College Physics 1: Lecture 1 - Mathematics Review
Overview
Lecture covers basic math skills required for College Physics, focusing on exponents, fractions, and solving equations. Emphasis is placed on algebra-based physics as opposed to calculus-based physics.
Key Points
- Audience: Intended for students in the class, but made publicly available.
- Math Skills: Fundamental for succeeding in physics; ensures focus is on physics concepts rather than struggling with math.
Exponents
Basics
- Superscript notation:
x
raised to the n
th power.
4^3
= 4 * 4 * 4.
- Fractional exponents: Example,
x^(1/2)
is the square root of x
.
- *Rules for Exponents:
- Product Rule:
x^m * x^n = x^(m+n)
.
- Example:
3^3 * 3^2 = 3^(3+2) = 3^5 = 243
.
- Quotient Rule:
x^m / x^n = x^(m-n)
.
- Example:
3^3 / 3^2 = 3^(3-2) = 3^1 = 3
.
- Power Rule:
(x^m)^n = x^(mn)
.
- Example:
2^2^3 = 2^6 = 64
.
- Distributive Rule:
(xy)^m = x^m * y^m
.
- Example:
(3*2)^4 = 3^4 * 2^4 = 81 * 16 = 1296
.
- Negative Exponent Rule:
x^-n = 1/x^n
.
- Example:
2^-1 = 1/2 = 0.5
.
- Roots Rule:
x^(1/n) = n-root of x
.
- Example:
4^(1/2) = √4 = 2
.
Fractions
- Multiplication: Multiply straight across.
- Example:
a/b * c/d = ac/bd
.
- Division: Multiply by the reciprocal.
- Example:
a/b / c/d = a/b * d/c = ad/bc
.
- Addition/Subtraction: Find common denominators.
- Example:
a/b ± c/d = (ad ± bc)/bd
.
Solving Equations
- Basic Principle: Perform the same operation on both sides of the equation.
- *Examples:
y = x/5
→ x = 5y
(multiply by 5)
ax - y = 2y
→ x = 3y/a
(move terms, divide by a)
a(x + b) = c
→ x = c/a - b
(divide by a, move terms)
y/x + a = b
→ x = y/(b - a)
(move terms, multiply by x)
√x + 3 - y = 0
→ x = y^2 - 3
(move terms, square both sides)
a(x - y) = b(x + y)
→ x = y(a + b)/(a - b)
(distribute, factor, solve)
Quadratic Equations
- Standard Form:
ax^2 + bx + c = 0
.
- Quadratic Formula:
x = (-b ± √(b^2 - 4ac)) / 2a
- *Steps:
- Rearrange into standard form.
- Identify coefficients a, b, c.
- Substitute into quadratic formula.
- Solve for x.
- Example:
2x^2 = 3x + 5
→ 2x^2 - 3x - 5 = 0
→ x = (-(-3) ± √((-3)^2 - 4(2)(-5))) / 2(2)
= x = 2.5
or x = -1
.
Conclusion
- Importance of learning to rearrange equations before plugging in numbers.
- Use of quadratic formula for solving specific types of equations.
- Next lecture will continue with further math review, introducing relationships, geometric concepts, and trigonometric functions.