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Boolean Expression Minimization
Jul 23, 2024
Boolean Expression Minimization
Introduction
Presenter: Jayashree Gupta
Topic: Minimizing a Boolean expression
Example Boolean Expression
Expression: (\overline{A}B + A + A\overline{B})
Consists of 3 terms: (\overline{A}B), (A), (A\overline{B})
Goal: Simplify or minimize the expression
Methods of Minimization
Using the Laws of Boolean Algebra
Using Karnaugh Map (K-map)
Frequently Used Boolean Algebra Laws
Identity Laws
:
(A + \overline{A} = 1)
(A \cdot \overline{A} = 0)
Annulment Laws
:
(1 + A = 1)
(0 + A = A)
(1 \cdot A = A)
(0 \cdot A = 0)
De Morgan’s Laws
:
((A + B)^{'} = \overline{A} \cdot \overline{B})
((A \cdot B)^' = \overline{A} + \overline{B})
Distributive Laws
:
(A \cdot (B + C) = (A \cdot B) + (A \cdot C))
(A + (B \cdot C) = (A + B) \cdot (A + C))
Redundant Literal Rule
:
Example: (A + \overline{A}B = A + B)
Minimization Techniques
Example 1
Expression
: (BC + \overline{B}C)
Simplification:
Take common (C)
(C(A + B + \overline{B}) = C(A + 1) = A + C)
Example 2
Expression
: ((\overline{A}B + AB))
Steps:
Apply distributive law and redundant literal rule
Simplified to (A + B)
Example 3
Expression
: (A + AB\overline{C} + \overline{A}B)
Simplification:
Combine terms where possible
Apply laws systematically
Simplified to (A + B)
Advanced Examples
Example 4
Expression
: (AB + AC\overline{B}C \cdot AB)
Steps:
Apply De Morgan's law and distributive properties
Simplification may include multiple layers of applying laws
Final minimized expression Various complex steps involved
Example 5
Expression
: ((AB + ABC) + A(BC + A\overline{B}C))
Strategies:
Apply redundant literal rule, De Morgan's law
Identify and cancel out contradictory terms
Conclusion
Simplification of Boolean expressions involves the systematic application of the Boolean algebra laws.
Common laws include Identity laws, De Morgan’s laws, Distributive laws, and the Redundant Literal Rule.
Practicing multiple examples helps in mastering the minimization process.
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