Diagonalizable Matrix: An n x n square matrix A is diagonalizable if there exists an invertible n x n matrix P and a diagonal matrix D such that AP = PD.
Similar Matrices: If A and D have this relationship, they are similar matrices.
Theorems
Theorem 1: If matrix A has n distinct eigenvalues, then A is diagonalizable.
Diagonalizable if and only if A has n linearly independent eigenvectors.
Visualizing Theorems:
A is diagonalizable ↔ A has n linearly independent eigenvectors.
n distinct eigenvalues → A is diagonalizable.
n distinct eigenvalues → n linearly independent eigenvectors.
Process of Diagonalizing a Matrix
Find Eigenvalues
Include multiple roots (e.g., lambda - 1 squared).
Arrange eigenvalues as diagonal entries of D.
Find Eigenvectors
For each eigenvalue, find corresponding eigenvectors.
Use these eigenvectors as columns in matrix P.
Ensure Vi is an eigenvector corresponding to lambda i.
Ensure enough eigenvectors are present; otherwise, A is not diagonalizable.
Examples
Example 1
Given eigenvalues of A are 0 and 6.
Steps:
Note: Two distinct eigenvalues imply A is diagonalizable.
Matrix D: Diagonal matrix with eigenvalues 0 and 6.
Matrix P: Construct using eigenvectors for 0 and 6.
Calculations:
Solve A - 0I2 and A - 6I2 for eigenvectors.
Construct P using eigenvectors.
Verify AP = PD.
Example 2
No given eigenvalues.
Steps:
Compute determinant of A - lambda I2 for eigenvalues.
Check eigenvalues: lambda = -3 with multiplicity 2.
Find eigenvectors for lambda = -3.
Result:
Only one independent eigenvector found → A is not diagonalizable.