General Physics: Momentum and Impulse
Welcome to the lesson on momentum and impulse, part of a comprehensive University-level physics series. The focus today is on understanding momentum and impulse before moving on to collisions in the next lesson.
Introduction
- Presenter: Chad from Chad's Prep
- Purpose: To simplify learning science and provide resources for students (General Chemistry, Organic Chemistry, General Physics, High School Chemistry).
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Key Concepts
Momentum
- Definition: Momentum (symbol: ( p )) is a vector quantity equal to mass times velocity.
- Formula: ( p = m \times v )
- It depends on both mass and velocity.
- Doubling mass or velocity doubles momentum; doubling both quadruples momentum.
- Direction of momentum is the same as velocity.
- Can be one or two-dimensional (linear momentum).
Impulse
- Definition: Impulse is a vector equal to force times the duration of time it acts.
- Formula: ( I = F \times \Delta t )
- Impulse changes an object's momentum.
- Related through the Impulse-Momentum Theorem: ( I = \Delta p )
- Units: Kilogram meter per second (kg路m/s), same as momentum.
Impulse-Momentum Theorem
- Impulse equals the change in momentum: ( F \Delta t = \Delta p )
- Derivation from Newton's Second Law: ( F = m \times a )
- Acceleration ( a = \Delta v / \Delta t )
- Rearranging gives ( F \Delta t = m \Delta v )
- Simplifies to ( I = \Delta (mv) )
Sample Problems
Problem 1 - Momentum Calculation
- A 1200 kg car traveling at 20 m/s.
- Momentum: ( 1200 \times 20 = 24000 ) kg路m/s
Problem 2 - Impulse and Velocity Change
- Car hits a cow applying avg. force of 90,000 N over 0.20 s.
- Impulse: ( F \Delta t = 90,000 \times 0.20 = 18,000 ) kg路m/s (in the opposite direction)
- New Velocity: Solving ( -18,000 = 1200(v_f - 20) ) gives ( v_f = 5.0 ) m/s
Problem 3 - Change in Momentum
- Car hit by a truck, moving backwards at 10 m/s.
- Change in Momentum: ( \Delta p = m(v_f - v_i) = 1200(-10 - 20) = -36,000 ) kg路m/s
Problem 4 - Impulse Duration
- Baseball hit off a tee, initial speed 0, final speed 40 m/s, force 10,000 N.
- Time: ( \Delta t = \frac{0.1 \times 40}{10,000} = 4.0 \times 10^{-4} ) seconds (0.4 ms)
Conclusion
- Understanding the relationship between impulse and momentum is crucial for solving physics problems involving force and motion.
- Emphasis on signs and directional vectors in calculations.
- Encouragement to like and support if the lesson was helpful, and happy studying!