Jul 10, 2024
Basic Concept:
log_b(a) = c
means b^c = a
log_b(a)
asks: "b
to what power equals a
?"Examples:
log_2(4) = 2
because 2^2 = 4
log_2(8) = 3
because 2^3 = 8
log_3(9) = 2
because 3^2 = 9
log_4(16) = 2
because 4^2 = 16
log_3(27) = 3
because 3^3 = 27
log_2(32) = 5
because 2^5 = 32
Evaluation with Common Bases:
log(100)
), assume base 10log(10) = 1
because 10^1 = 10
log(100) = 2
because 10^2 = 100
log(1000) = 3
because 10^3 = 1000
log(1,000,000) = 6
Negative Logs:
log(0.1) = -1
because 10^-1 = 0.1
log(0.01) = -2
because 10^-2 = 0.01
log(0.00001) = -5
Formula: log_a(b) = log_c(b) / log_c(a)
e
(natural logarithm)Examples:
log_2(8) = 3
translates to log(8) / log(2) = 3
log_5(x - 1)
to natural log: ln(x - 1) / ln(5)
Product Rule: log(a) + log(b) = log(a*b)
Quotient Rule: log(a) - log(b) = log(a/b)
Power Rule: log(a^c) = c*log(a)
Examples - Condensing Logs:
log(x) + log(y) - log(z) = log(xy/z)
2log(x) + 3log(y) - log(z)
becomes log(x^2) + log(y^3) - log(z) = log(x^2 * y^3 / z)
log(R^2 * S^5 / Z^6) = 2log(R) + 5log(S) - 6log(Z)
log(√(x^2 * y) / z^4)
expands to log(x^2 * y^1/2 / z^4)
and further to 2log(x) + 0.5log(y) - 4log(z)
Special Values:
Ln(1) = 0
Ln(e) = 1
Ln(e^5) = 5*Ln(e) = 5
Simplification Examples: (Using cancellation rules)
e^(ln(7))
simplifies to 7
5^(log_5(y^8))
simplifies to y^8
log_3(6) - log_3(2) = log_3(3) = 1
Basic Conversion: Convert log equations into exponent form to solve
log_x(27) = 3
becomes x^3 = 27
÷ solve x = 3
log_2(y) = 5
becomes 2^5 = y
÷ solve y = 32
Example: Solve log_2(x+5) = 3
2^3 = x + 5
8 = x + 5
x = 3
Combining Logs: Apply log rules first
log_2(x-3) + log_2(x-1) = 3
becomes log_2((x-3)(x-1)) = 3
2^3 = (x-3)(x-1)
and solve the quadratic equationSteps:
x
to find vertical asymptote and key points.Example: Graph y = log_2(x-3) + 1
x-3=0
÷ x=3
x-3=1
, x-3=2
÷ Points: (4,1)
and (5,2)
Domain & Range:
+∞
-∞ to +∞