here okay i hope you got it what i said correct see what i said right here for benzene we know all the uh all the carbon carbon bond lengths are identical right and benzene it does not behave like a normal alkene it does not behave actually benzene does not behave like a normal eclain but people as i told you four minutes back if i'll ask you what is the structure of benzene i mean some people among you uh will be giving me one structure some people among you will give me other structure and those structure won't be explaining all the properties of the benzene right those structures won't be explaining all the properties of the benzene right just i told you a few minutes back right if i assume this is the structure of benzene this structure of benzene is not going to explain all the properties of it right because we know for the benzene all the bond lengths must be equal but as for this structure all the bondings won't be equal yes so this is the structure which is not explaining all the properties of benzene so what i should get into my head i should straight away get something into my head that benzene must be exhibiting resonance that's why it's single structure is not explaining all the properties of benzene right here yes correct yes now people now before talking about what this resonance is all about i told you why this concept was given why this concept was given because some structures couldn't explain all the properties of a molecule right that's that that actually implied that the molecule exhibits resonance yes now what this resonance is all about before talking about that resonance i need to give you some basic things right here which you must know before starting the resonance over here let's talk about those basic things right first okay right okay the first thing which i'll be writing over here see that's something called as localized electron pair okay i'll use that term right here localized electron pair what is this localized electron pair all about remember when an electron pair is shared only between two atoms whenever the electron pair is shared only between two atoms we call that electron pair as the localized electron pair we call that electron pair as the localized electron pair yes okay for example like this let's say i've got a single bond b now this is one more electron pair between a and b this electron pair is just between two atoms right it is just between two atoms it is being shared by two atoms whenever electron pair like this is shared between two atoms we call this electron pair as the localized electron pair we call this electron pair as the localized electron pair which is just shared between two atoms right similarly if i talk about this one if i talk about this one say on oxygen you are going to lone pair this lone pair belongs to oxygen this lone pair belongs to oxygen i'll be calling this lone pair as the localized lone pair right this electron pair it is shared between only two atoms i'll be calling this electron pair as the localized electron pair and this lone pair which is of oxygen basically okay i'll be calling this as the localized lone pair of oxygen right here yes i can see that okay now people after this there is something called as delocalized electron pair what is delocalized electron pair all about okay remember a pair of electron which is shared between more than two atoms whenever i'll be having such pair of electron which will be shared between more than two atoms we call we call that electron pair as the delocalized electron pair right here for example for example have a look see let's say i've got something like this a single bond b single bond c right for example at one instant i could see the electron pair between a and b at another instant at another instant what i could saw what i could see is i saw the electron pair i saw the same electron pair between b and c after some time yes correct see at first instant i saw the electron pair between a and b after some time i saw the same electron pair between b and c right here so can i say the same electron pair is being shared by more than two atoms we call this electron pair right here as the delocalized electron pair which is shared between more than two atoms right here okay so localized electron pair is the one which is shared by two atoms delocalized electron pair is the one which is shared between more than two atoms okay got it now now guys now the point is now the point is now the point is which electrons are delocalized which electron pairs are delocalized okay remember a high energy electron pair can be delocalized like your pi electrons what does that mean what does that mean understand that as well what i said right here first thing a pair of electrons that is shared between more than two atoms we call that pair of electron as the as the delocalized electron now which electron pair will be delocalized that electron pair that electron pair which will be having high energy a high energy electron pair can be delocalized and the example of that delocalized electron pair is going to be the pi electron right okay now the point is how come pi electrons have got high energy how come we call why we call these pi electrons as high energy electrons why we call these this the pi electron pair why we call the pi electrons why we call the pi electron pair as the as the high energy electrons higher high energy electron pairs right there's a point there's a there's a reason for that okay see guys i hope you would have studied chemical bonding yes i hope you have studied chemical bonding in the chemical bonding you'd have discussed one topic called as vbt okay and vbt explains the formation of sigma bond and the and the pi bond due to the head-on overlapping as well as parallel overlapping right do the head-on overlapping do the direct overlapping which bond is formed sigma bond is formed right and due to the and do the parallel overlapping which bond is formed which bond is formed due to the parallel overlapping i must say the pi bond is formed if you remember yeah correct now we will have a look let's say this is one atom which i have let's say this is the nucleus of one atom correct let's say this is one orbital okay let's say this one orbital of it this is one more orbital of one more atom okay and this is the head-on overlap so over here which bond is formed sigma bond is formed correct let's say this is one more orbital of this atom let's say this one more orbital of this atom can i say they are going to show the sideways over parallel overlap which leads to the formation of pi bonds so right here which bond got formed pi bond got formed okay right can i say this this electron density this electron density right here it is under the influence of it is under under the direct influence of these two nucleuses right can i say this electron part this electron density right here which led to the formation of sigma bond it is under the influence of two nucleuses directly yes but what about this electron density guys what about this electron density is this under the influence of two nucleus directly no way no way that electron density which experiences which experiences more force of attraction that electron density we say it has got less energy okay and that electron density which experiences less force of attraction from the nucleus less force of attraction from the nucleus we say that electron density have got higher energy right higher energy means that's what i told you right that's what i told you feminist back a high energy electron pair can be delocalized like pi electrons these are basically this is basically the pi electron density and pi electron density is having high energy and remember only only high energy electron pair can be delocalized like your pi electron which will be which will be which will be less under the influence of the nucleus yes exact exactly right right is it clear taylor is it clear till is it clear tiller yeah let me know in the chat box first yes i'll be giving the examples also just wait for it i'll be giving the examples this is just a starting wait okay right okay now now guys we got to know high energy electron pair can be delocalized like your pi electrons and the delocalization of these pi electrons is what we call as a resonance right delocalization of these pi electrons is what we call as a resonance now the point is what is this d localized you know pi electrons yeah that's something which is which we should know first right what is this d localization of electrons first thing which i told you a pair of electron which is shared between more than two atoms that's what we call as delocalized electron pair right now which electron pairs can be delocalized those electron pairs which will be having high energy those are going to be delocalized like your pi electrons right and the d localization of these high energy electrons delocalization of these pi electrons that's something which we call as resonance now the point is what is this delocalization of pi electrons all about right what is this d localization of pi electrons all about right let me tell you the sigma electrons are under the subjugation of are under the subjugation of more more attraction between the nucleus right more attraction means more attraction actually means they have got it has got less potential energy right something which we discuss in physics whenever there are attractions energy is released less energy is there with the system less energy means more stability right in case of pi electrons pi electrons are are less are under the less influence of the nucleus right so there'll be less attraction on that if there is less attraction on the pi electrons the pi electron energy will be definitely more yeah i hope you got it yes okay got it uh yes i am taking class on the railway on the platform also yes absolutely all right see you guys understand now so i hope these three points are clear now the point is the deal i told you delocalization of pi electrons is something called as a resonance now what the point is the point is what is this delocalization all about what is this d like relocalization all about let's understand the concept of delocalization right here okay in order to make you understand the concept of delocalization of pi electrons i'm going to take the orbital approach of resonance by means of which you'll get the idea of what is this delocalization of pi electrons all about yeah see i hope you remember the structure of benzene yes what is benzene it's a six membered ring yeah see if i'm making a structure of benzene like this isn't it a six membered ring like this correct in case of benzene do you do you remember in case of benzene every carbon is sp2 hybridized yes every carbon is sp2 hybridized right right these are the sigma bonds between carbon carbon carbon these are all the sigma bonds yes okay and which hybridization this this carbon undergoes right here sp2 hybridization can i say there'll be one mtp orbital on this carbon right here yes which will be perpendicular to the plane containing these pawns containing these sigma bonds absolutely there will be one more empty orbital like this there'll be one more empty orbital like this with this one there'll be one more like this one more like this one more lives on every carbon atom you'll see one unhybridized p orbital on every carbon right here yes now people sigma bond has already got formed between the carbon atoms right now is the term turn forward now is the turn for pi bonds right see this sigma bond as i told you earlier it's formed by the direct overlap okay direct overlap of the orbitals of the hybrid orbitals direct overlap of the hybrid orbitals direct overlap direct overlap direct overlap now what is going to happen now there will be parallel overlapping now there will be parallel overlapping all these mtp orbitals they are parallel to each other they are parallel to each other now the cases arise right here there can be parallel overlapping and that parallel overlapping can be done many ways how have a look see guys the first possibility which i'm writing over here first of all let me make the six membered ring writer again the first possibility which i am showing you right here the first possibility which can happen which can happen this one and this one will show overlap okay at the same time this one and this one will show overlap at the same time this one and this one will show overlap right and this is first of all the parallel overlapping and parallel overlapping leads to the formation of what it leads to the formation of pi bond right so due to this overlap can i say one pi bond would have got formed right here similarly due to this partial overlap due to this parallel overlap one more pi bond would have got formed right here due to this one more pi bond would have got formed right here so this is one probability this is one probability that these two orbitals would have overlapped these two orbitals would have overlapped and these two orbitals would have overlapped parallely which would have resulted into this structure this is one bubble structure i will say which i'm assuming something something like this would have happened right at the same time there is one more possibility at the same time there is one more possibility at the same time let's let's assume these orbitals have not overlapped let's assume this orbital i mean i'm changing the color let's say this orbital and this orbital has overlapped okay let's assume this orbital and this orbital has overlapped let's assume this orbital and this orbital has overlapped okay which which would be giving me one more structure like this which is going to be one more probable structure of benzene there's going to be one more bubble structure of benzene okay and due to this overlapping a pi bond would have got formed right here a pi bond would have got formed right a pi bond would have got form right here so i got two probable structures of benzene right here i got two probable structures of benzene right here but people if i consider any one of the problem structures among these two this is one probable structure this is one more probable structure which would have happened right is this structure explaining all the properties of benzene no way why is that because because because we know as per your benzene is concerned it has got identical bond lengths but as for this structure right here double bond okay right here single bond right a double bond right here single bond so all the bond bond lengths are not going to be identical yes right all the bond links are not going to be identical yes correct so this structure is not explaining all the properties of benzene similarly this structure is not explaining all the properties of benzene right this structure is not explaining all the properties of benzene correct but we will at the same time i can say something this structure is giving me some information about benzene this this structure is also giving me some information about the benzene right this is giving me some information about the benzene this this structure is also giving me some information about the benzene right correct now what i'll be doing right here what is going to be the actual structure of benzene correct if this is not the actual one this is not the actual what is going to be the correct one in case of benzene what happens all these p orbitals all these p orbitals all these p orbitals they are going to overlap parallelly simultaneously right they are going to simultaneously overlap parallely right here which leads to the formation of one angular electron density on the top of the on the top of the plane which consists of the sigma bonds yeah yes let me show it like this let me show it to you like this see the actual structure benzene is going to be like this this is going to be the six membered ring in which you have got the sigma bonds six sigma bonds right okay right here in this one okay now people on the top of it there is going to be electron density one angular electron density i'll call this as pi electron density okay on the top of it correct this is your pi electron density this is your pi electron density so actually in case of benzene all these pi orbitals they overlap partially but simultaneously which leads to the formation of one angular electron cloud writer okay i can see that i can say that yes now people if i ask you if i ask you if i ask you in this structure which i got this is the actual structure of benzene now this is the actual structure of benzene in which these p orbitals in which these p orbitals would have partially overlapped simultaneously okay if i ask you can i localize can i localize the pi electrons between the two carbon atoms right here i cannot say whether the pi electrons are between these two carbon atoms i cannot say whether the pi electrons are between two carbon atoms i cannot see whether the pi electrons are between two between these two between these two no i cannot check that right so i can say pi electrons right here in this structure are delocalized yes right right i cannot say i can say pi electrons right here are delocalized i'm i'm unable to locate them between two carbon atoms right i have no idea whether the pi electrons are between these two these two these two these two no way so i'll say this is the delocalizing this is something called as delocalization of pi electrons right and this delocalized you know pi electrons is what we call us is what we call as the resonance got it got it let me know in the chart box let me know in the chat box yes let me know in the chat box so it's clear dusted yes got it if i ask you one thing if i ask you one thing is this structure giving me the complete information about the benzene no way is this structure giving no right that structure that proposed structure that probable structure which does not give me the complete information about the actual molecule that probable structure is something called as canonical structure or resonating structure i'll be calling this structure and this structure i'll be calling these two structures as the canonical structures canonical forms or the resonating structures of the benzene right and how do i represent benzene actually now how do i represent the true structure of benzene true structure of benzene i'll be representing like this right this is the angular electron density which is on the top of the plane which contains these sigma bonds right here yes this is something which i called as the true structure or this is something which i call as the resonance hybrid this is something which i call as the resonance hybrid writer yes is that clear got it got it very very simple can i say this resonance hybrid it is basically the combination of these two it is basically the combination of these two how come this resonance hybrid is combination of these two canonical structures these two resonating structures how come have a look as per the as for the first one as per this structure is concerned between these two carbon atoms there is a single bond but as for this structure ah just a second guys wait uh where is that bond just a second see as per as per these two as for this structure is concerned between these two carbon atoms there should be double bond but as for this structure is concerned between these two carbon atoms there is there should be single bond right right so what is going to happen as for this structure there should be a single bond as per this structure there should be a double bond between these two right can i say can i say this bond actually in case of resonance hybrid in case of resonance hybrid it's not going to be a double bond exactly it's not going to be a single bond exactly it's going to lie between single and double bond right that's why i've shown it like this over here yes correct can i say it's basically a partial double bond right here it's not exactly the double bond it's not exactly the single bond it lies between single and double right so i'll be calling this as the partial double bond right here yes correct right priya you can show that as well you can show that as well you can show that as well yeah this is going to be what it's going to it's going to lead to the formation of partial double bonds right here and people as you all must be knowing as you all must be knowing as you all must be knowing if i talk about single bond if i talk about double bond and if i talk about partial double bond can you let me know the strengths of these pure single bond partial double bond and the actual double bond can you let me know about the strengths of these can i say bond strength of the actual double bond is maximum followed by the partial double bond followed by the actual single bond right wherever bond strength will be more can i say bond length is going to be less there right right right can i say bond length bond length is going to be can i say bond length is just going to follow the opposite order this is the order of bond length this is the order of what bond strength right here yes exactly exactly yeah right well people i've summarized all this i've summarized all this beautifully in one slide where all these points are written first thing this is the actual structure there's the true structure which explains all the properties of benzene right so i'll be calling this as either as the true structure or i'll be calling this as the resonance hybrid okay now people this is one of the proposed one of the probable structure of benzene okay there is probability that benzene sometimes could have formed this structure there is probability that benzene could have sometimes formed this structure so this benzene it's clearly not giving me the 100 information i mean this structure is not giving me clear information 100 information about benzene this is not giving me 100 information about benzene so i can say this is something this is the structure the hybrid which i'm saying this is the structure which i got by combining these two i'll assume something like this i'll assume this structure is giving me 50 information about benzene this structure is giving me 50 information about benzene if i'll combine the two informations i'll be getting something like this which is what we call as resonance hybrid yes right exactly exactly guys exactly yeah okay okay okay wonderful all right let's move on let's move on see few minutes back whatever i told you till now i've summarized it everything beautifully right here see that structure which contains the localized bonding but cannot explain all the properties of molecules are called as theoretical structures horizontal structures or canonical structures yes yes right see see guys i'm going to make it again see if you remember this is something which i call as a resonance hybrid right here yes this is something which i call a resonance hybrid right correct well guys it's one of the probable structure of the benzene this is one of the probable structure of benzene right and at the same time at the same time we have got one more probable structure of benzene right ah just a second this is one more probable structure of benzene this is what we call as hybrid right resonance hybrid correct people can i say in this structure i can easily locate where the pi electrons are yes i can clearly say in this structure pi electrons are between these two pi electrons are between these two carbon atoms pi electrons are here similarly in this structure i can easily locate the pi electrons can i see over here over here this structure this structure contains localized pi electrons this structure contains localized pi electrons so these localized structures these structures which contains the localized bonding but cannot explain all the properties of molecules these are what we call as theoretical structures resonating or canonical structures right right but this one it contains deluxe delocalized pi electrons right here okay you cannot exactly locate where the electrodes are no way you are not going to locate that yeah you cannot do that correct you cannot do that so i'll be calling this as hybrid and this will clearly give me the idea about i mean this is going to give me all the information about benzene this hybrid right yes yes correct remember guys the stability of hybrid the stability of resonance resonance resonance hybrid okay the the stability of this hybrid is always going to be greater than the stability of its canonical structures remember that at the same time okay why is that why is that because over here the pi electrons are delocalized they are under the influence of more than two nucleuses right right here i can say pi electrons are delocalized they are under the influence of more than two nucleuses right so there will be more force of attraction between them there'll be more force of attraction on those pi electrons right correct more of attraction less energy less energy more the stability can i say this hybrid this hybrid is definitely going to have less energy than the rest of its canonical structures yes can i can i say that yeah so less energy means more stability definitely the hybrid is going to be the maximum stable among among the among the rest of the canonical structures of india let's move on let's move on there's something which i told you none of the canonical structure is the true structure of benzene right because none of the canonical structure gives you the exact hundred percent data about the actual benzene right yes okay and people one more thing one more thing that structure which contains the delocalized bonding which contains the delocalized bonding but can explain all the properties of the molecule is something called as a resonance hybrid right the example is your this one this is the resonance hybrid of benzene correct yes absolutely i hope this is clear right okay let's move on see guys as i told you due to the delocalization of pi electrons what happens partial pi bonds are formed partial double bonds are formed yes and what about the what about the bond length of the single bond partial double bond and exact double bond this is something which i told you feminist back this is the order of the bond length and this is the order of the bond strength yes just opposite of the bonding this is something which i told you a few months back right i've summarized it everything right here you can take the screenshot off if you want or you'll be getting the pdf of it after once the session ends in the telegram yeah okay let's move on to something called as pi electrons well people pi electrons talking about pi electrons pi electrons are actually of two types one is called as a real pi electrons another one is called as differential pi electrons what are real pi electrons real pi electrons are there in your double bond as well as in triple bond those electron pairs those electron pairs which are there in double bond or triple bond those pi electron pairs which are there in double bond or triple bond those are what we call as real pi electrons okay and those electrons like your lone pair lone pair or the negative charge with the lone pair this is what we call as this what we call as differential pi electron okay so i classify pi electrons in two type two types one is called as a real pi real pi electrons real electrons are the ones which are there in the double bond those pi electrons which are there in the double bond and those pi electrons which are there in the triple bond i call these electrons as the real electrons and the lone pair is called as differential pi and the negative charge with a lone pair is also called as what it's also called as differential pi electron remember this right now okay what about the energy order of these real pi electrons and differential pi electrons what about their energy order remember remember the negative charge with a lone pair the negative charge with a lone pair it's going to have maximum energy followed by lone pair followed by the real pi electrons okay this is the energy order of these pi electrons right here remember this remember this correct correct that's great yesh1 that's great okay this is the actual energy order of these pi electrons first negative charge with a lone pair with maximum energy followed by a lone pair followed by the normal pi electrons real pi electrons yes okay exactly this differential pi this it looks like an emoji yeah okay let's move on guys let's move on now the point is what are the conditions for the resonance okay what all conditions must be satisfied so that we can explain the resonance yeah okay first first condition and the very important condition presence of parallel p orbitals with high energy electrons coplanar to each other right this is the first conditions there's the first condition for the resonance there should be parallel p orbitals between two adjacent carbon atoms there should be parallel if i'm talking about carbon right if i'm talking about benzene for example okay that should be what parallel p orbitals with high energy electrons which must be coplanar to each other what is what does that mean let's say this your p orbital let's say this is one more p orbital one more p orbital one more p orbital one more p orbital right one more one more right here okay all these p orbitals first of all must be parallel to each other right they should contain what high energy electrons they should contain high energy electrons they should contain high energy electrons right and they should be coplanar to each other this is the nucleus of one this is the nucleus this is the nucleus all these nucleus they should lie in the same plane like this yeah they should lie in the same plane like this correct now people now people how many possibilities are parallel overlapping our hair how many possibilities are parallel overlapping of air one possibility is this is the this can be the parallel overlapping this right this one this one this one this one correct this one i'll show right here this one i'll show right here this one i'll show right here this is first probability of parallel overlapping right this is first probability second probability would have been like this second probability would have been like this this should have been the overlap this should have been the overlap right similarly similarly this should have been the parallel overlap this should have been the parallel overlap similarly this should have been the parallel overlap this should have been the parallel overlap right can i say do the delocalization of these high energy electrons every every bond got the partial double bond yes it got the partial double bond character every bond got the partial double bond corrector right here due to the delocalization of these higher energy electrons yes i can say that yes so remember guys the first condition for resonance is there should be the presence of the parallel p orbitals with high energy electrons and they must be coplanar to each other point number one right now point number two point number two what is that going to be see this is something which i told you four minutes back right due to the delocalization of pi electrons during the delocalization of pi electrons the pair of electrons is subjected to more force of attraction see a localized electron pair lies between two nucleus a delocalized electron will be therein will be there will be shared by more than two atoms right more than two atoms that means that means that is subjugated to the attraction by more than two nucleuses right i can say that due to the attraction energy of that energy of the system decreases if the energy of the system decreases stability increases so can i say due to resonance due to resonance due to the delocalization of pi electrons the pi electron pair is subjected to more force of attraction okay due to which potential energy decreases stability increases that's why we say resonance increases the stability of the molecule yes let me know in the chat box where it's clear yes right exactly let's move on to one more point see guys resonance hybrid is always more stable because resonance is present in the hybrid not in the canonical structure yes delocalizes delocalization is present actually in the hybrid it's not present in the canonical form it's not see canonical from it cannot explain all the properties of the molecule right it cannot explain all the properties of the molecule resonance delocalization delocalization is present in the hybrid it's not present in the canonical form in the canonical form the pi electron pairs are localized yes those are localized i hope this point is also clear to you right resonance hybrid is always more stable because resonance is present in the hybrid not in the canonical form right point number next all the canonical forms should have almost same energy all the canonical forms should have this is one more condition for the resonance okay whatever canonical forms will be having they must have almost similar energy for example let me make you understand like this let's say i have got a hybrid or i'll call that as the true structure which i'm representing with t let's say this t is the true structure of the molecule right let's say it has got few canonical forms i'm proposing one of its structure is for example c1 i'm proposing one of its structure is c2 i'm proposing one obvious structure is c3 i can call these only the canonical forms only the canonical forms if they'll be having similar energies if they'll be having almost same energy right if some other guy comes he gives one more uh probable structure of this this t right here which is c4 but let's assume the energy of c4 is far far greater than the rest of these forms i won't be considering this as the canonical form i would be considering this as the canonical form yes i won't be considering this as the canonical form right here okay remember this okay now out of all the canonical forms that structure which is more stable that gives the better representation of the true molecule yes okay so what this statement is all about see we know out of all the out of all the resonating structures out of all the canonical forms there will be one of the canonical form that is going to be highest stable among all the canonical forms yes absolutely right can i say that canonical form which is going to be maximum stable among all the canonical forms can i say that would be more like your resonance hybrid can i say that'll be more like your true molecule right right yes i can say that i can say that yes so this is something like that which is written over here out of all the canonical forms that structure which is more stable gives the better representation of the true molecule right that that's that that canonical form which is which is more which is the most stable among all the canonical forms i will say that would be more like your true molecule right that'll be more like your true molecule okay remember this point as well now all the canonical forms all the canonical forms should have same should have same total sum of shared and unshared electron pairs what does that mean let's say i'm giving you two canonical forms right here these are the two canonical forms of some molecule aware of some molecule okay these are the two canonical forms of some molecule right here okay i will be only calling them as the canonical forms if they have got equal number of electron pairs if both the canonical forms will if if both the forms will have the equal electron pairs then only i will be calling them as the canonical forms okay how come i'll be checking that how come i'll be taking that have a look have a look guys however guys understand see this is first of all one bond that means one electron pair these are three bonds that means three electron pairs so one plus three this is one more electron pair right here so one plus three plus one that means over here in this in this form we have got total five electron pairs so here also should be five electron pairs then only i can call them as the canonical forms right yes have a look have a look this is a single bond that means one electron pair right double bond two electron pairs lone pair lone pair that means two electron pairs two to four one five so both the ones have got equal number of total electron pairs right here okay both the ones have got equal electron pairs right here okay so this is one most important condition guys here okay what is that all the canonical forms they must have same number of total electron pairs okay if the total electron pairs are not same in the two forms i won't be calling them as the canonical forms remember this as well right okay now now let's move on let's move on and let's talk about the types of conjugation let's see where in we can use the concept of resonance how how the delocalization of pi electrons actually takes place let's let's get to know that okay the first thing the first form by means of which i'll show you how the delocalization of pi electrons is taking place for that for that in order to make you understand that i need to show you the sigma sorry pi sigma vacant orbital conjugation okay whenever you see pi sigma and vector vector orbital whenever you see pi sigma and vacant orbital like this okay remember at that time there will be resonance there will be the delocalization of pi electron right and this delocalized of d this d localization of pi electron how come it takes place see guys let's say this atom a between let's say this is atom b right here and this is the empty orbital of that this is the empty of the orbital of atom b i'm just making you understand after this i'll be giving you the actual examples so right here can i say let's say this atom c over here okay can i say this is pi this is pi this is sigma and this empty orbital okay so what is going to happen conjugation which conjugation pi sigma empty orbital conjugation whenever you see pi sigma empty orbital conjugation remember there will be the d localization of pi electron and that delocalization of pi electron is something called as a resonance yes so what you'll be doing right here what you'll be doing right here just in order to make its other canonical forms in order to make its another other canonical forms what you'll be doing you'll be just let's say let's say let's say let's say you have got something like this just a second let's say there's a positive charge over it let's say there's a pause charge over here okay let's say there's a false charge over here okay now guys in order to make one more canonical form just remove one of the pi bond and keep this pi bond over here instead of this one okay wait i'll let me make it separately so that there won't be any sort of doubt to you okay what i'll be doing first of all i'll be removing one pi bond and this pi bond i'm going to take over here directly directly directly without doing any sort of disturbance it's going to be c now it's going to be single mode a it's going to be double bond b right here okay right now guys see over here there was a double bond there was a double bond okay right here we have we had the pi bond but now there is no pi bond so i'll be representing it by the positive charge i'll be showing the positive charge over here now guys this pi bond is right here in between over here there was positive charge now due to the formation of pi bond there'll be no positive charge right here this is one more hybrid this is one sorry this is one more canonical form of this structure this this one yes these are the two canonical forms these are the two canonical this was one canonical form this is one more canonical form right if i need to make the resonance hybrid how will i how will i be making that i'll be just combining these two right i'll be combining all the resonance structures as per this resonating structure a and c should have double bond as per this one they should have what they should have single bond so if i'll combine them that means a and c will be having partial double bond yes it'll be like this i'll be writing a over here everything see so it's going to be like this yeah correct as for this one a and b should have single bond as per this one a and b should have double bond so it should have partial double bond like this right it should have partial double bond like this correct let me write this b over here correct now as for this structure as for sorry as for this structure c should have positive charge as for this structure c should not have positive charge so i'm going to represent as delta positive slight positive yes similarly as per this structure b should have positive as per this b should not have so i'll be showing it plus delta over here this is going to be the resonance hybrid right this is going to be the resonance hybrid right yes akshata just take the video a little back it'll be automatically replay okay right now people let me give you the exact examples of how to understand this type of conjugation which is pi sigma back into orbital conjugation yeah right yes subhash i teach in v enthuse also here css i teach in vnts also okay the first example which i'm giving here right right now okay this is something which i'm giving to you okay this is one canonical structure of one molecule some molecule is there this is one of the canonical structure of it okay i need to make few more canonical structures of this one let me see how many canonical structures can get formed see first thing do i have a pi bond yes do i have a sigma bond yes right is there any vacant orbital with this carbon let's check that let's check that people i hope you remember what is the outermost uh configuration of carbon it is 2s22p2 yes it is 2s22p2 it's going to be like this it's going to be like this it's going to be like this the outermost configuration of carbon yes correct now due to excitation can we say one electron will be removed from here so that electron will be going right here yes that electron will be going right here it is arrow like this yeah that electron will be going right here right this is the excited state of the carbon this is the excited state of the carbon correct now right here carbon has got the positive charge that means one of the electron is removed from here okay so i'll say one p orbital is empty right here okay now people can i say the carbon can undergo sp2 hybridization this carbon right here is undergoing sp2 hybridization so how many atomic orbitals are intermixing right here three atomic orbitals are in the mixing which leads to the formation of three hybrid orbitals three sp2 hybrid orbitals right now people i'm going to arrange as per your bonding is concerned i'm going to arrange these three sp2 hybrid orbitals in such a way that there should be minimum repulsions among them yes let me make this structure like this let me make this structure again like this so that you get it properly so that you get it properly okay let me make a structure like this this is ch okay this was c which i'm talking about right here this is c who's whose configuration i'm talking about right here it underwent sp2 hybridization right it underwent us sp2 hybridization which led to the formation of three sp2 hybrid orbitals this is one this is one more and and and this is one more yes right this hybrid orbital will show direct overlap it will show direct overlap i don't know level this carbon right but people every hybrid orbital has got one electron right here every hybrid orbital has got one electron right here one hydrogen would have come from this side done the overlap one hydrogen would have come from this side done the overlap but with this carbon it has got one mtp orbital one pure pure will right here correct which is empty can i say i got pi sigma empty orbital right can i say it is the conjugation which i'm talking about right here this is the conjugation which i'm talking about right here this is pi sigma and empty will it show resonance right here yes definitely guys it will show resonance because it is the same conjugation which i'm talking about right here pi sigma vector whenever you see pi sigma vector orbital there will be the d localization of pi electrons yes now how this d like delocalization of pi electrons will take place right here understand what i'll say see you guys see first of all i got to know that conjugation is there that means that means that means that means what will happen the localization of pi electrons is going to take place okay now we'll the first thing which is going to happen right here just see just remove this double bond take this double bond right here so the structure which you'll be getting see if you are removing if you are removing double bond from here there'll be the positive charge on this this carbon right here there'll be composition on this carbon right here yes single bond now ch right i'm putting instead of this double bond i'm putting the double bond right here it's going to be double bond like this so it's going to be ch2 now it had the positive charge now during the formation of double bond that post charge would have would have gone yes this is the one more canonical structure of this okay so how many canonical structures right here two canonical structures right here if i need to make the if i need to make the resonance hybrid will i be making that yes i'll be combining the two right here double bond right hand single bond yes so it should be like this h2c it should be like this this should be ch yes single bond over here double bond so there'll be the partial double bond like this so it is ch2 correct now positive charge is on which atom so as for this structure positive charge should be on this atom as per this structure positive charge should be on this atom so i'm making it by delta this is the resonance hybrid which is definitely going to be stable in this as well as this yeah this is going to be more stable than its canonical forms i hope you know that yeah i hope you know that correct yes azam bro english channel i'm not supposed to talk in hindi people let me know in the chat box if it's clear till here let me know in the chat box if i scale to everyone so that i can move on and give you a few more things yeah yeah okay wonderful so this is one more canonical form and this is the true molecule hybrid which i'm calling yes this is the hybrid okay people there are a lot of exceptions in this as well okay you need to know those exceptions but before talking about the exceptions before talking about the exceptions i'll show you how to draw the resonating structures now now we will see first thing right here i've got a pi bond this is pi this is sigma and this carbon is sp2 hybridized it will be having a p orbital mtp orbital right which will be parallel to this one which will be parallel to this one right this will be parallel to this one so can i say this is pi sigma empty mtp orbital right so this is the conjugation it's going to show conjugation so first kind of canonical structure which i'll write here the second which i'm going to make just remove this double bond keep it right here so the structure is going to be like this just put the double bond it's going to be like this just a second it's going to be like this see i'll remove this double bond that'll be the positive charge on this carbon right so so right here it's going to be ch2 this positive charge would have got compensated by the presence of this double bond and how got nothing would do with these double bonds right here can i say in this structure again i got pi sigma positive charge pi sigma p orbital mtp orbital right can i say it's going to show conjugation this keep this double bond right here correct can i say one more structure is going to be like this it's going to be it's going to be like this just have a look guys just have a look it's first of all double bonded ch2 i didn't do anything with this yes correct now now now since i'm removing double from double from from this carbon so this carbon is going to get positive charge right and just put a double bond right here by putting a double bond this positive charge would have got nullified right here and one more double bond similarly like this yes can i see again in this there is pi sigma and positive charge conjugation yes so can i say one more resonating structure will be like this one more resonating structure will be like this let me make the resonating structure like this yeah see guys i'll remove the pi bond from this carbon so get the positive charge right i'll keep the pi bond right here yes due to the formation of this pi bond can i say this positive got nullified yes there is one more pi bond like this and this is as it is right right i can say that now people can i say i got one more conjugation pi sigma positive pi sigma positive means pi sigma mtp orbital right can i say it's again going to show conjugation absolutely so one more canonical form of this is going to be like this one more canonical form of this is going to be like this it's going to be have a look uh it's going to be like this yeah correct now there'll be a double bond right here on this ch2 there'll be a positive charge right double bond double bond double bond right here okay so how many canonical structures do we have people this was not the actual molecule this was the canonical this was one of the canonical structure and i made rest of four canonical structures right yes so there are total five canonical structures right here can i say first one and last one are these same or different is the same or different first one and last one first one this is what i was expecting answer from someone see first one and last one these are not same these are different but they have same energy same stability okay first one and last one it has got first and last they have got same energy same stability but they are different but they are different they are different right here this is the localized electron pair between these two carbons but right here right here there's a single bond right so this structure and this structure both the ones are different right right yes so remember first one and last one these are different structures but but see having same stabilities yes i hope this clear right exactly wonderful let me move on to fear more see this something which i told you there's something which i told you this something which you'll be getting in the form of pdf right okay if i need to make that resonating uh see if i need to make this what do we call this is the resonance hybrid how the resonance hybrid will look like what do you think how the resonance hybrid will look like yes aim the aims there is exception you'll be getting you will be getting that in some time let me finish it off first see if i need to make the resonance hybrid in the resonance hybrid so right here single bond double bond so right here you'll be getting the partial double bond character okay everywhere in the ring also over here partial double bond right there will be the positive charge over here there'll be the delta positive on this side right there'll be delta power on this side there'll be delta powers on this side so my resonance hybrid right here is going to be like this my resonance hybrid is going to be like this i'll make the circle right here okay and this is your ch2 correct this this is a dotted circle guys it's not a complete it's a daughter circle right and delta positive right here okay similarly delta positive right here correct similarly delta positive right here right similarly delta positive right here can i say this is going to be the resonating hybrid right here right great everyone yes let's move on let's move on to a few more examples see guys this is the resonance hybrid which which is formed right here yes like this okay well people let's talk about the third example right here will there be resonance in this one will there be resonance in this one yes i'm not talking about the stability of anyone stability i'll be talking differently wait for that wait for that i'm just showing you how to draw the structures first okay after that i'll let you know how to compare the stability of these okay so no need to hurry at all we have got time chill chill okay see you guys right here can i see this is this is first of all carbon which is sp2 hybridized sp2 hybridized means there will be one empty orbital which which i've shown you feminist back how come there will be the empty orbital right here mtp orbital right here yes which is going to be the perpendicular to the plane which contains these bonds yes perpendicular like this there'll be this is going to be this pen is going to be one lobe of that empty orbital right mtp orbital yes correct now people can i say right here i got pi sigma and mtp orbital right pi sigma empty p orbital is it the conjugation which we are talking about right here yes can i say right here what is going to happen can i say right here right here resonance will happen delocalization of pi electrons will take place so my first resonating structure which is going to be like this just just remove this pipe ground pi bond keep it here correct so the structure is going to be like this structure is going to be like this first of all i'm removing this pi bond from this carbon so this carbon gets a positive charge and since due to the formation of double bond this paused charge is nullified yes correct this is one of the resonant structures correct okay now people one more chance is there again i got pi sigma positive pi sigma positive means pi sigma mtp orbital can i say now one more structure is going to be like this i'm removing double bond from here it's going to be positive yes put the double bond right here right this positive charge would have got nullified yes this is one more structure this one more resonating structure correct now people do you think this is pi sigma and positive again will it show conjugation if it shows conjugation the pi bond will come here and positive will be come here then these two structures are going to be same then the structures are going to be same then right if i do one more uh transfer of these pi electrons right here if if i do one more this delocalization of pi electrons right here it's going to be same as the first one yes is it will form same as the first one correct so how many resonating structures do we have right here how many resonating structures do we have right here we've got three resonating structures yes three resonating strikes three canonical forms what is going to be the resonating hybrid all about can i say your resonating hybrid will be like this see every body is getting partial double one character yes every bond is getting partial double bond character there will be positive charge over here so this delta positive positive charge over here so this is again delta positive positive charge over here again delta also right here this is the resonance hybrid whole stability will be more than that of these three whose energy will be less than that of these three right and that one which is going to be the more stable which is going to be the most stable among all these canonical forms that one it will truly represent your the true molecule yes we can say that correct oh it's priya's birthday happy birthday priya happy birthday god bless you happy happy happy birthday harish just do one thing to take the video back it'll be replay bro take the video a little back it'll be automatically a replay okay harish what i'm saying just drag the video a little back it'll be automatically a replay bro [Music] okay let's move on to fay more so there's something which i've shown you right here this something and this is okay people one more important thing one more important thing due to resonance due to the delocalization what is happening to the charge can i say charge is getting distributed due to this resonance can i say charge is getting distributed right charge is getting distributed due to this delocalization of pi electrons right due to the distribution of charge what is going to happen to volume charge density can i say volume charge density will decrease and if you remember in the first session i have told you volume charge densities inversely stability if volume charge density of the molecule decreases its stability eventually increases yes right i can say that i can say that correct very very very simple this is yeah okay so i can say simply due to the distribution of charge volume charge volume charge and see what volume charge density decreases due to the resistance of charge volume charges decreases and if the volume charge density decreases i must say stability increases yes right exactly okay let me know guys will this molecule show resonance let me know in the chat box let me see how much concepts you got till now from this question i'll get to know did you get the actual concepts or not let me know let me know fast let me know fast let me know fast will this molecule show resonance i'm waiting for your answers guys what do you think will it show resonance so normally till now what i told you see this is pi this is pi yes this is sigma and this is sp2 hybridized carbon so it will have mtp orbital so this is pi sigma mt orbital yes so it should show it should show resonance so what do you think should be its structure its hybrid sorry its canonical form it should be like this put the double bond right here this should be ch2 this should be oh and right here this should be positive so as per you this should be this this should be something this should be it's one more canonical form but we will do you do do you remember do you remember do you remember positive charge on an electro negative element makes it highly unstable so this will be highly unstable its energy will be very very high correct so this is not going to be the resonating structure of this yes see first of all this is this is not some true structure this is the canonical form this is the canonic this is one of the canonical form right it's another canonical form was supposed to be this one but as i told you canonical form should have same should have almost same energies right but if this canonical form exists its energy very will be very very high but we know canonical forms that canonical form whose energy will be will be very very high or very very less as compared to the rest of its canonical forms that does not exist so it does not exist right right and for the molecule to show resonance there should be two canonical forms but right here only one so this molecule is not going to show any sort of resonance yes i can say that correct i can say that exactly happy birthday bro if it's your birthday happy birthday bro happy birthday god bless you okay few more few more guys see this is one more interesting thing right here this one more interesting thing right here which i want you guys to take a note of carefully see the atom having positive charge that atom having positive charge the atom having positive charge should have vacant orbitals then only it shows the then only it shows the sigma pi weakened orbital conjugation which leads to the which leads to the happening of resonance yes right right now guys understand what is going to happen over here normally if a normal person will think he'll think like this this is pi this is sigma and over here positive so pi sigma positive charge it will definitely show resonance right he'll make the structure and so on but people right here understand right here understand is the octet of nitrogen complete it is making three bonds with three hydrogens right like this and one bond right here is the octave nitrogen complete absolutely octet of nitrogen is complete yes if the octet of nitrogen is complete can i say it's in its outer motion there will be eight electrons right its outer motion will be like this 2s2 2s2 2b6 right because its octet is complete now 2s22p6 right is there any vacant p orbital is there any vacant orbital in nitrogen there is no vacant orbital right and for the resonance to happen it should be pi sigma and it should have vacant orbital writer if it is not having any vacant orbital can i say this one is not going to show any sort of resonance right here yes yes absolutely guys absolutely now let me know in the second one see this is absolutely pi this is sigma and this is positive normally i should think like this this is pi this is sigma this is positive so it should show resonance as per the conjugation which i've shown you right here a few minutes back but what is going to happen right here see oxygen it has formed two bonds with hydrogen right there is one lone pair on oxygen there is one lone pair of function and this is one more bond so people two to four to six to eight can i say octave oxygen is complete if octet of oxygen is complete its outermost configuration should be again 2s2 2p6 is there any is there any empty orbital right here no empty orbital right here yes correct so no resonance at all right because for the resonance there should be pi sigma and empty orbital correct correct correct yeah clear to everyone let me know in the chat box but it's clear so that i can give a few more examples let me know in the chat box yeah okay because we know i've told you feminists back i've told you a few minutes back since we are talking about we are talking about pi sigma and empty orbital conjugation empty orbital conjugation right we are talking about this but right right here no doubt you have pi then you have sigma but right here there is no empty orbital pi sigma right here there is no empty orbital so no conjugation at all okay right let's talk about few more important things which will will the molecule show resonance will the molecules show resonance what about the first one will the first one show any sort of resonance what do you think will the first one show any sort of resonance yes or no yeah is it going to show resonance what do you think the first one i'm asking see guys understand like this understand like this which kind of conjugation we are talking about right here uh pi sigma mt orbital right that conjugation we are talking about right here you can check it out you can check it out have a look see guys first of all p is forming three bonds with r correct and right here one more bond correct so is the octet of p complete octet of p is complete absolutely octet of p is complete octopus complete understand what i should say if the octet of p is complete this one exception guys okay except this is not the exception this is a concept basically the opt of p is complete first of all we know octop is complete right but guys but if the octave p is complete its configuration should be 3s2 3p6 correct this should be configuration of this phosphorus after completing this octet right since there will be 3d also with zero electrons right can i say there are empty d orbitals right so can i say i got the conjugation as pi sigma mt orbital this is going to show resonance yes let me know in the chat box if it's clear let me know fast yes got it wonderful okay let me know in the second one let me know in the second one will the second one show resonance what do you think will the second one show resonance people this is organic this is organic you need to be very careful with the things with small small things you need to be careful with will the second one show resonance see guys just check the octave sulfur first sulfur is forming three bonds with r and one bond right here so octane of sulfur is completing completed after completing the octet can i say configuration of sulfur is going to be 3s2 3p6 yes but there'll be 3d also with zero electrons in sulfur right so empty 3d orbitals are there can i say i got the conjugation as pi sigma empty empty orbital can i say it is going to show resonance absolutely yeah yes yes what about the last one what about this one guys will it show resonance what do you think will the last one show resonance what do you think will the last one show resonance well i can see majority of people are saying no why is that c nitrogen's octet is complete right three bonds with hydrogen and one bond with carbon so its octet is complete after completing the nitrogen the nitrogen is going to have to have the outermost convection as 2s2 2p6 after completing the octet yes right so it's not going to have any orbital any empty orbital right here no doubt this was sick this was pi this was sigma it should have empty orbital but it's not having any empty orbital so it's not going to show any sort of hybrid sorry any sort of uh con this resonance right yes exactly guys all of you are perfectly correct wonderful right right wonderful guys okay two more examples three more examples then we'll end the today's discussion then see guys this resonance effect is not over yet i've just started the resonance in the today's session i made you understand the actual concept of what this resonance is all about okay i didn't i didn't do the questions based on this concept in the next session which i'll be taking in the next session we are going to do the part second of this resonance effect which is going to be very very very important okay right okay let me know among these which which all will show resonance what do you think what do you think let me know first what about the first one is the first one going to show any sort of resonance writer so i'll be doing that soon just wait for that will the first one show resonance absolutely guys first one will show arizona see pi this is sigma this is going to have empty d orbital right it's going to a phosphorus will have mtd orbital right so the first one is going to show resonance what about the second one what about the second one what about the second one will the second one show resonance people use your brain use your chemical bonding concepts chemical bondings is plays a vital role right here in the goc look here guys look here look here look at understand understand what i'll say understand what i'll say which kind of hybridization this boron is showing right here it is forming three sigma bonds one two and three so it will be sp2 hybridized yes what is the configuration of boron isn't it 2s2 2p1 outermost configuration i'm asking yeah 2s2 like this two electrons in s and in p there will be one electron like this ground state if i'll ask you about the excited state one electron will go to the p so excited state is going to be like this one electron right here one electron over here is this the excited state right this is the excited state now which hybridization is not sp2 can i see these two orbitals will undergo mixing hybridization and there'll be one p orbital left over here so there will be the vacuum p orbital guys there will be the v p orbital so over here you'll be having the vacant p orbital so this is pi this is sigma this is vacant p orbital so hybridization is going to happen right here yes and if i ask you what is going to be the canonical structure of this one see this is one canonical structure it's another canonical structure let's let's make that let's make that shift this double bond right you're going to shift this double bond you are shifting this double bond from this carbon so this carbon is going to get positive charge so it's going to ch2 positive right here correct this this is single bond this is ch this is your double bond now this is bh2 right here correct yes can i say that can i say that and people i hope you remember there will be since there was a single bond this was neutral now there will be negative charge on this boron yes right right absolutely perfectly correct perfectly correct perfectly great so are these two going to be the resonating structures yeah absolutely yes priya since right here it didn't have any charge right it was a single bond now it is giving a double bond so definitely it will be having negative charge if it had the positive charge then due to the double bond that positive charge would have got neutralized that would have been no negative charge right here correct but it was neutral first it was neutral first so due to the formation of double bond negative charge got placed right here on bora yes correct okay what about the last one let me know let me know the last one guys i just want to see i just really want to see i just i just want to see the last one by means of which i'll get to know whether you got the concepts or not let me know about the last one will it show resonance will it show resonance yes absolutely this will show resonance and what is going to be your homework guys you are going to make all its canonical forms all its canonical forms you are going to make all its canonical forms okay take a picture of that and do send me on the in the comment box or in my personal telegram personal instagram wherever you find me do send me that okay i'll be personally checking it one by one right okay this was the first type of conjugation which is your pi sigma and empty orbital conjugation this was the first type of conjugation empty orbital conjugation i mean pi sigma empty orbital conjugation wherein resonance can happen okay this is not this not done yet there are other conjugations as well which i'll be letting you know in the next session okay not now right uh well people with this i think our today's discussion is over yes so for the ones who joined us late who joined us late let me tell you we have come up with a neat 2021 crash course for you and this you'll be getting trained by the teachers of your choice and after that at the same time your whole syllabus will be getting completed in your physics chemistry as well as biology right the test series mocktus everything is included right here in this test series i mean in this crash course and at the same time there will be some separate sessions regarding their tricks and tips by means of which you can solve the questions in lesser time yes and people at the same time it's going to be a two-way learning interactive platform wherein you can ask your doubts any time your master teachers yes and in order to get enrolled in this if you want me to train you personally in your chemistry for the upcoming neet 2021 just click on the without after clicking on the vedanta just click on the neet crash course after clicking on the need crash course use the coupon code as wscc if you want me to personally train you for the upcoming neet 2021 and apart from that you'll be getting the discount of 20 writer after using this wscc coupon code right here there is one more way by means of which you can get enrolled in this okay you just need to click on the link which is there in the description box of the video click on that link okay use the coupon code get added right right okay all right well talking about 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the channel at the same time so that everyone gets benefited out of these sessions right i hope everything is clear till here yes i hope everything is clear till here i'll see you guys again tomorrow at the same time and tomorrow we are going to continue with this resonance effect right here okay till then you guys take care bye bye god bless you all love you all take care bye guys