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Understanding Key Gas Laws and Equations

Feb 11, 2025

Lecture Notes on Gas Laws

Introduction

  • Focus on key formulas and equations for gas laws in chemistry.
  • Importance of understanding units and conversions.

Pressure

  • Definition: Pressure = Force / Area.
  • Units:
    • Standard unit in physics: Pascal (Pa)
      • 1 Pascal = 1 Newton/m²
    • Chemistry unit: Atmosphere (atm)
    • Conversions:
      • 1 atm = 101,300 Pascals (101.3 kPa)
      • 1 atm = 760 mmHg = 14.7 psi

Ideal Gas Law

  • Formula: PV = nRT
    • R (gas constant) = 0.08206 L atm/mol K or 8.3145 J/mol K
    • Units:
      • Pressure in atm or Pa
      • Volume in Liters or m³
      • Temperature in Kelvin
    • Temperature Conversion: Kelvin = Celsius + 273.15

Combined Gas Law

  • Equation: ( \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} )
  • Pressure and volume units must match; temperature in Kelvin.

Boyle's Law

  • Equation: ( P_1V_1 = P_2V_2 )
  • Relationship: Inverse relationship between pressure and volume.

Charles' Law

  • Equation: ( \frac{V_1}{T_1} = \frac{V_2}{T_2} )
  • Relationship: Direct relationship between volume and temperature.

Gay-Lussac's Law

  • Equation: ( \frac{P_1}{T_1} = \frac{P_2}{T_2} )
  • Relationship: Direct relationship between pressure and temperature.

Avogadro's Law

  • Equation: ( \frac{V_1}{n_1} = \frac{V_2}{n_2} )
  • Relationship: Direct relationship between volume and moles.

Molar Mass and Density

  • Molar Mass: Replace n with m/MW in PV = nRT to get pressure, volume, and molar mass relation.
  • Density: ( D = \frac{PM}{RT} )
    • Can calculate density or identify gas using molar mass and density.

Standard Temperature and Pressure (STP)

  • Conditions:
    • Temperature: 273 K (0°C)
    • Pressure: 1 atm
    • 1 mole gas = 22.4 L at STP

Dalton's Law of Partial Pressures

  • Concept: Total pressure = Sum of individual partial pressures.
  • Equation: Partial pressure = Mole fraction x Total pressure.

Kinetic Theory

  • Average Kinetic Energy: Proportional to temperature.
  • Use R = 8.3145 J/mol K.

Root Mean Square Velocity

  • Equation: ( v_{rms} = \sqrt{\frac{3RT}{MW}} )
    • MW in kg/mol, R = 8.3145 J/mol K._

Graham's Law of Effusion

  • Equation: ( \frac{R_2}{R_1} = \sqrt{\frac{MW_1}{MW_2}} )
  • Relationship: Rate of effusion inversely related to square root of molar mass.
    • Inverse relationship between time and rate.

Conclusion

  • Reference to practice problems available for deeper understanding.