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Understanding Circle Equations and Properties

Mar 24, 2025

Lecture Notes: Equation of a Circle

Definition of a Circle

  • A circle is the set of all points equidistant from a fixed point, known as the center.
  • The radius is the distance from the center to any point on the circle.

Equations of a Circle

  • General Form (center at any point (h, k)):
    • ((x - h)^2 + (y - k)^2 = r^2)
  • Simplified Form (center at the origin (0, 0)):
    • (x^2 + y^2 = r^2)

Explanation of the Circle Equation

  • A right triangle can be formed by:
    • The distance from the origin to ((x, y)) which is (x) units parallel to the x-axis and (y) units parallel to the y-axis.
    • Using the Pythagorean Theorem: (x^2 + y^2 = r^2) describes the relationship.

Examples

  • Example 1: Equation for a circle with center (0,0) and radius 3:
    • Formula: (x^2 + y^2 = 9)
  • Example 2: Equation with radius (\frac{1}{2}):
    • Formula: (x^2 + y^2 = \frac{1}{4})
  • Example 3: Determine the radius from the equation (x^2 + y^2 = 36):
    • Radius (r = 6) units.
  • Example 4: Circle centered at origin passing through ((5, 3)):
    • Find (r^2) by substituting (x = 5), (y = 3) into the equation.
    • Result: (x^2 + y^2 = 34).

Determining Point Position Relative to a Circle

  • If on the circle: (x^2 + y^2 = r^2)
  • If outside the circle: (x^2 + y^2 > r^2)
  • If inside the circle: (x^2 + y^2 < r^2)
  • Example: Point ((-5, 9)) relative to (x^2 + y^2 = 100)
    • Calculation shows ((-5)^2 + 9^2 = 106) which is greater than 100, thus outside the circle.

Equation of a Circle Not Centered at the Origin

  • Given: Center ((3,4)), radius 8
  • Equation: ((x - 3)^2 + (y - 4)^2 = 64)

Shortest Distance from a Point to the Circle

  • Tip: Shortest distance follows a line through the circle's center.
  • Use the distance formula between the point and the center, subtract the radius.
  • Example: From point ((10, 7)) to circle (x^2 + y^2 = 49)
    • Full distance: (\sqrt{149})
    • Subtract radius (7), shortest distance (= 5.21) units.

Conclusion

  • Practice problems available at Jensen Math for further learning.