Northwest Corner Method for Transportation Problem
Introduction
- Objective: Find the initial basic feasible solution using the Northwest Corner Method.
- Components of the problem:
- Sources: F1, F2, F3
- Destinations: A, B, C, D
- The number (e.g. 60) in the grid shows the cost of transportation for one unit.
- Supply capacity is given for each source.
- Demand is given for each destination.
Steps in the Northwest Corner Method
- Start at the top-left corner (Northwest corner).
- Allocate units based on the minimum of supply and demand.
- Adjust supply and demand after each allocation.
- Cross out rows or columns where supply or demand is exhausted.
- Move to the next cell (always moving right or down).
Detailed Procedure
Step 1: Allocate from F1 to A
- Supply (F1): 30
- Demand (A): 35
- Minimum: 30
- Allocate: 30 units
- Adjustments:
- F1 supply: Exhausted
- A demand: 35 - 30 = 5
- Cross out row of F1
Step 2: Allocate from F2 to A
- Supply (F2): 40
- Remaining Demand (A): 5
- Minimum: 5
- Allocate: 5 units
- Adjustments:
- F2 supply: 40 - 5 = 35
- A demand: Exhausted
- Cross out column of A
Step 3: Allocate from F2 to B
- Supply (F2): 35
- Demand (B): 28
- Minimum: 28
- Allocate: 28 units
- Adjustments:
- F2 supply: 35 - 28 = 7
- B demand: Exhausted
- Cross out column of B
Step 4: Allocate from F2 to C
- Supply (F2): 7
- Demand (C): 32
- Minimum: 7
- Allocate: 7 units
- Adjustments:
- F2 supply: Exhausted
- C demand: 32 - 7 = 25
- Cross out row of F2
Step 5: Allocate from F3 to C
- Supply (F3): 50
- Remaining Demand (C): 25
- Minimum: 25
- Allocate: 25 units
- Adjustments:
- F3 supply: 50 - 25 = 25
- C demand: Exhausted
- Cross out column of C
Step 6: Allocate from F3 to D
- Supply (F3): 25
- Demand (D): 25
- Minimum: 25
- Allocate: 25 units
- Adjustments:
- F3 supply: Exhausted
- D demand: Exhausted
Summary of Allocations
| Source-Destination | Units Allocated | Cost Per Unit | Total Cost |
|--------------------|-----------------|---------------|------------|
| F1 to A | 30 | 6 | 180 |
| F2 to A | 5 | 5 | 25 |
| F2 to B | 28 | 11 | 308 |
| F2 to C | 7 | 9 | 63 |
| F3 to C | 25 | 7 | 175 |
| F3 to D | 25 | 18 | 450 |
Total Cost: 1076
Conclusion
- The initial basic feasible solution utilizes the Northwest Corner Method with a total transportation cost of 1076.