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Understanding Logarithms and Their Properties

Aug 22, 2024

Evaluation of Logs

Basic Definitions

  • Logarithm: Log base b of a number x is the exponent to which b must be raised to get x.
  • Notation: log_b(x) = y means b^y = x.

Examples of Logarithms

  • log_2(16):

    • 2^4 = 16
    • Result: log_2(16) = 4
  • log_3(27):

    • 3^3 = 27
    • Result: log_3(27) = 3
  • log_5(25):

    • 5^2 = 25
    • Result: log_5(25) = 2
  • log_4(1):

    • Always equals 0
    • Result: log_4(1) = 0
  • log_7(7):

    • 7^1 = 7
    • Result: log_7(7) = 1

Logarithm of Powers of 10

  • log(1000) (base 10 assumed):
    • 10^3 = 1000
    • Result: log(1000) = 3
  • log(100):
    • 10^2 = 100
    • Result: log(100) = 2
  • log(0.0001):
    • 10^-4 = 0.0001
    • Result: log(0.0001) = -4

Patterns in Logarithms

  • log(1) = 0
  • log(10) = 1
  • log(100) = 2
  • log(1000) = 3
    • Pattern: For each additional zero, the logarithm increases by 1.
  • For negative decimals:
    • log(0.1) = -1
    • log(0.01) = -2
    • log(0.001) = -3
    • log(0.0001) = -4

More Logarithmic Identities

  • log_b(x) = y implies b^y = x
  • Example: 7 log_7(38) = 38
  • Example: 5 log_5(14) = 14
  • Example: 8 log_8(y) = y

Additional Examples

  • log_3(9):
    • 3^2 = 9
    • Result: log_3(9) = 2
  • log_3(1/9):
    • 3^-2 = 1/9
    • Result: log_3(1/9) = -2
  • log_9(3):
    • Result: log_9(3) = 1/2
  • log_9(1/3):
    • Result: log_9(1/3) = -1/2

Practice Problems

  1. 2^x = 8:

    • x = 3
  2. 3^(-2) = 1/9:

    • Result: Log value = -2
  3. Square root of 25:

    • 25^(1/2) = 5
    • Result: 5
  4. Square root of 64:

    • 64^(1/2) = 8
    • Result: 8
  5. 4th root of 16:

    • 16^(1/4) = 2
    • Result: 2
  6. 4th root of 81:

    • 81^(1/4) = 3
    • Result: 3

Conclusion

  • Logarithms are an essential concept in mathematics that relate exponentiation and multiplication. Understanding their properties and how to evaluate them is crucial.