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Exploring Constitutional Isomers in Chemistry

Sep 15, 2024

Lecture on Drawing Constitutional Isomers

Introduction

  • Topic: Drawing Constitutional Isomers in Organic Chemistry
  • Previous Topics: Naming alkanes, drawing conformations of alkanes
  • Future Topics: Newman projections, conformations of cycloalkanes (e.g., cyclohexane chair conformation)

Channel Introduction

  • Host: Chad from Chad's Prep
  • Goal: Make science understandable and enjoyable
  • Series: Weekly organic chemistry lessons for 2020-21
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Understanding Hydrocarbons

  • Saturated vs. Unsaturated Hydrocarbons

    • Saturated: Max hydrogens possible, formula CnH2n+2
    • Unsaturated: Contains pi bonds/rings, reduces hydrogen count
    • Example: C7H16 (saturated) vs. C7H14 (unsaturated)
  • Degrees of Unsaturation

    • Every pi bond or ring removes 2 hydrogens from saturation
    • Hydrogen Deficiency Index: (2C + 2 - H - Hal + N) / 2 = Degrees of Unsaturation

Drawing Constitutional Isomers

  • Saturated Hydrocarbons (C7H16 Example)

    • No pi bonds or rings
    • Start with longest chain and reduce step by step
  • Methods for Drawing Isomers

    • Start with the longest chain (7 carbons)
    • Reduce to 6, 5, 4 carbons while adding branches
    • Avoid end placement for branches to ensure new isomers
    • Unique positions for branches on middle carbons

Detailed Example: Drawing Isomers for C7H16

  • 7 carbon chain: Simple straight chain
  • 6 carbon chain: Explore positions for single carbon branches
  • 5 carbon chain:
    • Add two branches (methyl groups) in different positions
    • Consider single ethyl group placement
  • 4 carbon chain: Limited options, fill 3 out of 4 middle positions

Incorporating Oxygen (C4H10O Example)

  • Understand how oxygen does not affect the saturation calculation

  • Oxygen Placement

    • Can form alcohols (OH group) or ethers (O in chain)
  • Alcohols: Oxygen bonded at different locations

    • On end carbons or 1 carbon in
  • Ethers: Oxygen between carbons

    • Divide carbons as 3-1 or 2-2 across the oxygen

Conclusion

  • Total Isomers for C4H10O: 7 (4 alcohols, 3 ethers)
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