Jul 12, 2024
log base (a) of (b) asks a to what power equals blogā4 = 2 because 2² = 4logā8 = 3 because 2³ = 8logā9 = 2 because 3² = 92^5 = 32)10log10 = 1log100 = 2 (10² = 100)log1000 = 3, log1000000 = 6 (count zeros)0logā16: 4² = 16 so it's 2logā
125: 5³ = 125 so it's 3logāā(1/4) involves negative exponents, hence logāā(1/4) = -½4 raised by fractions without leading to confusionlogāb = log_b/logālog(A) + log(B) = log(A*B)log(A) - log(B) = log(A/B)log(A^k) = k*log(A)log(X) + log(Y) - log(Z) = log((X*Y)/Z)ln(1) = 0, ln(e) = 1e^(ln(a)) = alog base 3 of 27 = 3 leads to x = 30, 1, base)y valuesx and y, solve for yy=x