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Billiard Balls Collision Analysis

Apr 5, 2025

Billiard Balls Collision at an Angle

Introduction

  • Discussion about collision of billiard balls at an angle
  • One ball is moving at 5 m/s, and the other is at rest
  • After collision, first ball moves at a 40° angle from its original direction
  • The second ball moves in a different direction
  • Goal: Determine the speeds of the balls after collision

Key Concepts

Initial Conditions

  • V_1i: Initial velocity of the first ball = 5 m/s
  • V_2i: Initial velocity of the second ball = 0 m/s (at rest)
  • Collision Angle: First ball moves at a 40° angle post-collision

Conditions for 90° Angle of Separation

  • Elastic collision
  • Equal mass of the two balls

Angle Calculations

  • Angle of separation is 90° if both conditions are met
  • Given angle for the first ball = 40°
  • Calculated angle for the second ball = 50°

Conservation of Momentum

  • Momentum is conserved along both x-axis and y-axis

X-Axis Momentum

  • Initial momentum: ( M , V_1i )
  • Post-collision, resolve velocities into components:
    • First ball: ( M , V_{1f} , \cos(\theta) )
    • Second ball: ( M , V_{2f} , \cos(\alpha) )
  • X-axis conservation equation: [ M , V_1i = M , V_{1f} , \cos(\theta) + M , V_{2f} , \cos(\alpha) ]
  • Mass cancels out, angle values plugged in:
    • ( \cos(40°) = 0.77 )
    • ( \cos(50°) = 0.64 )

Y-Axis Momentum

  • Initial momentum along y-axis: 0 (no initial y-component)
  • Post-collision, resolve y-components:
    • First ball: ( M , V_{1f} , \sin(\theta) )
    • Second ball: ( M , V_{2f} , \sin(\alpha) ) (negative direction)
  • Y-axis conservation equation: [ M , V_{1f} , \sin(\theta) = M , V_{2f} , \sin(\alpha) ]
  • Mass cancels out, solve for relationship:
    • ( V_{1f} = V_{2f} , (1.19) )

Solution

  • Use relationship and solve equations:
    • Substitute ( V_{1f} ) in x-axis equation
    • Solve for ( V_{2f} ): 3.21 m/s
    • Substitute ( V_{2f} ) back to find ( V_{1f} ): 3.82 m/s

Conclusion

  • Speeds after collision:
    • First ball: 3.82 m/s
    • Second ball: 3.21 m/s
  • Illustration of solving using conservation of momentum principles

Additional Notes

  • If you have questions or comments, feel free to ask.
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