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Understanding Quadratic Equations by Factoring
Aug 22, 2024
Solving Quadratic Equations by Factoring
Introduction
Topic: Solving quadratic equations by factoring.
Importance of finding values of x that make the equation equal to zero.
Process of solving quadratic equations includes factoring.
Example 1: Factoring x² - 5x = 0
Equation:
x² - 5x = 0
Step 1:
Identify greatest common factor (GCF).
GCF = x.
Step 2:
Factor the equation.
Factored form: x(x - 5) = 0.
Step 3:
Solve for x.
Factor 1: x = 0 (x₁).
Factor 2: x - 5 = 0 ⟹ x = 5 (x₂).
Solutions:
x₁ = 0, x₂ = 5.
Example 2: Factoring 4x² - 6x = 0
Equation:
4x² - 6x = 0
Step 1:
GCF = 2x.
Step 2:
Factor the equation.
Factored form: 2x(2x - 3) = 0.
Step 3:
Solve for x.
Factor 1: 2x = 0 ⟹ x = 0 (x₁).
Factor 2: 2x - 3 = 0 ⟹ x = 3/2 (x₂).
Solutions:
x₁ = 0, x₂ = 3/2.
Example 3: Difference of Two Squares
Equation:
x² - 49 = 0
Step 1:
Recognize as difference of squares.
Factored form: (x + 7)(x - 7) = 0.
Step 2:
Solve for x.
Factor 1: x + 7 = 0 ⟹ x = -7 (x₁).
Factor 2: x - 7 = 0 ⟹ x = 7 (x₂).
Solutions:
x₁ = -7, x₂ = 7.
Example 4: Factoring 3x² - 75 = 0
Equation:
3x² - 75 = 0
Step 1:
GCF = 3.
Step 2:
Factor the equation.
Factored form: 3(x² - 25) = 0 ⟹ 3(x + 5)(x - 5) = 0.
Step 3:
Solve for x.
Factor 1: x + 5 = 0 ⟹ x = -5 (x₁).
Factor 2: x - 5 = 0 ⟹ x = 5 (x₂).
Solutions:
x₁ = -5, x₂ = 5.
Example 5: Factoring a Trinomial
Equation:
x² - 2x - 15 = 0
Step 1:
Prepare two sets of parentheses.
Step 2:
Find factors of -15 that sum to -2.
Factors: -5 and 3.
Step 3:
Factor the equation.
Factored form: (x - 5)(x + 3) = 0.
Step 4:
Solve for x.
Factor 1: x - 5 = 0 ⟹ x = 5 (x₁).
Factor 2: x + 3 = 0 ⟹ x = -3 (x₂).
Solutions:
x₁ = 5, x₂ = -3.
Example 6: Assignment
Problem: Factor x² + 5x + 6 = 0.
Example 7: More Factoring
Equation:
x² + 3x - 28 = 0
Step 1:
Prepare parentheses.
Step 2:
Find factors of -28 that sum to 3.
Factors: 4 and -7.
Step 3:
Factor the equation.
Factored form: (x + 7)(x - 4) = 0.
Step 4:
Solve for x.
Factor 1: x + 7 = 0 ⟹ x = -7 (x₁).
Factor 2: x - 4 = 0 ⟹ x = 4 (x₂).
Solutions:
x₁ = -7, x₂ = 4.
Conclusion
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