Common Electrical Formulas for DC Circuits
Basic Circuit Components
- Battery: Provides the voltage.
- Resistor: Limits the current flow.
- Conventional Current: Flows from the positive terminal to the negative terminal of the battery.
- Electron Flow: Opposite to conventional current.
Key Electrical Formulas
Ohm's Law
- Formula: ( V = IR )
- ( V ): Voltage in volts
- ( I ): Current in amps
- ( R ): Resistance in ohms
Power
- Formula:
- ( P = VI )
- ( P = I^2R )
- ( P = \frac{V^2}{R} )
- ( P ) measured in watts
- Conversions:
- 1 Horsepower = 746 watts
- 1 Watt = 1 Joule/second
Electrical Work/Energy
- Formula:
- Work = Power ( \times ) Time
- ( Energy = Charge \times Voltage )
- Current: Rate of charge flow, ( I = \frac{Q}{t} )
Series Circuits
- Current: Same through all components (( I_T = I_1 = I_2 = I_3 )).
- Total Resistance: ( R_T = R_1 + R_2 + R_3 )
- Voltage Drop: ( V = IR )
- ( V_1 = I_1R_1 )
- ( V_2 = I_2R_2 )
- ( V_3 = I_3R_3 )
- Kirchhoff's Voltage Law: ( V_B = V_1 + V_2 + V_3 )
Parallel Circuits
- Voltage: Same across all components (( V_B = V_1 = V_2 = V_3 )).
- Total Resistance: ( \frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} )
- Total Current: ( I_T = I_1 + I_2 + I_3 )
- Kirchhoff's Current Law: The total current entering a junction equals the total current leaving it.
Example Problem: Current Calculation
- Scenario: Calculate unknown current ( I_5 ).
- Given:
- ( I_1 = 20 ) amps
- ( I_2 = 18 ) amps
- ( I_3 = 13 ) amps
- ( I_4 = 29 ) amps
- Solution:
- ( I_T = I_1 + I_2 - I_3 - I_4 + I_5 = 0 )
- Solve for ( I_5 ):
- If ( I_4 = 29 ), ( I_5 = 4 ) amps towards the junction.
Conclusion
- Common formulas used for analyzing simple DC circuits.
- Kirchhoff's laws are essential for understanding current and voltage distributions.
For more practice problems and related content, check out the links provided in the description.