Lecture Notes on Photon Wavelength and Frequency
Key Concepts
- Speed of Light (c):
- Constant value: (3 \times 10^8) meters/second.
- Wavelength (λ):
- Frequency (ν):
Important Equations
- Wavelength and Frequency Relation:
- (c = \lambda \times \nu)
- Rearranged to find wavelength: (\lambda = \frac{c}{\nu})
- Rearranged to find frequency: (\nu = \frac{c}{\lambda})
- Energy and Frequency Relation (Planck's Equation):
- (E = h \times \nu)
- (h = 6.626 \times 10^{-34}) joules (\cdot) seconds.
Problem Solving
Problem 1: Calculate Wavelength Given Frequency
- Given: Frequency = (2.5 \times 10^{12}) Hz.
- Solution:
- Use equation: (\lambda = \frac{c}{\nu}).
- Substitute values: (\lambda = \frac{3 \times 10^8}{2.5 \times 10^{12}}).
- Result: (\lambda = 1.2 \times 10^{-4}) meters.
- Convert to micrometers: (1.2 \times 10^{2}) micrometers (120 micrometers).
Problem 2: Calculate Frequency Given Wavelength
- Given: Wavelength = (1.5 \times 10^{-8}) meters.
- Solution:
- Use equation: (\nu = \frac{c}{\lambda}).
- Substitute values: (\nu = \frac{3 \times 10^8}{1.5 \times 10^{-8}}).
- Result: (\nu = 2 \times 10^{16}) Hz.
Problem 3: Frequency with Wavelength in Nanometers
- Given: Wavelength = 350 nm.
- Solution:
- Convert nm to meters: (350 \times 10^{-9}) meters.
- Use equation: (\nu = \frac{c}{\lambda}).
- Result: (\nu = 8.57 \times 10^{14}) Hz.
Problem 4: Wavelength Given Frequency in Megahertz
- Given: Frequency = 95 MHz.
- Solution:
- Convert MHz to Hz: (95 \times 10^{6}) Hz.
- Use equation: (\lambda = \frac{c}{\nu}).
- Result: (\lambda = 3.16) meters.
Conceptual Understanding
- Inverse Relationship:
- Wavelength and frequency are inversely related:
- As frequency increases, wavelength decreases.
- As wavelength increases, frequency decreases.
Additional Problems
Energy to Frequency and Wavelength
-
Problem: Determine frequency of a photon with energy (E = 3.5 \times 10^{-18}) joules.
- Solution:
- Use equation: (\nu = \frac{E}{h}).
- Result: (\nu = 5.28 \times 10^{15}) Hz.
-
Problem: Determine wavelength from energy (E = 4.3 \times 10^{-19}) joules.
- Solution:
- Calculate frequency: (\nu = \frac{E}{h}).
- Calculate wavelength: (\lambda = \frac{c}{\nu}).
- Convert result to nanometers: 462 nm.
These notes cover calculations involving photon wavelength and frequency, including conversions between units and understanding the inverse relationship between frequency and wavelength.