Chapter 8: Similarity
8.1 Similar Polygons
- Definition: Similar polygons have the same shape but different sizes.
- All corresponding angles are congruent.
- Corresponding sides are in proportion, not congruent.
Example with Triangles
- Given: Two triangles are similar.
- All corresponding angles are congruent.
- Sides are proportional.
- Example ratios from smaller to larger triangle:
- Smallest side: 3 : 6
- Medium side: 4 : 8
- Largest side: 5 : 10
- Observation: Ratios are equivalent (e.g., 3/6 = 1/2, 4/8 = 1/2, 5/10 = 1/2).
Writing Similarity Statements
- Notation: Similar symbol is like congruent symbol without the equal sign.
- Naming Example:
- Small triangle: ABC
- Large triangle: DEF
- Similarity statement: ΔABC ~ ΔDEF
- Ensure corresponding angles match: A with E, B with F, C with D.
Side Ratios
- Side ratio is the proportion between corresponding sides.
- Example: Side ratio is 1/2 (e.g., 3/6, 4/8, 5/10).
- Also known as similarity ratio or perimeter ratio.
- Scale factor tells how much larger one figure is compared to another.
Solving for Sides
- Ensure proper side matching using triangle naming.
- Proportion setup: X/17 = 10/14
- Solve using cross-multiplication:
- 14X = 170
- X = 170/14 = 85/7 or approximately 12.14
Additional Examples
Squares
- Side ratio: 2 : 3
- Area ratio: 2² : 3² = 4 : 9
- Pattern: Side ratio squared equals area ratio.
- To find side ratio from area ratio, take the square root.
Application with Figures
- Given two similar figures with side ratio 3 : 4:
- Incorrect setup: 3/4 = 20/X (wrong because sides and areas aren't directly proportional)
- Correct setup via area ratio: 9/16 = 20/X
- Solve proportion: 9X = 320, X = 320/9 = 35.5 square feet
Practice Example with Socks
- Given side ratio 4 : 5:
- Find area ratio: 4² : 5² = 16 : 25
- Setup proportion with areas: 16/25 = X/30
- Solve: X = 480/25 = 19.2 square feet
- Note: Ensure similar shapes are stated for correct ratio applications.
- Key Concepts: Similarity involves proportional reasoning, and ratios of sides are foundational to understanding similarity and area calculations.
End of Chapter 8.1. Next session will continue with further concepts.