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Calculus Optimization Summary

Jul 12, 2025

Overview

This lecture covers optimization problems in calculus, focusing on maximizing or minimizing functions in contexts such as productivity, drug dosage, geometry, and profit.

Maximizing Productivity

  • Productivity as a function of years of service is optimized by finding critical values of its derivative.
  • The first derivative is set to zero: -8T + 224 = 0; solving gives T = 28.
  • Second derivative is negative, indicating a maximum at T = 28.
  • Productivity is greatest when T = 28 years, yielding maximum output.

Drug Dosage and Maximum Blood Pressure

  • Blood pressure function maximized with respect to drug dosage.
  • First derivative set to zero; factored to find critical values at X = 0 and X = 1/9.
  • First derivative test confirms X = 1/9 is a relative maximum.
  • Maximum blood pressure occurs when dosage is X = 1/9 (≈0.111 cc).

Maximize Function with Constraints

  • Maximize b = xy² with constraint x + y² = 9, x > 0, y > 0.
  • Substitute x = 9 - y² to get b in one variable.
  • Take first and second derivatives; solve for critical values.
  • Valid maximum at y = 3/√2, x = 9 - (3/√2)² = 4.5.
  • Maximum value of b is 81/4.

Maximizing Rectangular Area (Swim Area Problem)

  • Area A = xy, constrained by perimeter 2x + y = 1800 (since one side is on the shoreline).
  • Substitute y = 1800 - 2x, so A = x(1800 - 2x).
  • Derivative set to zero gives x = 450, y = 900.
  • Maximum area is 450 × 900 = 405,000 square yards.

Maximum Profit Problem

  • Profit P = Revenue - Cost; profit function is P(x) = 35x - 0.1x² - 20.
  • Set derivative P'(x) = -0.2x + 35 to zero; solve for x = 175.
  • Second derivative is negative; confirms maximum at x = 175 units.
  • Maximum profit when producing/selling 175 units is $3,042.50.

Key Terms & Definitions

  • Critical Value — Where the first derivative is zero or undefined; used to find maxima/minima.
  • Objective Function — The function to be maximized or minimized.
  • Constraint — An equation or inequality that limits variables in optimization.
  • Second Derivative Test — Determines concavity to confirm maxima or minima.

Action Items / Next Steps

  • Practice setting up and solving optimization problems with constraints.
  • Review how to apply the first and second derivative tests for maxima and minima.
  • Complete assigned homework problems on optimization using calculus.