Sep 28, 2024
2x - 7
x^2 + 3x - 5
2x^3 - 5x^2 + 7x - 3
5/(x - 2)
(3x - 8)/(x² - 9x + 20)
(x - 4)(x - 5) ≠ 0
(2x - 3)/(x² + 4)
√(x - 4)
√(x² + 3x - 28)
(x - 4)(x + 7) ≥ 0
√(x + 3)/(x² - 16)
(x + 4)(x - 4) > 0
√(x + 3)/(√(x² - 16))
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