Transcript for:
Video #6: Limit Evaluation Example 2

In this video we're going to look at an example using the properties of limits to find the limit as x approaches six of the cube root of two plus x. So we have the limit as x approaches six of the cube root of two plus x. The first limit property we will apply involves the root on the most outside of this function. The limit property tells us that the limit of a root is the root of the limit, especially if we're dealing with an odd root. So we're looking at now the cube root of the limit as x approaches six of two plus x. Now we will use the summation of limits. Now we will use our sum property for limits inside of this root to break this down a little bit further. We're looking at the cube root of the limit as x approaches six of two plus the limit as x approaches six of x. Let's extend our root bar a little further. Now to figure out each of these two limits we'll return back to our limit properties. Looking at the cube root of the limit as x approaches six of two will be that constant. It doesn't matter what x is approaching if this is a constant here that limit is that constant, and this second limit we can rephrase it as a question: what is x approaching as x approaches six? Seems a little tautological that this would say that our answer is six for that part, or we end up with the cube root of eight which equals two.