charge in the point of the what will be the electric field so at uh let me say that is positive charge right so [Music] in the distance so the distance is nothing but r minus a square and ethernet dipole movement electric dipole dipole moment negative so which is equal to minus i hope you will understand earlier all right everything is a vector one right which is equal to e plus plus e minus total upper positive abdomen okay q by r minus a whole square and the p cap the unit vector shows the direction apron plus either minus so e electric field on negative charge then minus r plus a unit cap the p cap unit vector just the direction all the time right other couple either [Applause] [Applause] is minus r square plus r square minus a square plus a square so the remaining term is 2 a r 2 a r apparent number four a r out of the major b cap [Applause] minus a square [Music] i will neglect india if r is much much greater than a r1 i will neglect this point up in the terminal and neglect it so i have r square and ing over square which is nothing but r to the power 4 yeah r to the power 4 n over uppo k q in the four e r sorry p vector which is equal to 2 a q p cap then the direction lambda negative charge to minus uh positive charge about 2 years on the dipole distance cubed into the charge suppose yellow to your point in the point this becomes negative yeah negative y axis remember with a smile