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Understanding Molarity and Its Applications
Sep 25, 2024
Molarity Podcast Lecture Notes
Introduction to Molarity
Concept
: Molarity is a unit used to quantify the concentration of a solution.
Visual Aid
: Solutions with varying molarities can be visually identified (more concentrated solutions appear darker).
Definition
: Molarity = moles of solute ÷ liters of solution.
Units: Moles per liter (M).
Importance of Molarity
The most common concentration unit in chemistry.
Essential for solving chemistry problems involving solutions.
Example Calculations
Example 1: Sodium Chloride Solution
Problem
: Calculate the molarity of a 2-liter solution containing 0.4 moles of NaCl.
Equation
:
Molarity = Moles of solute / Liters of solution
M = 0.400 moles / 2.00 liters = 0.200 M
Notation
: Use capital M for molar.
Significant Figures
: Maintain the least number of significant figures from values used (3 sig figs).
Example 2: Potassium Nitrate Solution
Problem
: Find the molarity of 56.7 grams of KNO3 dissolved in 3.50 liters of solution.
Conversion
:
Convert grams to moles (KNO3 = 101.11 g/mol).
Moles = 56.7 g / 101.11 g/mol = 0.561 moles
Calculation
: M = 0.561 moles / 3.50 liters = 0.160 M
Significant Figures
: 3 significant figures.
Example 3: Finding Grams from Molarity
Problem
: How many grams of KNO3 are needed for 1.50 liters of 0.5 M solution?
Steps
:
Solve for moles: 0.5 M = x moles / 1.50 liters → x = 0.750 moles
Convert moles to grams: 0.750 moles × 101.11 g/mol = 75.8 grams
Example 4: Sodium Hydroxide Solution
Problem
: Determine molarity of a solution with 450 mL volume containing 12.45 grams of NaOH.
Conversions
:
Convert grams to moles: NaOH (~40.00 g/mol)
Moles = 12.45 g / 40.00 g/mol = 0.3113 moles
Convert mL to liters: 450 mL = 0.4500 liters
Calculation
: M = 0.3113 moles / 0.4500 liters = 0.6918 M
Significant Figures
: 4 significant figures maintained.
Conclusion
The lecture covered various examples of how to calculate molarity.
Encouraged to practice with the packet provided and ask questions in class.
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