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Common Base Configuration of BJT
Jul 29, 2024
Common Base Configuration of BJT
Introduction
Common application of BJT: Used as an amplifier.
Configurations of BJT: common emitter, common base, common collector.
Common Base Configuration
In this configuration,
Base terminal
is common between input and output.
Input: between
Base and Emitter
terminals.
Output: between
Collector and Base
terminals.
Device operates in
active region
:
Base-emitter junction:
Forward biased
Collector-base junction:
Reverse biased
NPN and PNP Transistors
NPN Transistor
:
Emitter current goes away from the transistor.
Base and collector currents enter into the transistor.
PNP Transistor
:
Emitter current enters into the transistor.
Base and collector currents go away from the transistor.
Emitter current:
Equal to summation of base and collector currents.
Characteristics of Common Base Configuration
Characterized by
Input and Output Characteristics.
Input characteristics show relationship between
Vbe
(input voltage) and
Ie
(input current).
Similar to forward characteristics of PN diode.
As
Vcb
increases, the curve shifts left and
Ie
increases due to decreasing depletion width.
Input Impedance
Input impedance (Zin):
Determined from slope of input characteristics.
Z_in = (\frac{\Delta V_{be}}{\Delta I_e})
Very low resistance, typically in the
ohm range
.
Output Characteristics
Output characteristics define relationship between
Ic
(output current) and
Vcb
(output voltage).
Three regions of operation:
Active Region
:
Collector current (Ic) remains constant irrespective of
Vcb
change.
(I_c = \alpha \cdot I_e)
Saturation Region
:
Collector current reduces as
Vcb
becomes negative.
Both junctions forward biased.
Cut-off Region
:
Emitter current is zero; collector current remains almost zero.
Only due to minority charge carriers, i.e.,
Icbo
(reverse saturation current).
Amplification in Common Base Configuration
Simplified analysis without DC biasing voltages.
Example:
Input impedance
(R_in) =
10 ohm
Input voltage
(V_i) =
5 mV
Input current
(I_e) = (\frac{5 mV}{10 ohm} = 0.5 mA)
Assuming (\alpha = 1), (I_c \approx I_e)
Output impedance
(R_o) = Typical in
hundreds of kΩ
Load resistor
(R_L) =
1 kΩ
Output voltage (V_o):
(V_o = I_o \times R_L = 0.5 mA \times 1 kΩ = 0.5 V)
Voltage gain
= (\frac{V_o}{V_i} = \frac{0.5 V}{5 mV} = 100)
Current Gain
Current gain (Ic/Ie) is
less than 1
in this configuration.
Voltage gain typically varies from
50 to 300
.
Conclusion
Common base configuration allows for voltage gain.
Next topic:
Common-Emitter Configuration
.
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