Lecture Notes: Acid-Base Titrations
Introduction
- Focus on acid-base titrations.
- Discussion on titration curves and calculating pH at various points in the process.
Problem 1: Determining Concentration of H2SO4
- Given: 28.9 mL of H2SO4 titrated with 38.4 mL of 0.25 M NaOH.
- Objective: Find concentration of H2SO4.
- Methods:
- Stoichiometry:
- Balance chemical equation: H2SO4 + 2 NaOH โ Na2SO4 + 2 H2O.
- Convert volumes to liters.
- Use molarity to find moles of NaOH.
- Convert moles of NaOH to moles of H2SO4 using molar ratio.
- Determine concentration by dividing moles of H2SO4 by original volume in liters.
- Result: [H2SO4] = 0.1661 M.
- Equation Method (M1V1 = M2V2):
- Modify equation considering the 1:2 molar ratio.
- Balance through number of protons and hydroxide ions.
- Result: Same as stoichiometry method: [H2SO4] = 0.1661 M.
Problem 2: Volume of NaOH for Equivalence Point
- Given: 23.6 mL of 0.46 M monoprotic acid titrated with 0.19 M NaOH.
- Objective: Find volume of NaOH at equivalence point.
- Method:
- Use M1V1 = M2V2, considering 1:1 molar ratio for monoprotic acid.
- Result: Volume needed is 57.14 mL.
Titration Curves
Strong Acid-Strong Base Titration
- Initial low pH with strong acid, rises dramatically, equivalence point at pH 7.
- Inverse for strong base-strong acid: starts high, decreases, same equivalence point.
Weak Acid-Strong Base Titration
- Starts at higher pH than strong acid titration.
- Equivalence point is above pH 7.
- At half equivalence point, pH = pKa.
Weak Base-Strong Acid Titration
- Starts relatively high, but not as high as strong base.
- Equivalence point pH is less than 7.
- At half equivalence, concentrations of acid and base are equal.
Important Equations and Concepts
- Henderson-Hasselbalch Equation:
pH = pKa + log([Base]/[Acid])
- Buffer Region: Resist changes in pH, ph = pKa at half equivalence point.
- Calculating pH at Equivalence Point:
- Strong acid-strong base: pH = 7.
- Weak acid-strong base: pH > 7.
- Weak base-strong acid: pH < 7.
Example Problem: Strong Acid-Strong Base Titration
- Given: 50 mL of 1 M HCl titrated with 0.50 M NaOH.
- Objective: Calculate pH at various stages.
- Stages:
- Calculate equivalence volume: 100 mL.
- Initial pH of HCl solution: 0 (from concentration of H+).
- pH after adding 30 mL NaOH: Use moles of HCl, NaOH.
- pH at equivalence: 7.
- pH after 125 mL NaOH: Calculate excess OH-, find pOH, then pH = 12.85.
Next Topic
- Discussion will continue with weak acid and strong base titration examples.
These notes provide a comprehensive overview of acid-base titrations, focusing on the calculations and concepts relevant to determining pH and titration curves.