Jul 10, 2024
Basic Concept:
log_b(a) = c means b^c = alog_b(a) asks: "b to what power equals a?"Examples:
log_2(4) = 2 because 2^2 = 4log_2(8) = 3 because 2^3 = 8log_3(9) = 2 because 3^2 = 9log_4(16) = 2 because 4^2 = 16log_3(27) = 3 because 3^3 = 27log_2(32) = 5 because 2^5 = 32Evaluation with Common Bases:
log(100)), assume base 10log(10) = 1 because 10^1 = 10log(100) = 2 because 10^2 = 100log(1000) = 3 because 10^3 = 1000log(1,000,000) = 6Negative Logs:
log(0.1) = -1 because 10^-1 = 0.1log(0.01) = -2 because 10^-2 = 0.01log(0.00001) = -5Formula: log_a(b) = log_c(b) / log_c(a)
e (natural logarithm)Examples:
log_2(8) = 3 translates to log(8) / log(2) = 3log_5(x - 1) to natural log: ln(x - 1) / ln(5)Product Rule: log(a) + log(b) = log(a*b)
Quotient Rule: log(a) - log(b) = log(a/b)
Power Rule: log(a^c) = c*log(a)
Examples - Condensing Logs:
log(x) + log(y) - log(z) = log(xy/z)2log(x) + 3log(y) - log(z) becomes log(x^2) + log(y^3) - log(z) = log(x^2 * y^3 / z)*log(R^2 * S^5 / Z^6) = 2log(R) + 5log(S) - 6log(Z)log(โ(x^2 * y) / z^4) expands to log(x^2 * y^1/2 / z^4) and further to 2log(x) + 0.5log(y) - 4log(z)*Special Values:
Ln(1) = 0Ln(e) = 1Ln(e^5) = 5*Ln(e) = 5Simplification Examples: (Using cancellation rules)
e^(ln(7)) simplifies to 75^(log_5(y^8)) simplifies to y^8log_3(6) - log_3(2) = log_3(3) = 1*Basic Conversion: Convert log equations into exponent form to solve
log_x(27) = 3 becomes x^3 = 27 รท solve x = 3log_2(y) = 5 becomes 2^5 = y รท solve y = 32Example: Solve log_2(x+5) = 3
2^3 = x + 58 = x + 5x = 3Combining Logs: Apply log rules first
log_2(x-3) + log_2(x-1) = 3 becomes log_2((x-3)(x-1)) = 32^3 = (x-3)(x-1) and solve the quadratic equationSteps:
x to find vertical asymptote and key points.Example: Graph y = log_2(x-3) + 1
x-3=0 รท x=3x-3=1, x-3=2 รท Points: (4,1) and (5,2)Domain & Range:
+โ-โ to +โ