Problems on Trains - Aptitude Questions and Answers

Importance of Learning Aptitude Questions on Trains

• Purpose: Enhance problem-solving skills for interviews, competitive exams, and entrance tests such as CAT, GATE, GRE, MAT, and various bank and railway exams.
• Confidence: Helps in approaching exams and interviews with full confidence.

Resources for Solving Train Problems

• Platform: IndiaBIX offers a variety of aptitude questions with solutions.
• Types of Questions: Multiple-choice, objective-type, and true-or-false questions available for practice.
• Downloadable Content: Questions and answers can be downloaded as PDFs or eBooks for offline practice.

Solving Techniques

• Practice exercises that include shortcuts and tricks are provided to help solve problems more efficiently.

Example Problems and Solutions

Problem 1

• Question: A train at 60 km/hr crosses a pole in 9 seconds. Find the length of the train.
• Solution:
  • Speed conversion: ( \frac{60 \times 5}{18} = \frac{50}{3} ) m/sec
  • Length = Speed x Time = ( \frac{50}{3} \times 9 = 150 ) meters

Problem 2

• Question: A 125 m long train passes a man running at 5 km/hr in 10 seconds. Find the train's speed.
• Solution:
  • Relative speed = ( \frac{125}{10} \times \frac{18}{5} = 45 ) km/hr
  • Train speed = Relative speed + Man’s speed = 45 + 5 = 50 km/hr

Problem 3

• Question: A 130 m train crosses a bridge in 30 seconds at 45 km/hr. Find the bridge length.
• Solution:
  • Speed conversion: ( \frac{45 \times 5}{18} = \frac{25}{2} ) m/sec
  • Total distance = 130 + bridge length = ( \frac{25}{2} \times 30 )
  • Bridge length = 245 meters

Problem 4

• Question: Two trains crossing a man in 27 and 17 seconds cross each other in 23 seconds. Find the speed ratio.
• Solution:
  • Let speeds be ( x ) and ( y ) m/sec
  • Equations: 27x + 17y = 23(x + y)
  • Solving gives ratio ( x:y = 3:2 )

Problem 5

• Question: A train crosses a platform in 36 seconds and a man in 20 seconds at 54 km/hr. Find platform length.
• Solution:
  • Speed conversion: ( \frac{54 \times 5}{18} = 15 ) m/sec
  • Train length = 15 x 20 = 300 m
  • Total distance (platform + train) = 15 x 36 = 540 m
  • Platform length = 240 meters

Additional Resources

• Video Explanation: YouTube Explanation for detailed steps.