Transcript for:
Understanding the Photoelectric Effect Principles

What do we mean by photoelectric  effect? Observe this animation.   In this animation, light strikes a metal surface  and electrons are ejected from the surface. So,   the photoelectric effect phenomenon is the  emission of electrons from the surface of   a body (generally metal) when exposed  to suitable electromagnetic radiation.   In 1888, Hallwachs set up the fundamental  experiment that verified the photoelectric   effect experimentally. Here we have an  electroscope with one movable leaf and a   perfectly cleaned zinc plate. The zinc plate is  fixed to the metal cap of the electroscope. The   system is charged negatively, so the leaf rises to  the left under the effect of the repulsive force.   When the ultraviolet radiation emitted by the  ultraviolet lamp reaches the zinc plate, the leaf   falls immediately. But, why? This is because  the electroscope loses its negative charge.   When the negatively charged zinc plate is  exposed to ultraviolet radiation electrons are   liberated from its surface, so the electroscope  discharges and the leaf falls down. This is the   photoelectric effect phenomenon. The emitted  electrons are called photoelectrons because   they are ejected from the surface of the metal  due to the energy carried by the incident light. The electroscope is charged negatively again. The  ultraviolet lamp is replaced by a red laser. When   the charged zinc plate is illuminated by a red  light, the leaf does not fall whatever the sign   of the charge of the zinc plate. Then, electrons  are not liberated from its surface. Why does the   photoelectric effect not work for red light?  Let's see in the simulation in the next slide.   Focus please, this is important. Would any light  incident on any pure metal liberate electrons from   the surface of the metal or are there specific  conditions? In this PHET simulation, a sodium   plate is illuminated by red light of wavelength  (λ = 750 nanometers). We noticed that there is no   emission of electrons from the surface of sodium  whatever the exposure time to the incident light.   Let's increase the intensity or the power of the  incident light. Also, we still have no emission   of electrons. Now, let's decrease the wavelength  of the incident light to (λ = 563 nanometers).   We still have no emission of  electrons whatever the power   and the exposure time to the incident light.  Let's decrease λ to a value of 540 nanometers. Also, no electrons are liberated from the  surface of sodium. If λ equals 539 nanometers, now, we notice that electrons are  liberated from the surface of sodium.   So, photoelectric effect takes place. If we  decrease the wavelength to another value of   309 nanometers, electrons are still liberated from  the surface of sodium. So, we can conclude that if   the wavelength of an incident light is less than  or equals 539 nanometers, electrons are liberated   from the surface of sodium. And, if λ is greater  than 539 nanometers, the incident light is not   capable of liberating any electron whatever the  power and the exposure time to the incident light.   (539 nanometers) is called the threshold  wavelength of sodium. Now, let's determine   that threshold wavelength of copper. For, ( λ =  665 nanometers), electrons are not liberated from   the surface of copper whatever the power or the  exposure time to the incident light. For ( λ = 264 nanometers), electrons are not liberated from  the surface of copper. For ( λ = 263 nanometers), we notice that now electrons  are liberated from the surface   of copper. Therefore. (263 nanometers) is  the threshold wavelength of copper. Then,   if λ is less than 263 nanometers, electrons  are liberated from the surface of copper. As we have seen in the previous slide, in order  to extract electrons from the surface of a pure   metal, then the wavelength of the incident  radiation must be less than or equal to a   certain threshold wavelength. Each pure metal  has its own value of the threshold wavelength.   In this table, we have the threshold  wavelength for some pure metals.   Now, if the wavelength of the incident radiation  is greater than the threshold wavelength,   there is no emission of photoelectrons  from the surface of the metal whatever   the radiation power and the exposure time to the  incident radiation. So, what is the definition of   the threshold wavelength of a certain metal?  It is the maximum wavelength of the incident   radiation which is capable of extracting  electrons from the surface of this metal.   Now, let's study another characteristic of  a pure metal, called threshold frequency and   denoted by (𝛎o). We know that the wavelength of an  electromagnetic radiation in a certain medium is   given by the speed of this radiation in the same  medium over its frequency. Then, the threshold   wavelength λ𝐨 of a pure metal equals (c over the  threshold frequency 𝛎o of the same metal, where   c is the speed of light in vacuum and it equals  [ 3 × (10)^8 m/s ]. We have seen in the previous   slide that in order to extract electrons, the  wavelength (𝛌) of the incident radiation should   be less than or equal to the threshold wavelength  (𝛌o) of the pure metal. But, 𝛌 equals ( c /   𝛎 ), where (𝛎) is the frequency of the incident  radiation. Compare these two fractions. Since,   they have the same numerator, then to extract  electrons from the surface of a pure metal the   frequency (𝛎) of the incident radiation should be  greater than or equal to the threshold frequency   of the pure metal. Then, the threshold frequency  of a pure metal is the minimum frequency of the   incident radiation which is capable of extracting  electrons from the surface of this metal. What is the conclusion of this study? In  photoelectric effect, extraction of electrons   from the surface of the pure metal depends only  on the nature of the metal and on the frequency   or the wavelength of the incident electromagnetic  radiation. If the frequency of the incident   radiation is less than the threshold the frequency  of the metal or if the wavelength of the incident   radiation is greater than the threshold wavelength  of this metal, then the incident electromagnetic   radiation is not capable of liberating any  electron whatever the radiation power and the   exposure time to the incident radiation. In the  end, don't miss the rest of the material about the   photoelectric effect explained in the next videos.  You can find the links in the description. [Music]