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VIDEO: 5.2 Understanding Mass Percents in Chemistry

Oct 23, 2024

Lecture Notes: Mass Percents and Empirical Molecular Formulas

Introduction

  • Topic: Mass percents and empirical molecular formulas
  • Part of a high school chemistry series on stoichiometry
  • Lecturer: Chad from Chad's Prep
  • Lessons will be released weekly throughout the 2020-21 school year

Mass Percents

  • Concept: Percentage of each element within a compound based on mass
  • Formula: ( \text{Percent} = \frac{\text{grams of element}}{\text{total grams of sample}} \times 100 )
  • Example: Calcium carbonate (CaCO3)
    • Convenient sample size: 1 mole (100 grams total)
    • Calculating Percentages:
      • Carbon: 12 grams of carbon in 1 mole, thus 12% carbon
      • Oxygen: 48 grams of oxygen in 1 mole, thus 48% oxygen

Intensive Property

  • Mass percents are intensive properties
  • Independent of sample size

Empirical vs. Molecular Formulas

  • Molecular Formula: Actual number of atoms of each element in a molecule
  • Empirical Formula: Simplest whole number ratio of atoms in a compound

Examples

  • Benzene (C6H6): Empirical formula CH
  • P4O10: Empirical formula P2O5
  • Ethanol (C2H6O): Empirical formula same as molecular formula

Converting Mass Percents to Empirical Formula

  • Example: Compound with 80% carbon and 20% hydrogen by mass
    • Start with 100 gram sample size for easier math
    • Convert mass to moles:
      • Carbon: 80 grams -> 6.67 moles (12 g/mol)
      • Hydrogen: 20 grams -> 20 moles (1 g/mol)
    • Empirical Formula Calculation:
      • Ratio: C6.67H20
      • Simplify by dividing by smallest number (6.67)
      • Empirical formula: CH3

Handling Non-Whole Number Ratios

  • If ratio is not a whole number (e.g., C1H2.5)
    • Multiply to get whole numbers (e.g., multiply by 2 to get C2H5)

Determining Molecular Formula

  • Empirical formula alone can't determine molecular formula
  • Requires additional data: Molecular weight or molar mass
  • Example: Given molecular weight of 30 AMUs
    • Empirical weight of CH3: 15
    • Molecular formula: Double empirical formula to C2H6

Conclusion

  • Understanding mass percents and empirical formulas is essential for stoichiometry
  • Practice problems and further resources available on Chad's Prep website

Additional Resources

  • Chad's Prep website for practice problems and study guides: chadsprep.com

Feel free to leave questions in the comment section of the lecture video.