Elastic Collision Analysis and Solutions

Mar 26, 2025

Lecture Notes: Elastic Collision Problem

Problem Statement

  • A 4 kg ball moving east at 5 m/s strikes a 2 kg ball at rest.
  • Objective: Calculate the velocities of both balls post-collision assuming a perfectly elastic collision.

Key Concepts

  • Conservation of Momentum: Momentum is always conserved in collisions.
  • Conservation of Kinetic Energy: In perfectly elastic collisions, kinetic energy is conserved.

Equations Needed

  1. Conservation of Momentum: [ m_1 \cdot v_1 + m_2 \cdot v_2 = m_1 \cdot v_1' + m_2 \cdot v_2' ]

    • (v_1): Initial velocity of the first ball
    • (v_2): Initial velocity of the second ball (0 since it's at rest)
    • (v_1') & (v_2'): Final velocities of the balls
  2. Conservation of Kinetic Energy (simplified for elastic collisions): [ v_1 + v_1' = v_2 + v_2' ]

Solution Steps

Step 1: Apply Conservation of Momentum

  • Initial condition: (m_1 = 4), (v_1 = 5), (m_2 = 2), (v_2 = 0)
  • Momentum equation: [ 4 \times 5 = 4v_1' + 2v_2' ]
  • Simplifies to: [ 20 = 4v_1' + 2v_2' ]

Step 2: Apply Conservation of Kinetic Energy

  • Energy equation: [ 5 = -v_1' + v_2' ]

Step 3: Solve the System of Equations

  • Combine momentum and energy equations:
    • (4v_1' + 2v_2' = 20)
    • (-v_1' + v_2' = 5)
  • Use elimination method:
    • Multiply second equation by 4: (-4v_1' + 4v_2' = 20)
    • Add to first equation to solve for (v_2'): (6v_2' = 40)
    • (v_2' = 6.67) m/s
  • Solve for (v_1'):
    • Substitute (v_2') back into energy equation
    • (v_1' = 6.67 - 5 = 1.67) m/s

Verification

Check Momentum Conservation

  • Initial momentum: (4 \cdot 5 = 20)
  • Final momentum: (4 \cdot 1.67 + 2 \cdot 6.67 = 20.02)
  • Approximation confirms momentum conservation.

Check Kinetic Energy Conservation

  • Initial kinetic energy: (\frac{1}{2} \cdot 4 \cdot 5^2 = 50)
  • Final kinetic energy: (\frac{1}{2} \cdot 4 \cdot 1.67^2 + \frac{1}{2} \cdot 2 \cdot 6.67^2 = 50.06)
  • Approximation confirms kinetic energy conservation.

Conclusion

  • Final Velocities:
    • (v_1' = 1.67) m/s
    • (v_2' = 6.67) m/s
  • Both momentum and kinetic energy are conserved, verifying the correctness of the solution.