Understanding Series and Parallel Circuits

May 22, 2025

Series and Parallel Circuits

Introduction

  • Discusses series and parallel circuits with batteries and resistors.
  • Resistors can be viewed as light bulbs.
  • Series circuit: one path for current.
  • Parallel circuit: multiple paths for current.

Circuit Characteristics

  • Series Circuit:
    • One path for current.
    • Increases total resistance as more resistors are added.
    • Decreases current flow, making light bulbs dimmer.
  • Parallel Circuit:
    • Multiple paths for current.
    • Voltage remains constant across all paths.
    • Total resistance decreases as more resistors are added, increasing overall current.

Current Flow

  • Conventional current flows from positive to negative.
  • Electrons flow from negative to positive.

Series Circuit Calculations

  1. Example Problem: Two resistors in series (4Ω and 6Ω) with a 30V battery.

    • Total resistance: R_total = R1 + R2 = 10Ω.
    • Use Ohm’s law: V = IR to find current: I = V/R = 30V/10Ω = 3A.
    • Voltage drop:
      • 6Ω: V = IR = 3A * 6Ω = 18V
      • 4Ω: V = IR = 3A * 4Ω = 12V
    • Kirchhoff's Voltage Law: Sum of voltage drops equals battery voltage.
  2. Power Calculations:

    • Power of battery: P = VI = 30V * 3A = 90W.
    • Resistors' power:
      • 6Ω: P = I²R = 3² * 6Ω = 54W
      • 4Ω: P = V²/R = 12²/4Ω = 36W
    • Total power absorbed equals power delivered.

Concepts of Power

  • Power is work divided by time.
  • 1 Watt = 1 Joule/second.
  • Faster energy transfer means higher power.

Example Problem: Series Circuit with Three Resistors

  • Resistors: 5Ω, 3Ω, 2Ω; Battery: 60V.
  • Total resistance: R_total = 10Ω.
  • Current: I = 60V/10Ω = 6A.
  • Voltage drops:
    • 5Ω: 30V
    • 3Ω: 18V
    • 2Ω: 12V
  • Power calculations align with Kirchhoff's law.

Parallel Circuit Calculations

  1. Example Problem: Two resistors (6Ω and 8Ω) with a 24V battery.

    • Voltage across resistors is the same.
    • Current through resistors:
      • 6Ω: I = V/R = 24V/6Ω = 4A
      • 8Ω: I = V/R = 24V/8Ω = 3A
    • Total current: I_total = 4A + 3A = 7A.
    • Kirchhoff's Current Law: Current into a junction equals current out.
  2. Resistance and Power in Parallel Circuits:

    • Total resistance: R_equivalent = 3.43Ω using 1/R_total = 1/R1 + 1/R2 formula.
    • Power:
      • Battery: P = VI = 24V * 7A = 168W
      • Resistors:
        • 6Ω: P = I²R = 9 * 6Ω = 54W
        • 8Ω: P = V²/R = 144/4Ω = 36W

Conclusion

  • Series Circuit: Single path for current; total resistance increases with more resistors.
  • Parallel Circuit: Multiple paths; voltage across resistors is the same.
  • Power conservation: Power delivered equals total power absorbed by resistors.