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Key Problems in Coordinate Geometry
Feb 11, 2025,
Lecture on Problems in Coordinate Geometry
Key Concepts
Vertical and horizontal lines
Area of a right triangle
Midpoint formula
Distance formula
Equation of a circle
Tangent line
Intercepts and graphing
Distance in 3D
Area of shaded regions
Equilateral triangle
Median of a triangle
Perpendicular bisector
Altitude of a triangle
Detailed Notes
Finding the Coordinates of Point B
Vertical Line
: x-coordinates are the same.
Horizontal Line
: y-coordinates are the same.
Example: B shares x-coordinate with A (1), and y-coordinate with C (2).
Area of Right Triangle
Formula: (\text{Area} = \frac{1}{2} \times \text{base} \times \text{height})
Base
: Distance between B and C is 4 units.
Height
: Distance between A and B is 3 units.
Area
: (\frac{1}{2} \times 4 \times 3 = 6) square units.
Center of a Circle
Endpoints of diameter
: (1, 2) and (7, 10).
Midpoint Formula
: (\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right))
Center: (4, 6)
Area and Circumference of Circle
Radius
: Use distance formula between center and endpoint.
Distance: 5
Area
: (\pi r^2 = 25\pi)
Circumference
: (2\pi r = 10\pi)
Standard Equation of Circle
Equation: ((x - h)^2 + (y - k)^2 = r^2)
Center: (4, 6), Radius: 5
Equation: ((x - 4)^2 + (y - 6)^2 = 25)
Equation of Tangent Line
Slope
: Perpendicular slope is negative reciprocal.
Example, given points A (3, 2) and B (5, 8):
Slope of AB: 3
Slope of Tangent: -1/3
Equation: ( y = -\frac{1}{3}x + \frac{29}{3})
Area of Region Bounded by Axes
Equation: (4x + y = 8)
Intercepts
:
x-intercept: (2, 0)
y-intercept: (0, 8)
Area
: (\frac{1}{2} \times 2 \times 8 = 8) square units
Distance in 3D
Points: Origin (0, 0, 0) and P (3, 4, 5)
Distance Formula
: (\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2})
Distance: 5√2 ≈ 7.07
Distance from Point to Line
Line: (3x + 4y - 7 = 0)
Point: (5, 3)
Distance Formula
: (\frac{|ax_1 + by_1 + c|}{\sqrt{a^2 + b^2}})
Distance: 4 units
Area of a Shaded Region
Circle with x-intercept 4,0 and y-intercept 0,4
Area of Square
: Side length = 8
Area of Circle
: (\pi (4)^2 = 16\pi)
Shaded Area
: 64 - 16\pi
Equilateral Triangle
Side length
: 8
Area
: (16\sqrt{3}) square units
Median of a Triangle
Points: A (1, 2), B (5, 10), C (7, 4)
Midpoint of AC
: (4, 3)
Equation of Median
: y = 7x - 25
Perpendicular Bisector
Bisector Equation
: Passes through midpoint, slope is negative reciprocal
Altitude of a Triangle
Passes through vertex, perpendicular to base
Equation
: Shares same slope with perpendicular bisector, different point
Altitude Equation
: y = -3x + 25
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