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Boundary Traversal of Binary Tree
Jun 27, 2024
Boundary Traversal of Binary Tree
Overview
Goal
: Print the boundary traversal of a binary tree (currently focusing on anti-clockwise traversal).
Steps
: Left boundary (excluding leaves), leaf nodes, right boundary (in reverse, excluding leaves).
Steps to Solve the Problem
1. Left Boundary (Excluding Leaves)
Start
with the root of the tree.
Include the root
in the data structure to store the boundary traversal.
Move to the left of the root
.
If the left node is not a leaf, add it to the data structure.
If a left node doesn't exist, move to the right node.
Continue this until reaching a leaf node, then stop.
2. Leaf Nodes
Perform an inorder traversal
of the tree to fetch leaf nodes.
Inorder traversal: Visit left subtree → root → right subtree.
Check each node: If it's a leaf node, add it to the data structure.
This ensures leaf nodes are captured from left to right.
3. Right Boundary (In Reverse, Excluding Leaves)
Start
with the root's right node.
Use a stack or vector
to store these nodes temporarily.
Move to the right nodes
.
Add nodes if they are not leaves.
If a right node doesn't exist, move to the left node.
Stop at leaf nodes.
Reverse the stored nodes
before adding them to the final boundary traversal to ensure anti-clockwise order.
Algorithm Summary
Left Boundary
: Traverse left, if not left, then right. Exclude leaves.
Leaf Nodes
: Inorder traversal to check for leaf nodes.
Right Boundary
: Traverse right, if not right, then left. Exclude leaves. Reverse order.
Final Boundary Traversal
: Combine results from the above steps.
Code Explanation
C++ and Java Code Overview
Initialization
: Declare a vector or data structure to store boundary traversal.
Root Check
: If the root is empty, return an empty data structure.
Add Root
: If the root is not a leaf, add it to the data structure.
Left Boundary
:
Start from root's left.
Add nodes to left boundary data structure if not leaves.
Move left or right accordingly.
Right Boundary
:
Start from root's right.
Add nodes to a temporary data structure if not leaves.
Move right or left accordingly.
Reverse the temporary data structure and append to final result.
Leaf Nodes
:
Use inorder traversal to add leaf nodes to the data structure.
Combine Results
: Merge results from left boundary, leaf nodes, and reversed right boundary.
Time and Space Complexity
Time Complexity
: O(N), where N is the number of nodes in the tree.
Left boundary: O(Height of Tree)
Right boundary: O(Height of Tree)
Inorder traversal: O(N)
Space Complexity
: O(N), considering the space required to store the traversal sequence.
Closing Notes
Make sure to implement the algorithm correctly in code.
The provided code examples (C++ and Java) can be useful for reference.
Remember to like and subscribe to the channel for more content.
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