In this video, I'm going to talk about cis and trans isomers. So what are cis and trans isomers? How would you describe them? So, the cis isomer... has two groups on the same side.
So on the left we have the cis isomer and the trans isomer has two groups on opposite sides. Now these two isomers they have different physical properties. In fact, the isomer on the left has a dipole moment of approximately 3 Debye, and the one on the right is 0. The one on the right is nonpolar.
The one on the left is polar. The carbon-chlorine bond is relatively polar, and so if you draw the dipole moment, notice that on the right, the arrows, they cancel. The arrow has to point towards the more electronegative chlorine atom. On the left, they don't cancel.
In fact, there's a net dipole moment that goes upward if you add these two vectors. And so that's why this molecule is polar. So because it's polar, the boiling point of the cis isomer is greater than that of the trans isomer. So for the cis isomer, the boiling point is about 60 degrees Celsius.
And for the trans isomer, it's less. It's about 47.5. So polar molecules typically have a higher boiling point than nonpolar molecules.
As you can see, the cis and trans isomers have different physical properties. They have different boiling points and different dipole moments. And this is due to the fact that the double bond lacks free rotation.
In order for the trans isomer to convert to the cis isomer, you have to break the pi bond and so this hydrogen cannot easily switch positions with the chlorine and that's why you have such different physical properties. In the case of ethane you do have free rotation among the carbon carbon single bond. The energy barrier is very low it's like 12 kilojoules per mole in order to switch between the staggered and the eclipsed conformation.
But in the case of cis and trans isomers the energy barrier is very very high so it takes a lot of energy to break that pi bond. And so, these are two distinct isomers with different physical properties. So, it takes a lot of energy to go from the trans form into the cis form. And so, there's no free rotation with cis and trans isomers. It takes a lot of energy to convert from one form to another.
Now, there's different ways to represent cis and trans isomers. You can also represent them... using rings.
In this example, we're going to have two hydroxyl functional groups on the wedge. So that is going out of the page. And on the right, we're going to have one on the dash, which is going into the page, and one on the wedge. So on the left, we have the cis isomer, because Both hydroxyl groups are going in the same direction out of the page. On the right, we have the trans isomer.
One is going into the page, the other one is going out of the page. So one is going up, the other is going down, and so they're in opposite directions. And so that's another way in which you could represent cis and trans isomers.
Now consider these four molecules. So what I want you to do is determine which of these alkenes can show Cis and trans isomerism. So which of these molecules can you draw cis and trans isomers for?
So let's look at the first example on the left. Can we draw the cis and trans isomer for this alkane? It turns out that we can't because on the carbon at the left, it has two atoms that are the same.
So if the two groups are the same, You can't show cis and trans isomerism. For this one you could. This is the trans isomer.
So this carbon is attached to two different groups. It's attached to a hydrogen and a methyl group. And this carbon is attached to two different groups, a hydrogen and an ethyl group. So what we have here is the trans isomer.
So if we want to draw the cis isomer, we can draw like this. And so notice that the hydrogen atoms are facing the same side. So that's the cis isomer for this particular alkene.
Now for the third example, we can't show any cis or trans isomers because this carbon is attached to the same group. It doesn't have two different groups attached to it. The same is true for the last one.
This carbon that's part of the double bond is attached to two methyl groups. So because these two methyl groups are identical to each other, this alkene doesn't have any cis or trans isomers. So the only one that has it is this example. So that's how you can tell if an alkene will have cis and trans isomers. Look at each carbon that is part of the double bond and analyze them.
See if they're attached to two different groups or if they're attached to two of the same group.