May 22, 2025
Example Problem: Two resistors in series (4Ω and 6Ω) with a 30V battery.
R_total = R1 + R2 = 10Ω.V = IR to find current: I = V/R = 30V/10Ω = 3A.V = IR = 3A * 6Ω = 18VV = IR = 3A * 4Ω = 12VPower Calculations:
P = VI = 30V * 3A = 90W.P = I²R = 3² * 6Ω = 54WP = V²/R = 12²/4Ω = 36WR_total = 10Ω.I = 60V/10Ω = 6A.30V18V12VExample Problem: Two resistors (6Ω and 8Ω) with a 24V battery.
I = V/R = 24V/6Ω = 4AI = V/R = 24V/8Ω = 3AI_total = 4A + 3A = 7A.Resistance and Power in Parallel Circuits:
R_equivalent = 3.43Ω using 1/R_total = 1/R1 + 1/R2 formula.P = VI = 24V * 7A = 168WP = I²R = 9 * 6Ω = 54WP = V²/R = 144/4Ω = 36W