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Lec 2: 1.3 Constant Acceleration

Sep 12, 2025

Overview

This lecture demonstrates how to solve a physics problem involving a sandbag dropped from a rising balloon, focusing on equations of motion with constant acceleration.

Problem Setup

  • A balloon ascends vertically at 6 m/s.
  • A sandbag is dropped from the balloon with an initial upward velocity of 6 m/s at ( t = 0 ).
  • The sandbag hits the ground after 8 seconds.
  • Required: speed of the sandbag at impact and altitude of the balloon at that instant.

Key Equations and Steps

  • Use constant acceleration motion equations to solve for positions and velocity.
  • Define upwards as the positive direction.
  • Acceleration due to gravity is ( g = -9.81 ) m/s² (downwards).

Calculating Sandbag Position (when it hits ground)

  • Use ( s = s_0 + v_0 t + \frac{1}{2} a t^2 ).
  • ( s_0 = 0 ), ( v_0 = 6 ) m/s, ( a = -9.81 ) m/s², ( t = 8 ) s.
  • Substitute: ( s = 0 + 6(8) + 0.5(-9.81)(8^2) ).
  • Result: ( s_{\text{bag}} = -265.9 ) m (downward, indicating it is below the release point).

Calculating Balloon Position (after 8 s)

  • Balloon moves at constant velocity, so ( a = 0 ).
  • ( s = s_0 + v_0 t ), ( s_0 = 0 ), ( v_0 = 6 ) m/s, ( t = 8 ) s.
  • ( s_{\text{balloon}} = 6 \times 8 = 48 ) m (above release point).

Finding Balloon Altitude (above ground)

  • Altitude is the vertical distance between the balloon and ground at ( t = 8 ) s.
  • ( \text{Altitude} = s_{\text{balloon}} - s_{\text{bag}} = 48 - (-265.9) = 313.9 \approx 314 ) m.

Speed of Sandbag at Impact

  • Use ( v = v_0 + a t ).
  • ( v_0 = 6 ) m/s, ( a = -9.81 ) m/s², ( t = 8 ) s.
  • ( v = 6 + (-9.81)(8) = -72.5 ) m/s (downwards).
  • Speed (magnitude) is ( 72.5 ) m/s.

Key Terms & Definitions

  • Constant Acceleration — Motion with unchanging acceleration, such as gravity near Earth's surface.
  • Initial Velocity (( v_0 )) — The sandbag's velocity at the moment of release.
  • Altitude — The vertical distance from the ground to the balloon.
  • g (Gravity) — Acceleration due to Earth's gravity, approximately ( 9.81 ) m/s² downwards.

Action Items / Next Steps

  • Practice applying equations of motion to problems with constant acceleration.
  • Review the signs (positive/negative) for direction in kinematics problems.