Jul 18, 2024
X = X₀ * e^(-kt)C = C₀ * e^(-kt)C = 20 * e^(-0.57*4)C = 2 µg/mlt₀.₅ = 0.693 / kVd = X₀ / C₀C = 20 * e^(-0.57t)).C₀ = 20 µg/ml, k = 0.57 hr⁻¹C = C₀ * e^(-kt)C₀ = 20 µg/ml, k = 0.57 hr⁻¹, t = 4 hrsC₄ = 20 * e^(-0.57*4) = 2 µg/mlt₀.₅ = 0.693 / 0.57 = 1.22 hrC₀ = 20 µg/ml = 20 mg/LVd = 500 mg / 20 mg/L = 25 Lt = 2.303/k * log(C₀/C)t = 2.303/0.57 * log(20/1) = 5.26 hrsdX/dt = Q - kX
C = Css * (1 - e^(-kt))Css = Q / ClQ = Css * ClQ = Css * ClCl = k * Vd = (0.693/12) * 20 = 1.16 mg/hrLoading Dose (X₀) = Css * VdX₀ = 0.1 µg/ml * 20 L = 2 mg*