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Understanding Area Under Curves with Riemann Sums
Dec 14, 2024
Lecture on Finding Area Under a Curve with Riemann Sums
Key Concepts
Riemann Sums:
Method to approximate the area under a curve.
Definite Integral:
Exact calculation of the area under a curve from point (a) to (b).
Endpoints:
Used in Riemann sums to calculate the area with left, right, and midpoint methods.
Function Example
Consider (f(x) = x^2 + 1).
Parabola
starting at 1 and opens upward.
Calculate area from (x = 0) to (x = 2).
Definite Integral Calculation
Integrate (f(x) = x^2 + 1) to find the antiderivative.
Evaluate from 0 to 2:
(\int_0^2 (x^2 + 1) , dx = \left[\frac{x^3}{3} + x\right]
0^2 = \frac{8}{3} + 2 = \frac{14}{3} \approx 4.67)
Riemann Sums
Delta x (width of rectangles):
(\Delta x = \frac{b-a}{n})
Left Endpoint Approximation:
Use points (0, 0.5, 1, 1.5).
Result: 3.75 (under-approximation).
Right Endpoint Approximation:
Use points (0.5, 1, 1.5, 2).
Result: 5.75 (over-approximation).
Midpoint Rule:
Use points (0.25, 0.75, 1.25, 1.75).
Result: 4.625 (most accurate of three).
Observations
Increasing (n) (number of rectangles) increases approximation accuracy.
Averaging left and right Riemann sums gives a closer approximation.
Visual Representations
Graphing Rectangles:
Left endpoint: rectangles below the curve.
Right endpoint: rectangles above the curve.
Midpoint: balances areas above and below the curve.
Example with Different Function
Function:
(f(x) = x^3), ([0, 4])
Calculate definite integral: (\int_0^4 x^3 , dx).
Area using left: 36, and right: 100.
Midpoint provides closer estimate.
Decreasing Functions
Example:
(f(x) = \frac{1}{x}), ([1, 2])
Actual area: (\approx 0.6931).
Left endpoint: over-approximation.
Right endpoint: under-approximation.
Sigma Notation and Limits
Defining Definite Integral with Limit:
[ \text{Area} = \lim_{n \to \infty} \sum_{i=1}^{n} f(x_i) \Delta x ]
(\Delta x = \frac{b-a}{n})
Right Endpoint Formula:
(x_i = a + i\Delta x)
Left Endpoint Formula:
(x_i = a + (i-1)\Delta x)
Equations
Sum of constant (c): (cn)
Sum of (i): (\frac{n(n+1)}{2})
Sum of (i^2): (\frac{n(n+1)(2n+1)}{6})
Sum of (i^3): (\left(\frac{n(n+1)}{2}\right)^2)
Final Example
Function:
(f(x) = 5x - 2)
Interval: ([1, 4])
Definite integral: (\int_1^4 (5x - 2) , dx) gives (\frac{63}{2}).
Conclusion
Using different Riemann sum methods and exact integrals provides a comprehensive understanding of approximating area under curves.
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