Sep 15, 2024
f'(x)y'dy/dxdy/dx means the rate of change of y with respect to x.f'(x) = lim(h→0) ((f(x+h) - f(x)) / h)f(x) = x² + 4x + 4 using first principles.
f'(x) = 2x + 4f(x) = x^n, the derivative is f'(x) = n*x^(n-1).
y = x² results in y' = 2x.y = x² + 4x + 4y' = 2x + 4*y = kx, the derivative is dy/dx = k.
y = 4x, derivative is 4.y = x³ + 3x² + 5
y' = 3x² + 6xy = 1/2 x^(1/2)
y' = 1/(2√x)x into f'(x) to find gradient at that x.y = x² + x - 6, find gradient at x = 2.
5.y = 3x⁴ - 2x^(-1/2) + 3x + 1, find y'.
y' = 12x³ + x^(-3/2) + 3