Jul 18, 2024
X = X₀ * e^(-kt)
C = C₀ * e^(-kt)
C = 20 * e^(-0.57*4)
C = 2 µg/ml
t₀.₅ = 0.693 / k
Vd = X₀ / C₀
C = 20 * e^(-0.57t)
).C₀ = 20 µg/ml, k = 0.57 hr⁻¹
C = C₀ * e^(-kt)
C₀ = 20 µg/ml, k = 0.57 hr⁻¹, t = 4 hrs
C₄ = 20 * e^(-0.57*4) = 2 µg/ml
t₀.₅ = 0.693 / 0.57 = 1.22 hr
C₀ = 20 µg/ml = 20 mg/L
Vd = 500 mg / 20 mg/L = 25 L
t = 2.303/k * log(C₀/C)
t = 2.303/0.57 * log(20/1) = 5.26 hrs
dX/dt = Q - kX
C = Css * (1 - e^(-kt))
Css = Q / Cl
Q = Css * Cl
Q = Css * Cl
Cl = k * Vd = (0.693/12) * 20 = 1.16 mg/hr
Loading Dose (X₀) = Css * Vd
X₀ = 0.1 µg/ml * 20 L = 2 mg