Do subscribe to Ekeeda Channel and press bill icon to get updates about latest engineering HSC and iit jee main and advanced videos new chapter 2 Hinged parabolic arches introduction and concepts Hello friends today we are studying a niche after his name as to hinge artists why we are setting to hinge artists because in structural analysis true we will still with indeterminate structure the indeterminate structure is nothing but the structure which is not analyzed by the condition of equilibrium is known as indeterminate structure so let's see in details to hinge arches now see to hinge parabolic artists today we are seeing 2-inch parabola causes introduction and their concepts now see the hatches will be look like this arches will be looked like this as we are seeing or tuning charges so this is your first change and this one is your second hinge in previous in Si one will these with the three hinge axes because there we are studying patronym structure here we are studying in determine structure now see how we will get indeterminate structure see in fixed in sorry in hinge we have two reaction and in hinge also we have two reaction means number of reaction will be four and condition of equilibrium will be three so it is an indeterminate structure now as this distance is nothing but this is your total health means span and this is your riser this is rice H and this is Point C is nothing but crown of the arches now as you all know in this type we have two reactions this see first one will be this is your a part this is B part and this is your C part now see first we have here VA and it is always inverse as you are laws in arches we will deals with H is always in word then VB then HB YH is always in words because if it is a asked if you are applying the load from upward the arch will be your eyes will be at Point a and joint B will open the arch toe to resist this will not open the eyes we will using the resistance forces nothing but H a and a cheapy so remember carefully in Carthage we always assume H is always invert okay now after that equal section over here a one section over here at X X at a distance X from a this distance is X at a distance X from a this is X and this distance is nothing but Y this distance is your wife now now the the actual bending moment at section is given by the actual bending moment at section is given by means here we are taking section bending moment at X will be M minus H a in to Y M is nothing but moment minus H into y where m is nothing but B moment and this is your minus H moment me moment minus H moment okay now in the in acid were two in two hinge arches we are using one formula to find H in Si one indeterminate structure we directly apply bending moment at C and we can find this form and the value of H but in this one in this one we have used one formula of H this formula will be we can use the formula of H the formula will be H is equal to integration of my DX upon integration of Y squared DX this is an important formula in this chapter you can remember to find H okay so remember this formula carefully and Y is nothing but as you all lost for H upon L square into L X minus X square is nothing a parabolic equation sugarcane okay now not equally tight one note for any problem H is equal to integration of Mo Y DX upon integration of Y square DX now now keep remember one things just simply you can remember in two in georgia's you have to remember one formula to find H we can use formula integration of my DX upon integration of Y square DX that's a and Y is equal to 4 H upon L square into L X minus X square you can remember this two formula we have done with this chapter okay so now after that to find H when we are finding we are using this formula there are certain cases that we can check whether our answer will it correct or not so let's see what are these cases now let's see this is a case one in case one what the case one says to us to hinge artists artists of span L mater rice h mater carries a concentrated load of w at the crown means we are using this as a you this is our for this is our sums if you dl if sorry if point load is at the center the blue and the distance will be L by 2 this is Elbert total distance will be L this is your edge this is first in this is second inch to check whether the our s will be but please remember carefully while finding in exam you and we are finding edge always use the formula s is equal to integration of my DX upon integration of v square DX okay don't directly use this formula H is equal to 25 point 122 WL but is just for the check for okay when you have pictures whether your answer is correct or not at that time you have to use this formula on D no need to use direct formula if you are using the remember you lose one to two marks okay now this is the first case when we have pointed at saying that the formula of H will be 25 upon 128 into WL by 2 now let's move to the next another case a two inch parabolic arch of span L and rise edge carries a Judea of W kilonewton per meter on left half of this one means UDL is left half of this span in the arches means like this so it's formula will be H is equal to WL square upon 16 H so now let's move on to case three now case three is what says to us a to hinge parabolic arches off span L rise H carries a hue dl of w kilonewton per meter on the entire span the entire span w kilonewton per meter square see if he UDL over the entire span h formula will be WL square upon 8h now let's move on to third fourth case I do it's parabolic as of the span L rise as Kerris UDL of W kilonewton per meter and a distance of from left hand side of a from left hand side means we have certain distance at a in UDL so our formula will be H is equal to W a square upon 16 H raise to 3 into 5 L raised to 3 minus 5 L square plus 2 a raise to 3 this is a formula so if you don't remember this formula it's not necessary to remember the formula because you are finding by the formulas H is equal to Y square of sorry integration of my DM by DX upon integration of Y square DX so no need to remember these formulas only for check these three formulas you can remember this one true and this one is 3 there are such many more cases to remember this problem but with exam we can't remember this whole formula so that's why we use the direct integration formula H is equal to Y squared integration of my upon integration of Y squared DX ok so remember this two three cases only I hope you understand this video share with your friends and yes don't forget to subscribe to our channel thank you you