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Chemistry Lecture: Moles, Particles, and Avogadro's Number

Jul 1, 2024

Chemistry Lecture on Moles, Particles, and Avogadro's Number

Key Concepts

Variables and Formulas

  • n (small): Number of moles
  • N (capital): Number of atoms, particles, or molecules
  • N<sub>A</sub>: Avogadro's Number
    • 6.02 x 10<sup>23</sup> (provided in exams)

Important Formula

  • N = n x N<sub>A</sub>
    • N is the number of particles
    • n is the number of moles
    • N<sub>A</sub> is Avogadro's Number

Methods Using the Formula

  1. Triangular Representation: Helps to use the formula in various ways
    • N at the top
    • n and N<sub>A</sub> at the bottom

Working Examples

Example 1

Determine the number of moles if you have 12.04 x 10<sup>23</sup> particles

  • Given:
    • Number of particles, N = 12.04 x 10<sup>23</sup>
    • N<sub>A</sub> = 6.02 x 10<sup>23</sup>
  • Applying the formula:
    • n = N / N<sub>A</sub>
    • n = (12.04 x 10<sup>23</sup>) / (6.02 x 10<sup>23</sup>)
    • Result: n = 2 moles

Example 2

Determine the number of molecules in 3 moles of H<sub>2</sub>O

  • Given:
    • Number of moles, n = 3
    • N<sub>A</sub> = 6.02 x 10<sup>23</sup>
  • Applying the formula:
    • N = n x N<sub>A</sub>
    • N = 3 x 6.02 x 10<sup>23</sup>
    • Result: N = 1.806 x 10<sup>24</sup> molecules

Complex Calculations with Different Data

Example with Grams

Determine the number of molecules in 36 grams of H<sub>2</sub>O

  • Step 1: Calculate moles

    • n = given mass / molar mass
    • Given mass = 36g, Molar mass of H<sub>2</sub>O = 18 g/mol
    • n = 36g / 18 g/mol = 2 moles
  • Step 2: Calculate number of molecules using moles

    • N = n x N<sub>A</sub>
    • N = 2 x 6.02 x 10<sup>23</sup>
    • Result: N = 1.204 x 10<sup>24 molecules

Practical Application with Compounds

Example: Water Molecules

  • 10 H<sub>2</sub>O molecules have:
    • 10 oxygen atoms
    • 20 hydrogen atoms
    • 30 atoms altogether

Example: Carbon Dioxide (CO<sub>2</sub>) Molecules

  • 5 CO<sub>2</sub> molecules have:
    • 5 carbon atoms
    • 10 oxygen atoms
    • 15 atoms altogether

Advanced Mole Calculations

Example with CaCO<sub>3</sub>

  • Given: 2 moles of CaCO<sub>3</sub>
  1. Number of CaCO<sub>3</sub> molecules
  • N = n x N<sub>A</sub>
    • N = 2 x 6.02 x 10<sup>23</sup>
    • Result: N = 1.204 x 10<sup>24 molecules
  1. Number of atoms in CaCO<sub>3</sub>
  • Ca atoms: 1 atom per molecule
    • 1.204 x 10<sup>24
    • C atoms: 1 atom per molecule
      • 1.204 x 10<sup>24
    • O atoms: 3 atoms per molecule
      • 3 x 1.204 x 10<sup>24</sup> = 3.612 x 10<sup>24

Summary

  • The ability to rearrange and understand chemistry formulas is crucial.
  • Utilizing Avogadro's Number and understanding moles are foundational skills in chemistry.