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Understanding Fourier Series and Coefficients

May 5, 2025

Fourier Series Lecture Notes

Introduction

  • Discussing Fourier series and how they approximate functions with trigonometric terms (sine and cosine).
  • Previous video covered the basics; this video goes deeper.

Key Questions Addressed

  1. How to compute the coefficients (aâ‚€, aâ‚™, bâ‚™) in a Fourier series.
  2. When does a Fourier series converge and provide a good approximation?

Mathematical Identities

  • Integrals of Trigonometric Functions:
    • Integral of sin(m·t) * sin(n·t):
      • Equals Ï€ if m = n.
      • Equals 0 if m ≠ n.
    • Integral of cos(m·t) * cos(n·t):
      • Equals Ï€ if m = n.
      • Equals 0 if m ≠ n.
    • Integral of cos(m·t) * sin(n·t):
      • Always equals 0.*

Computing Fourier Coefficients

  • Objective: Find coefficients aâ‚€, aâ‚™, bâ‚™ such that function f(t) is approximated by the Fourier series.
  • Procedure:
    1. Multiply the Fourier series by sin(m·t) and integrate from 0 to 2π.
      • Only the term with the same sine frequency contributes: b_m * Ï€ = integral from 0 to 2Ï€ of f(t) * sin(m·t) dt.
      • Solve for b_m:
        • b_m = 1/Ï€ * integral from 0 to 2Ï€ of f(t) * sin(m·t) dt.
    2. Multiply by cos(m·t) and integrate from 0 to 2π.
      • Only the term with the same cosine frequency contributes: a_m * Ï€ = integral from 0 to 2Ï€ of f(t) * cos(m·t) dt.
      • Solve for a_m:
        • a_m = 1/Ï€ * integral from 0 to 2Ï€ of f(t) * cos(m·t) dt.
    3. To find aâ‚€, multiply by 1 and integrate.
      • aâ‚€ = 1/Ï€ * integral from 0 to 2Ï€ of f(t) dt.*

Example Application

  • Function: f(t) = 1 from 0 to Ï€, and 0 from Ï€ to 2Ï€.
  • Find Coefficients:
    • aâ‚€ = 1.
    • aâ‚™ = 0 for n ≥ 1.
    • For odd m, b_m = 2/(Ï€ * m).
    • Resulting Fourier series: 1/2 + Σ (2/(Ï€ * n)) * sin(mt) for odd n.*

Convergence of Fourier Series

  • Fourier Convergence Theorem:
    • If f and f' are piecewise continuous, the series converges to:
      • f(t) where f is continuous.
      • Midpoint of discontinuity where f is discontinuous.
    • Demonstrates relaxed conditions for convergence.

Conclusion

  • Fourier series can approximate functions with both continuous and discontinuous points well.
  • Series converges to the function itself or the midpoint of discontinuities as more terms are considered.

Important Formulas

  • Fourier Coefficients:
    • aâ‚€ = 1/Ï€ * integral from 0 to 2Ï€ of f(t) dt
    • aâ‚™ = 1/Ï€ * integral from 0 to 2Ï€ of f(t) * cos(n·t) dt
    • bâ‚™ = 1/Ï€ * integral from 0 to 2Ï€ of f(t) * sin(n·t) dt*