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Understanding Arithmetic Sequences and Formulas
Feb 20, 2025
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Lecture on Arithmetic Sequences
Overview
Focus
: Finding a formula for the nth term of an arithmetic sequence.
Formula
: $a_n = a_1 + (n - 1) \cdot d$
$a_1$ = first term
$n$ = term number
$d$ = common difference
Justification of the Formula
Example Sequence
: 3, 8, 13, 18, 23, 28
This is an arithmetic sequence with a common difference ($d$) of 5.
Terms
:
$a_1 = 3$
$a_2 = 3 + 5$
$a_3 = 3 + 2 \times 5$
$a_4 = 3 + 3 \times 5$
Pattern Recognition
: Each term after the first can be calculated by adding the common difference multiplied by one less than the term number.
General Formula
: For $a_n$, use $a_1 + (n - 1) \cdot d$
Example Problems
Problem 1: Find the 10th Term
Sequence
: 3, 8, 13, 18, 23, 28, 33...
Steps
:
Recognize $a_1 = 3$ and $d = 5$.
Calculate: $a_{10} = 3 + (10 - 1) \cdot 5$
Result: $a_{10} = 48$
Problem 2: Find the 202nd Term
Steps
:
Use $a_{202} = 3 + (202 - 1) \cdot 5$
Calculate: $3 + 201 \cdot 5 = 1008$
Problem 3: Find First Term and Common Difference
Given
: $a_8 = 25$, $a_{14} = 43$
System of Equations
:
$a_1 + 7d = 25$
$a_1 + 13d = 43$
Solving System
:
Subtract equations to eliminate $a_1$.
Solve for $d$: $6d = 18 \Rightarrow d = 3$
Substitute back to find $a_1$: $a_1 = 4$
Conclusion
Key Takeaways
: Understanding the formula for the nth term and applying it to solve various problems.
Challenges
: Systems of equations can determine unknowns in arithmetic sequences.
Further Questions
: Encouragement to ask questions for clarification.
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