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Dimensional Analysis and Unit Conversions
Nov 12, 2024
Lecture Notes: Dimensional Analysis and Conversion Calculations
Introduction
Focus on calculations involving significant figures.
Explore dimensional analysis for unit conversions, primarily in metric systems.
Dimensional Analysis
Definition
: A method to convert between units ensuring units cancel out appropriately.
Process
: Start with a given value, use conversion factors, and perform calculations so units cancel.
Metric Conversions
Common Metric Conversions
:
Many involve factors of 1000, assign 1000 to the smaller unit.
Example: 1000 milliliters (mL) in a liter (L).
Examples
:
Convert 83 cm to meters (83 cm ÷ 100 = 0.83 m).
Convert 4.59 L to mL (4.59 L × 1000 = 4590 mL).
Convert 78.24 mg to grams (78.24 mg ÷ 1000 = 0.07824 g or 7.824 × 10^-2 g in scientific notation).
Temperature Conversions
Fahrenheit to Celsius
:
Formula: ( C = (F - 32) \times \frac{5}{9} )
Example: 172.9°F to Celsius gives 78.3°C.
Celsius to Kelvin
:
Formula: Add 273.15 to the Celsius temperature.
Example: 212 K to Celsius results in -61.15°C.
Problem Solving with Units
Steps
:
Identify starting and ending units.
Prepare a list of conversion factors.
Arrange units to ensure cancellation.
Decide on multiplication or division based on the position of numbers (top or bottom).
Example Problems
Volume Conversion
:
12 oz to mL using the factor 29.6 mL per fluid oz: 12 × 29.6 = 355 mL
Volume in Medicine
:
Convert 5 microliters to mL: Use multiple conversion factors for microliters to liters, then liters to mL (final result: 5.0 × 10^-3 mL).
Mass Conversion
:
Convert long tons (2240 lbs) to kilograms using 1 kg = 2.2046 lbs: Result is 1020 kg.
Area and Volume
:
Convert area in miles squared to km squared, and volume in cubic miles to cubic km using appropriate squared or cubed conversion factors.
Density
Definition
: Density = Mass/Volume
Using Density as Conversion Factor
:
Density of mercury used to convert volumes to mass.
Example: Convert 6.0 cm³ mercury to grams (density = 13.5939 g/cm³): 6.0 × 13.5939 = 81.6 g
Reverse Conversion
:
Given mass to find volume using inverse density.
Conclusion
Practice problems and quizzes after each lecture.
Encourage working on problems periodically instead of all at once.
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