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Evaluating Definite Integrals

Aug 19, 2025

Overview

This lecture explains how to evaluate definite integrals by finding antiderivatives and applying limits of integration, using step-by-step examples.

Definite vs. Indefinite Integrals

  • A definite integral has lower (a) and upper (b) limits of integration.
  • An indefinite integral does not have specific integration limits.
  • The result of a definite integral is a number; indefinite integrals result in a general function plus a constant (C).

Finding Antiderivatives

  • The antiderivative (integral) of f(x) is denoted as F(x).
  • To find the antiderivative of xⁿ, use xⁿ⁺¹/(n+1).
  • For a constant times xⁿ, factor out the constant and then integrate xⁿ.
  • For definite integrals, you do not add the constant of integration (C).

Evaluating a Definite Integral: Step-by-Step

  • Integrate each term in the function separately.
  • For example, ∫8x³dx = 8x⁴/4; ∫3x²dx = 3x³/3; ∫6xdx = 6x²/2.
  • Simplify each term: 8/4 = 2; 3/3 = 1; 6/2 = 3.
  • Combine to get the antiderivative: 2x⁴ + x³ + 3x².
  • Apply the limits: compute F(b) - F(a), where F(x) is the antiderivative.
  • Substitute b (upper limit) and a (lower limit) into F(x), then subtract the results.

Example Calculation

  • Definite integral from x = 2 to x = 3 of 8x³ + 3x² + 6x:
  • Antiderivative: 2x⁴ + x³ + 3x².
  • F(3) = 2(3⁴) + 3³ + 3(3²) = 162 + 27 + 27 = 216.
  • F(2) = 2(2⁴) + 2³ + 3(2²) = 32 + 8 + 12 = 52.
  • Definite integral value: 216 - 52 = 164.

Interpretation

  • The value of a definite integral represents the area under the curve of the function between the specified x-values.

Key Terms & Definitions

  • Definite Integral — Integral with upper and lower limits, giving a specific value.
  • Indefinite Integral — Integral without limits; solution includes a constant.
  • Antiderivative — Function whose derivative is the original function (F(x) for f(x)).

Action Items / Next Steps

  • Review additional example problems from the provided video description links.
  • Practice evaluating definite integrals with more complex functions, such as those involving square roots.