[Music] asalamu for for for cerent sources fore forence one spe fore for for for 1 s for l for for [Music] for line for Central bright d formula for k do onard door d difference Fring difference fore unar for with for for fin a sin theta equals to n Lambda a sin theta equals n lamb L 2 into Lambda / 2 L foral 2 + 1 Lal AET = to 2 N minus 1 2 N minus 1 into Lambda / 2 1 2 3 Val 2 into 1 l 2us 1 lus 1 2 3 4 5 n into Lambda d ided a x equal L lambid A2 A2 2 L 2 divid a lamb d by a second L 3 into lamb d by a minus 2 into lamb d by a so 3us L Del Del exct Lambda d for different different for 1 mm 1 mm inverse 3 m 1 1M 1.5 1.5 8.83 58 9 angstrom 589 into 10 inverse 10 m l l into 10 inverse 10 capital D value capital D value 1.5 a value 59 10 powerus 10.5 10 powerus 3 powerus 3 .835 into 10us 4 8835 into 10 inverse 4 for already 3 1 lamb Val 589 10 inverse 10 so so Lambda value 58 9 into inverse so Central [Music] Bri 8835 mm value 8835 mm 88835 into 10 inverse n = to n into Lambda into D ID a xn n into L by mply with and by dividing Lambda and Diving X 8835 into 10^ minus 3 Lambda which is 5890 into 10 inverse 10 d d Val small n Val 1 10^ minus 3 * 8835 10 the power- 3 8. 835 10 the^ minus 3 divided by 58 90 10 inverse 10 divided 1.5 n value small 10 for for unless and L 5896 5896 angstrom 5896 angstrom 58 96 10 inverse 10 m 2 mm for into Lambda by a which is 5896 into 10 inverse 10 capital D capital D value oneus 3 596 10 inverse minus 10 and 2 10us 2948 into 10 the^ minus 3 2948 into 10 to the power minus 3 2948 10 minus 3 something Lambda value 5 8 96 into 10 inverse 10 m 2 into 10 to the power minus 3 met D value 1 met D value 1 met for lambid 2 a Lambda 96 into 10 inverse 10 capital D value one 2 into 10us 58 96 into 10 inverse 10 D primee oh sorry 1 into 10 power minus 3 2 into 10 power minus 3 2 96 10 inverse minus 10 div 4 10^ minus 3 2 into 2 4 10 powerus 3474 into 10 powerus 4 1. 1474 into 10 the power - 4 met 596 10us 10 2 into 1 so 2 divided by A2 or A2 divided so 2 into 10^ minus 3 5896 into 10^ 4 58 5 sorry 58 96 58 96 5. 896 into 10 the power minus 4 m474 5896 5 5896 1. 474 10 powerus 4 4422 betus 4422 4.4 22 10 inverse 4 m deep thinking next 10 the power minus 3 met 1 met that's easy 6000 lamb 6 6000 into 10 inverse 10 6 into 10 inverse 7 m 6000 6 into 10 Cub 10us 10 so - 10 + 3 will be Min - 7 so 6 into 10 inverse 7 met Delta X Lambda D ID 2 a lamb 2 10^ minus 3 okay value 6 10 to the power minus 7 10 to the power minus 7 divided by 2 10 power minus 3 3 into 10 powerus 4 M 10 powerus 4 okay easy for minus 3 meter r d value 1 meter Lambda value 6 into 10 to the power D value 1 M Lambda value 6 into 10 to the power minus 7 l for for for 1al 1al 3al for maximed thet maximum value thet maximum value one sin thet maximum value one inverse one or approximately 90° Theta is equals to n Lambda sin Theta value Maxim into Oneal n Lambda Max L l for for [Music] foral Zar n equals to 1ar n equals to to 0al 1 Nal to 2 Nal 0 Nal to 1al to 2 for dka for okay Max okay which is frequency F value 10 to the power 16 S1 S2 S1 S2 1M 1 mm 10us 3.33 value 133 1 l 2us 1 2+ into lamb d Cal to F Lambda V equal to F Lambda which is into 10c into 10 the sorry 10 power 8 10 the power 16 divide 10 the power 16 divide into 108 l 2 LDA into Delta X Delta 2 L and 2 lamb 2 Del p lamb 2 Del for for a for Value Lambda Lambda small small l divid a n value n value Lal 10 the power minus 3 10 power minus 8us 3us 8 + 3 will beus 3 into 3 9 into - 8 + 3 10 to the power minus 5 okay okay l bet Lambda d by 2 8 3 into 10^ minus 8 mu W chapter six chapter [Music] 133 Val mu mu W mu Lambda Aid Lambda w 13 mu W ID mu a equals to Lambda a ID lamb l l lamb lamb W value mu divided mu W mu ided mu W lamb one mu 133 into 10 powerus 8 correct 3 10 the power minus 8 ID 1.33 22556 3 into 10^ minus 8 divided by 1.33 22556 but 2256 into 10 the^ minus 8 2256 into 10^ - 8 m for 2 capital capital Val S1 1M lamb 3 into 10 the power minus 8 mtip D value 1 S1 which is 1M 1us 3 Del x w Del X lamb Capital 2.25 6 into 10 ^ minus 8 multiply 1 / 2 into 10^ - 3 Cate divided 2 10 the^ minus 3 1.5 into 10 to the power uh 3 10 to the 3 10 the^ minus 8 divided 2 10 powerus 3 1.5 into 10^ minus 5 1.5 10 the powerus 5 simly 2256 8 2 into 10us 3 1.1 28 10 to the power minus 5 1.128 into 10 power d d Delta X of air minus Delta X of water 1.5 10 to the power minus 5 answer minus 3.72 into 10 the power minus 6 3.72 10 to the powerus 6 me 3.72 10 powerus 6 second paper chapter six second chapter 58 90 angstrom 589 into 10 inverse 10 met 1.5 1. a equals to n inverse Lambda 5 890 into 10 ^ minus 10 divided by a a value 1 which is 10us 3 589 10 powerus 10id 10 powerus 3E answer 0. 03374 0. 0.0 3374 finally last de okay LDA P Lambda value 58 90 into 10 to the power minus 10 Val 1.5 1.5 1.5 small equal x Lambda Lambda value 5890 into 10 inverse 10 capital D capital D value 1.5 divid a a value 10 the power minus 3 Sol 5890 10 the power minus 10 * 1.5 by 10 and 10us 3 8.35 10 to the power minus 3 result 8835 into .538 15 Formula 2 n + 1 into Lambda d ID 2 a 2 minus one lamb D ID 2 X5 X 8835 into 10^ minus 10 2 into small 2 into 15 + 1 2 into 15 + 1 L capital same Val 1.5 2 into 10 power minus 3 2 a a11 div 31 1.5 8835 835 10us 10 3. 10 power minus 7 8835 into sorry 8835 10 the power minus 3 8.8 35 10 the^ minus 3 3.us Lambda Prim 3.8 into 10 the^ minus 7 met 3.8 into 10^ - 7 m 3.8 into 10 the power - 7 m onar Okay so for 2 mm 2 mm 2 into 10 the power minus 3 meter 59 L lamb 59 Ang 590 10 inverse 10 m or Square so minus 10 + 2 59 into 10 powerus 8 [Music] X 1.5 1.5 into the power minus 6 Lambda Val Lambda value 59 into 10^ minus 8 into capital D Val one divided a value 2 into 10 the power minus 3 59 10 the^ minus 8 um divided 2 10^ minus 3 2.95 10 power minus 4 2.95 10 the power minus 4 M that's it just lamb value lamb value already lamb value Lambda = 59 into 10^ - 8 m 59 into 10^ 8 1.5 1.5 into 10 inverse 6 for equals 2 by Lambda into 2 pi divided by Lambda value 59 10 the power minus 8 multiplied by DX DX value 1.5 into 10 inverse 6 1.5 10 inverse 6 2 59 10us 8 div 5.8 5. 5.8 approximately 5.8 so 5.1 and 5.1 is basically 5 for okay 1 mm 10us 350 ,000 angstrom 6,000 angstrom 6,000 into 10 inverse 10 and further 6 into 10 inverse 7 Lambda d a Lambda d a 150 10 the powerus 2 a Val 10 the powerus 3 Bet value Cate 6 10 powerus 7 * 150 10 power - 2 ided 1 10 the^ minus 3 say 9 into 10 the power minus 4 9 into 10 the power minus 4 meter right math important 3 m capital D value 150 10 to the powerus 2 m Lambda Lambda 6 into 10 powerus 7 m is equal to um Lambda T Prime divided by a right l 6 into 10^ minus 7 D Prime Val d by 2 so 150 into 10 150 divided by 2 75 75 10 the^ minus 2 multiplied 6 10 the^ - 7 divided 1 10 the^ -3 4.5 into 10us 4.5 10 the powerus 4 me for into 10 inverse minus 2 Val 10 minus 10 the^ - 7 ultip by 150 10 ^ - 2 divided by 2 into 10 powerus 3 4.5 into 10us 4 M 4.5 into 10us Delta X is equals to bet that means okay okay number capital d d value met 4 into 10 inverse 4 value so 4 into 10 angstrom 62 angstrom 62 angr 620 into 10 inverse 10 m 62 into 10 the power minus 8 met 62 10 inverse 8 met for l 62 which is 1 2 into 4 into 10 inverse 4 Delta X for red 62 8 10 powerus 4 result 7.75 10 inverse 4 7.75 10 inverse 4 meter that's it okay [Music] for exactly correct for small N1 small N1 small N1 lamb lamb 62 into 10^ minus 8 for x equals to n Lambda D ID a 1 Lambda 1 is equal to N2 Lambda 2 N Lambda lamb Val N1 ID N2 multipli by Lambda one L which is 62 10 powerus 8 62 10^ minus 8 20 / by 30 62 10 the^ minus 8 4.1 3 3 3 3 333 10^ minus 7 Lambda 4 13333 4133 into 10 the power minus is less than the range of blue blue the range of blue a Lambda b or range of Lambda B blue Lambda range of blue of beun B Alo Bei for next Lambda lamb 520 angstrom 52 into 10 8 inverse 10 so 52 inverse 8 90 cm0 cm0 into 10 2m small a 0.4 mm normal 0.4 10^ minus 3 [Music] met s into Lambda ID 2 X7 Val 2 into 7 minus one 2 into 7us 1 Lambda Val Lambda Val 52 10^ minus 8 Val 90 CM 10 the powerus 2 2 into a Val 0.4 into 10^ 3 52 inverse 8 90 10 inverse 2 10 powerus 3 and 7.65 into 10us 3 7.65 into 10 ^ - 3 m okay 7.65 10^ minus 3 m i next into 10^ minus 2 D Val 90 10 the power minus 2 met r a value 0.4 10 the power minus Muer lamb divid Lambda Lambda 52 10 power minus 8 Lambda 52 10 power minus 8 me l 524 the power minus 8 divided 1.47 it 3.53 37 into 10 the^ minus 7 3537 into 10 Delta X for glycerin equals to Lambda d 2 lamb lamb d by 2us divided 2 into 844 2.8 10^ minus 3 3979 but 3.98 10 power minus 4 3.98 into 10 powerus 4 M next same process Lambda Lambda C lamb lamb mu for the kerosine 52 10 power minus divid by 1.44 lamb 52 10us 8 ID 1.44 3611 10 the power minus 7 36111 611 10 power- 7 me Del X for K which will be Lambda ker which is 90 10^ minus 2 divided by8 10^ minus 3 4.625 by 4.06 10 the^ minus 4 4 4.06 10 the power minus 4 met right 46 10 inverse 4.9 so Delta X and glycerin will not be equals to Delta X of C okay 5000 5 into 10 powerus 7 me1 mm small a 0.1 mm 0.1 10^ minus 3 capital D that will be 2 m so equals to x formul 10 into Lambda D ID a l which is 5 into 10 minus 7 D value 2 divided a value 0.1 01 10 powerus 3 50 10us 7ed by 2 divided by .1 10 the^ minus 01 1 by 10 1 by 01 01 10 bright light bright fr L already 5 into 10^ minus 7 me a 0.1 10 inverse 3 a 0.1 into 10 inverse 3 capital 0.1 10 inverse 3 capital D value 2 Nal to 10 a sin Theta is equals to L already sin inverse n Lambda ID a Lambda Val small n value 2 into lamb 2 sin Theta equal n Lambda sorry AAL n Lambda 2us 1 into Lambda 2 2us into Lambda 2 thet inverse n Lambda 2 into Lambda 2 and sin inverse 2 N minus 1 into Lambda ID right1 3 2.86 so 2. 865 degree 2865 degre 2 into 10 20us 1 so 19 19 * Lambda 5 10 inverse 7 uh divided by Twi a so divided by 2.2 10 the power inv 27225 27225 2723 thet primeus 2865 2. 865 minus 2723 0.142 de 0 142 S1 s S3 6333 angr lamb 6333 into 10^ minus 10 m 0.38 S1 0 38 10 powerus 3 m 0.019 mm so X 019 10^ minus 3 met kri for unocar door dur 2 minus one into Lambda D ID t L Lambda Val 6333 10 the power minus 10 D at which is one divided by divided by 2 multipli 38 10 the powerus 3 8 8.33 8.33 10 to the power minus 4 833 10 to the power minri for door d l divid a lamb Lambda value 6333 10 power minus 10 D value one divided byid a 3 10us three 4999 into 10^ minus 3 4999 is basically five 4999 into 10 to the power minus 3 inverse 4.99 5 into 10 the power minus 3 8.33 10 inverse 4 4.99 4.99 10us exactus 8.33 10 the^ minus 4 4157 10 the power minus 3 4.15 7 10 the power minus 3 final result final 4.9 3 8.33 inverse okay for Del formula Delta x n into Lambda D / a divid x x 0.38 M 0.38 0 38 10 the^ minus 3 XP 0.019 M 0.19 10 the power minus 3 mm divided by Lambda D Lambda value already which is 6333 633 . 0.3 10us 3ti 019 10^ minus 3 6333 10 the power minus 101 1 value 0.014 0.014 a val14 for ual Dora s for S3 S3 T S3 S3 e that's foric for frer frer fr e grating quri op right for Theta 2 n + 1 into Lambda by 2A I'm 2 1 into Lambda a b d con foric spe equals to n Lambda 2 N into Lambda / 2 Thal 2 + 1 into Lambda / 2 2us 1 into Lambda / 2 2 N minus 1 2 N minus one into Lambda / 2 both for for 1 C cus 2 met 1 cm 10 the power minus 2 met 6 6000 into 10 s into 10 power 5 6 into 10 Cub 10 S 10^ 5 capital N Val 6 into 10^ 5 D to the power 5 lamb Orange 6000 Ang Lambda 6,000 Ang 10 powerus 7 1.6 10 powerus 6000 lamb 5000r into 10 the power minus 7 5 into 10 the power - 7 meter okay value is equals to one for both small value D value 1 by 6 into 10 power 5 1 by 6 into 10 power 5 l L will be inverse small n small n value one multiplied by Lambda not Lambda not value 6 * 10 the^ minus 7 divided by d d value D value 1 by 6 into 10^ 5 D value 1 by 6 into [Music] 6 10 the power minus 6 10 the power 5 6 10 power 5 inverse or 6^ 5 6 10^ minus 7 multip 6^ 5 * 6 10 the power minus 2111 21 now would be inverse small n MTI Lambda g ided d Prime small lamb G which is 5 10us 7 divid by D Prime 1.6 10^ minus 6 directly Conant inverse 18209 18209 1821 de 18. 21° for 21.1 1821 definitely less 21.1 de okay okay next okay okay lamb 58 90 angstrom 589 into 10 the^ minus 10 + 1 10 the^ minus 9 meter 589 10us 9 met small Nal 10 for a sin Thal to 2 + 1 2 N minus 1 into Lambda 2al 2 + 1 into Lambda 2 into 2 + 1 Lambda divided 2 5 89 10 the^ minus 9 by 2 2 4 4 + 1 5 5 by 2 589 10^9 and div 10 8479 8.48 10 the power minus 6 met 8479 into 10 the power - 6 M plus okay Lambda value value P 589 10 to the power minus 9 Max maximum value Maxim Maxim a sin Theta equal n Lambda Lambda already Max 8479 10^ minus 6 a value 8 47 9 10 the power - 6 M Plus data L small 8479 10 the power - 6 ID 589 10 the powerus 9 result 1439 small n Val 1439 which is approximately 14 1439 14.4 14.4 approximately [Music] for next 04 mm 0 0 0 4 mim4 into 10 the power minus 3 met2 mm2 10 the power minus 3 6000 6000 6 into 10^ minus 7 met equals to small n Lambda small n value one Lambda D Val ID D sin inverse Lambda ID a + 6 10 ^ minus 7 divided by uh 004 10 ^ minus 3 plus2 10^ minus 3 1.4 sign inverse answer 14.4 775 14.4 775 degree or 14.4 it's fine 14.4 for Max 004 10 the power minus 3 met B val2 10 the power minus 3 meter Alo into 10 the power minus 7 meter Maxim 2 n + 1 into Lambda / 2 A + B sin Theta a b j Lambda A+ Bal to 2 n + 1 into Lambda / 2 2 + 1 Lambda into a l into a plus b 2 / Lambda 6 10^ minus 7 answer a plus B4 10^ minus 3 plus2 careful 10us 3 2 7id 2 3.5 small 3.5 small n Val 3.5 that means 3.5 completely for for for for for pointing Vector pointing for fore for for for frequency comp [Music] for for for for forc for fore for .46 into 10 to the power 15 meter 9.46 into 12 k foreign fore IAL I / 2 okay for angle foric fore fore for 6.27 12 k isolute for Facebook com Allah