let's move on to example so we have a resistor uh 2 Kil ohms resistor right okay so question is to determine the uh so voltage Uh current right so we need to find the current so okay so current so okay so problem provides with a voltage drop and the resistance right so okay so from these three components we can use this equations right V equal I * R right so okay so modify this one so IAL V over R right so okay so V equal 16 volt r equal 2,000 ohms right so okay equal 08 amp or 8 milliampere right it's easy right okay so another problem uh we have a motor we have a motor so right now the the the connection is to connected to outlet with a 120 volt and the current goes to current 5 amp goes through this motor right so okay so then so we have a voltage and the current so okay so with these two components we can find the power right so power equal V * I that's it right so okay so 120 * 5 so should be 600 but you need to be careful un need should be what right what what correct right okay so then okay another problem okay so uh we have a graph with VI relationship right VI relationship okay the voltage applied the voltage is 120 volt right so okay so 120 volt then the question is to determine the okay what the power in unit of what and the resistance right okay so then so generally in this case right now we have a relationship I and V right so okay so in this case I is 625 ampere right ampere right and ampere so then okay voltage is 120 ohm 120 volt so okay from this one we have two components right voltage and current so with these two components we can find the power right so power equal V * I right so okay combine together right so okay multiply together then we know that this is 75 watt right okay so we found the power so okay from voltage and current relationship we can find the uh resistance right okay so what is that we can use OMS right V equal I * R right so r = v over I right so 120 / by I = 6 to5 right correct uh right so should be should be 192 oh right it's easy right okay so another problem so okay so right now we have uh measure okay Power the outlet the the the power measurements right okay so then we electric the previous reading was uh 4650 kilow but now the current reading should be this guy right so okay so so here is five right so three 60 right CR meter is 5360 kilowatt hour right so okay so then okay we can you we can find from this readings we can find the current the the power uses is in this month right so okay so okay for the power usage should be uh okay 53 60 minus 4650 right so okay so they used 700 110 kilowatt hour right see energy was used right okay so then so the problem says the cost is 11 cents per kilow hour right so we can find here some electricity bill right so okay so in this case energy right so Bill cost should be energy times unit cost right unit cost C okay unit cost so okay 700 10 times unit cost is 11 cents right 11 cents so okay so in this case right seven uh okay so should be 7781 10 cents right $781 C correct all right all right okay let's move on to another problem okay we have two horsepower motor okay two horsepower motor then efficiency is 85% so how much is input to get to hor power modor output right okay so okay so we know this equation right hor hor power output divided by input equal efficiency right so in this case 75 or 75% right so output is given two horsepower right so two horsepower to hor so okay p inal p inal p out over 75 then okay right now the the unit of the output power is horsepower right we need to convert it to uh watt right so generally we know that one horsepower equal 746 what right okay so so the two two horsepower right so two times 2 * 746 so divide by7 five right so okay finally this one should be a 1989 wat so okay so to get two horsepower for motor so we need to input around 2 kilowatt Powers right so because over efficiency right okay so power input is 1980 89 so okay how much is current so current is we're going to use this equation P go v i right so right now unknown is I so I equal p over V so okay so 1989 divided by p v equal 20 220 so 220 right soal 9 almost 9 amp ampere right ampere okay okay let's move on to problem six okay so problem six so okay so we have this system right we have this system so but we have three Cascades right so first one is gear train second is generator third is transmission system right so okay so how can you find the uh uh overall efficiency see it's easy right see so then okay so in this case overall efficiency should be total equal efficiency one efficiency two efficiency three right so okay so so then problem gave us efficiency one efficiency two efficiency three right so okay 9 times 85 times then point 95 right so okay so we can find the total efficiency of the total system right so you can find the uh the efficiency correct okay so that's it if you have any question please let me know thanks