Jul 20, 2024
\sin(42) = \frac{X}{13}X = 13 \times \sin(42) ≈ 8.7\tan(37) = \frac{Y}{10}Y = 10 \times \tan(37) ≈ 7.5\cos(41) = \frac{13}{Q}Q = \frac{13}{\cos(41)} ≈ 17.2\tan(X) = \frac{5}{12}X = \text{tan}^{-1}(\frac{5}{12}) ≈ 22.6^{\circ}\cos(X) = \frac{4}{13}X = \text{cos}^{-1}(\frac{4}{13}) ≈ 72.1^{\circ}\sin(X) = \frac{5}{10}X = \text{sin}^{-1}(\frac{5}{10}) = 30^{\circ}