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Video 3.8: Implicit Differentiation Techniques
Oct 7, 2024
Section 3.8: Implicit Differentiation
Explicit Form vs. Implicit Form
Explicit Form:
Functions expressed as y = f(x).
Example: y = x^2 + 2x + 1.
Derivative found using the power rule: dy/dx = 2x + 2.
Implicit Form:
Functions not explicitly solved for y.
Example: x^2 + y^2 = xy.
Difficult or impossible to solve for y explicitly, requiring implicit differentiation.
Implicit Differentiation
Purpose:
Find dy/dx when y is not isolated in terms of x.
Key Steps: Differentiation Process
Differentiate both sides of the equation with respect to x.
Apply the chain rule to y terms (since y is a function of x).
Solve for dy/dx.
Example 1: Circle Equation
Given: x^2 + y^2 = 1.
This represents a circle of radius 1 centered at the origin.
Differentiate:
Left side: 2x + 2y(dy/dx) = 0.
Solve for dy/dx: dy/dx = -x/y.
Example 2: Another Equation
Given: y - x^2 + 2x = 1.
Implicit differentiation results in the same derivative as explicit differentiation.
Example 3: Complex Equation
Given: y^2 + 3x = 2.
Find derivative at the point (-1, √5).
Solve: dy/dx = -3/(2y).
At the point (-1, √5), the slope becomes -3/(2√5).
Complex Example with Product Rule
Given: yx^2 + y^3 = cos(y).
Use implicit and product rules:
Differentiate and solve: dy/dx = -2xy / (x^2 + 3y^2 + sin(y)).
Example with Exponential Function
Given: x^2y^2 + e^y = tan(y).
Implicit differentiation: dy/dx = -2xy^2 / (x^2y + e^y - sec^2(y)).
Application: Normal Line
Given: x^3 + x^2y + 4y^2 = 6.
Find normal line at point (1, 1).
Slope of tangent at (1, 1) is -5/9; normal line slope is 9/5.
Additional Example
Given: 1 + x = sin(xy^2).
Using implicit differentiation, solve for dy/dx.
Intersection of Curves
Hyperbola:
x^2 - y^2 = 5.
Ellipse:
4x^2 + 9y^2 = 72.
Intersection point (3, 2) shows lines are perpendicular (slopes are negative reciprocals).
Caution with Implicit Equations
Not every implicit equation represents a meaningful function.
Example: e^(x^2 + y^2) = 0 has no solutions, hence its derivative is meaningless.
Always consider if a function satisfying the equation exists.
Summary
Implicit differentiation is crucial for equations not explicitly solvable for y.
Be aware of assumptions concerning the existence of functions for implicit equations.
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