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Maximization Problem Solving with Simplex
Aug 30, 2024
Lecture Notes: Solving Maximization Problems Using Simplex Tableau
Introduction
Objective:
Solve a maximization problem using the simplex tableau method.
Initial Setup:
Convert the problem into standard form.
Add slack variables to convert inequalities to equalities.
Ensure all variables are non-negative.
Simplex Method Overview
Variables:
Two decision variables, additional slack variables.
Basic Solution:
Set two variables to zero and solve for the others.
Example: X2 and S1 set to 0 results in X1 = 8 and S2 = -12 (not feasible due to non-negativity).
Basic Feasible Solution:
Set X1 and X2 to 0 to make S1 = 16 and S2 = 12.
Feasible as all variables are non-negative.
Constructing the Simplex Tableau
Components:
Cj Row:
Objective coefficient row.
A Matrix:
Coefficients of variables in constraints.
B Column:
Right-side quantities (initially for basic variables).
Basic Variables:
Slack variables S1 and S2, considered unit columns.
Basis column indicates which are basic variables.
Zj Calculation:
Multiply Cb values with corresponding column values, sum the results.
Represents unit contribution to the objective function.
Net Evaluation Row (Cj - Zj)
Indicates net change in objective function if a variable enters the solution.
Selection:
Choose non-basic variable with highest positive value in Cj - Zj row as new basic variable.
Key column corresponds to this variable.
Iterations
Initial Basis:
Basic feasible solution with X1, X2 = 0; S1 = 16; S2 = 12.
Pivot Process:
Calculate ratios of B column values to pivot column values.
Select row with minimum ratio as pivot row.
Perform row operations to create unit column for new basic variable.
Objective Function Value:
Calculated from Zj row.
Conclusion
Optimal Solution:
Achieved when all Cj - Zj values are non-positive.
Final solution values: X1 = 2, X2 = 3, Objective Function = 32.
Graphical Representation:
Basic solutions correspond to feasible region's extreme points.
Steps Recap:
Convert to standard form with slack variables.
Develop initial tableau.
Select non-basic variable with largest Cj - Zj.
Calculate pivot row and perform row operations.
Repeat until optimal solution is achieved.
Summary
Successfully solved the maximization problem through systematic iterations and tableau adjustments.
End of Lecture
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