always appreciate yesterday but work for a better tomorrow so hello my shimmering Stars today I shot a groomer welcome you all to this amazing platform of PW English I welcome you all students to your Nexus batch and today we are going to proceed with our lecture number third based upon the chapter classification of elements and periodic properties so I guess students we have already revised the previous session and you have solved the homework questions also so I was looking to your comment section and I feel so happy that you are attempting the homework questions that I have provided you no need to worry the solution for all the homework questions will be provided in the last lecture okay of this particular chapter and you can just cross check over there and then at that spot of time you have to write in the comment section that how many questions according to you were correct of yours right after matching mine okay after matching the answers from my end so students let us start with our today's session ma'am what are we going to cover today how are we going to proceed now with regard to the periodic table I guess you all have learned the periodic table with the help of Tricks so students my one recommendation is if you have any easy trick in order to learn periodic table you can write in the comment section so the students who feel that you know this trick is much better than the previous one they can remember that as well so it depends only on you okay you can create the trick on your own in order to remember the periodic table guys okay so now coming to my topic over here again we are now starting with lecture number third and what are going to be the targets for this particular session first of all let us discuss that so students first of all let me tell you that here we are going to do a nomenclature of the elements whose atomic number is more than 100. okay so we are going to name them particularly and then afterwards we're going to see the classification and the prediction of elements that they lie in which period they lie in which group they line which block so we are going to do the prediction with the help of some certain rules it's very easy but yes questions are asked you will observe the question pattern over here in the session also yeah so the third segment that we're going to start is is going to be ncrt in text question at the back questions see let me tell you about ncrt in-text questions uh why I have taken this and about back questions I will be considering those questions which are like we need to solve something the theory based questions you can automatically just answer by your own with the help of notes that I'm providing you right but there are some questions for example if I'll ask you just uh write the name for the atomic number 114th element okay so for that we are going to solve such kinds of questions or if there is any numerical kind of question we are going to solve that as well uh whether it is of ncrt in text or ncrt back exercise we will be following that but not the theory based because Theory based I know you can do by your own with the help of the notes that we are creating over here right so ncrt in text and back questions with regard to the topic still now we have covered we are going to do that and yes there will be some homework questions also in between in order to you you know in order to see whether you are understanding the concept or not and then is the question rounds as we used to do in each and every session of us that we some solve some kind of questions and then three questions as a homework right so now students let us proceed with the very first topic of us but let us meet your friends that is calcium and barium so say students High to calcium and barium so basically they are saying hello my shimmering stars have you revised yesterday's class if not students don't you know uh don't do this again don't repeat this thing again you need to revise it just keep it in mind without revision you are going to forget it at some instance of time you will forget whatever you have heard whatever you have learned if you're not it for once everybody feels like oh we are getting the topic we're able to understand it we will rock in the examination but for rocking in the examination you need to practice you need to revise again and again again and again then only you are going to succeed without revision you won't for one instance of time we feel like yes we are getting the topic but if you are doing the revision then only you will proceed then only it will retain in your mind so do remember this okay now here is Miriam so he's saying let's Get Ready for today's class yeah so so first topic is IUPAC nomenclature of elements whose atomic number is more than 100 students always remember whensoever we are doing IUPAC of these elements over here at the end we need to add em i u m e m so let us see the names are derived by using roots by using roots for three digits the atomic number of the elements okay and adding em at the end okay now the atomic numbers uh for the elements which have three digits in it for them we are going to name it and we have to add em at the end it's quite simple okay let me show you the very basic rule that you need to keep in your mind so this is the very basic rule that you have to observe it so the very first thing is I have written digit over here for example I have provided you with one zero one so these are digits 1 0 and 1. so when so ever you see one over there you have to write n over there okay onceivers you will see Zero over here you have to write nil over there once you are observing one again you have to write an and at the end of that you have to write em ium so by this way you're going to name it so let me tell you for which digit which word is uh which word you have to use okay so if you are using a digit 0 over here students if you're using digit 0 you have to write nil now the root is the word that you have to write is nil but when you are you know writing the symbol of that compound over here the symbol of that element you have to use the first initial letter that is n okay so you have to repeat after me I know that it may sound very weird that we have to repeat it you are not able you are not sitting in front of me but yes students if you'll follow my instructions let me tell you it will be very very easy for you uh about you know understanding in organic chemistry in order to understand it so 0 is nil and N is your symbol then comes one for one you have to use an u in and the symbol you will be using is the first initial letter that is you then comes two you have to use by B I buy okay over here and then the initial letter B will be the symbol that we have to use then comes three that is try t r i try and the initial uh letter is T that is the symbol that you are going to use over here then comes what then comes four that is what quad q u a d quad and you have to use Q as the symbol the initial letter then for the digit five you have to use Pent the symbol is going to be the initial letter P then comes a hex so you have to use the initial letter H then comes 7 for 7 you have to use sept and the initial letter will be S the symbol that you're going to use over here then comes OCT and for Oct that is eight digit you have to use o as the symbol and at last is digit uh sorry digit number nine for that you have to you have to use e double n now this is quite different so you can put a star so that you won't forget it again and again see why do we write stars or why do we underline certain things for example when we are having examination you open your notebooks If You observe a star or an underlying symbol or a something which is written from different pen your initial you know observation will go over there only you will feel oh this is something important first I have to read this that's why I've told you to put a star over here for nine digit you have to use e double n and the symbol you are going to use is small letter e now let us write one by one for all of them let us first write for 1 0 1 in order to make you more understand so one zero one it is going to be now for one it is UN for 0 it is nil for one again it is on and at last you have to write yum how you are going to represent it so for one it is u then for 0 it is n then again for one it is u to you and you by this way you have to represent it okay students so now comes the now comes the nomenclature over here let me correct the let me correct the heading over here it's by chance written as mint leaves periodic table so let me initially correct it everybody write down the names that you have just done with the help of digits over here in this column then I am going to write along with you yes start writing the names for one zero one one zero two one zero three all over here students yes everybody start writing it I guess everybody's writing for one zero one now only we have done it is on nil um yes everyone then for again one you have to write an for 0 you have to write nil for 2 what you have to write by C over here it is written by b i by we'll be writing by then comes em yes now comes for 1 0 3 so it is UN nil try em everybody write for 1 0 4 1 0 5 I'm waiting for two more minutes and then we are going to cross check whether you have written right or wrong yes everybody write it down okay let us see for one zero four it is going to be on nil quad now for four we use quad em and one more thing students please correct it over here here double I won't come only single I will come so it is by em yes shall we write for fifth one zero five everybody for fourth we use what quad q u a d let us go for now fifth one it is going to be an now for 0 it is nil for five it is what paint and then comes em yes match your answers with mine then comes one zero six so it is for one and for 0 it is nil for six what for six we are going to use hex 10 comes em okay for one zero seven what are we going to write u n n then comes nil for zero then comes sept for seven and then comes em yes everyone then for one zero eight it is for one it is again and four zero it is nil then for eight it comes out to be ok then comes em yes for one zero nine what it will be on nil e double n then comes e m c for nine number we have to use what ma'am for nine number we have to use a double e double n now let us write the symbol of there as well symbols for there as well C for one zero one this is the initial Words which I am underlining over here uh so that it is quite clear to you see it is going to be U and u then it will be u n b then it will be u n t then it will be u n q then it will be u n p then it will be u n h then it will be u n s then it will be u n o and it will be u n e yes everyone so these are the names which were further discovered and they were provided to it that was for one zero one in general it is Mindy William then 4102 it is nobelium then laurentium rutherfordium okay now one of the questions you will observe from this in ncrt in text as well then bohorium then comes hasmium uh then comes okay clear everyone so these are the nomenclatures still 109 in the similar way you have to do for one zero ten to one zero eighteen shall we start yes everybody giving you two more seconds everybody do on your own then we are going to match your answers with mine yes everyone shall I start now so for one zero one for one it is again on for one it is again on for zero it is nil then comes em then one one one so again for one it is on again for one it is an for again one it is now comes for 113th so it is going to be on Triumph then for 114 it is an accordion then for 115 it is going to be on and then paint em then for 116 it is going to be an on text Em then for 117 it is going to be on on sept em then for 118 it comes out to be on em everybody kindly write it down so that we can move on to the next part of ours everybody kindly write this down everybody kindly write all of these names down so that we can move on to the next part salvi students shall we okay now let us write the symbols of them so it is symbol is going to be o u n sorry u n not o u u n then it is u u u then it is u u b then it is u u t then it is u u q then it is u u p then it is u u h then it is u u s then it is u u o clear everyone so these are the symbols for them yes everyone so this was about the nomenclature now comes students the classification of elements as per as block P block d block F block I will come to this topic but before that first of all do the prediction part let us do the prediction part so how are you going to predict whether an element lies in the S block P block d block or which period or group does it lies okay so this is really very essential see for period it is very simple okay for period what you have to see the outermost shell outermost shell the electron enters into which outermost shell for example let us take an example of nitrogen nitrogen as an atomic number seven so it is going to be one is two s two P three yes that means what is the outermost shell over here second shell second shell is the so that means the N value over here comes out to be 2 that means this is your period so that means the period here comes out to be what 2. clear everyone in the similar way let us take few more examples let us consider magnesium magnesium is atomic number 12 so it is going to be 1 is 2. 2s2 2p6 how many electrons two plus two four four plus six is ten 3 is to 12. so here outermost shell is your third shell so n here is 3 that means period here comes out to be what it comes out to be p is it clear so by this way you can identify about period you can tell clearly about period now what about map block or what about the group let us first of all right here about block let us mention about block if you have to see for Block you have to see that last electrons enters into which sub shell very simple that is basically the block okay if last electron enters into it lies under s block quite easy quite simple if last electron enters into P sub shell so it is P block if last electron enters into T sub cell surface d block similarly into F so it is f log clear let us say is take these examples only here last electron enters into P sub shell so this is p block see right here last electrons enter into S Sub shell so it is s block clear students so this was about period and block what about group map what about group everybody first of all write this down then we are going to do for group as well then we shall be doing for group as well everybody write it down then we shall be doing for group as well everybody write in your copies yes I hope so everyone has written this very good you can pause the video and write it okay students now comes for group see if it is if it is s block element okay that means if last electron is entering into S Sub shell then what you have to do there in that case uh for group the total number of valence electrons what I'm saying is if you know that last electron enters into s subtial that means it lies in the P sorry s block so you have to see the total number of valence electrons let us consider the previous case only uh that this is the S block element right so here last electron enters into assumption so calculate total valence electrons now what are the total valence electrons the outermost shell electrons so over here the outermost electrons are two that means this is the group number here comes out to be what 2. got my point very good take one more example over here let us take one more example of sodium sodium basically is atomic number 11 so it is one is two two is two two P six three S one now see it lies in in the S block element right and how many valence electrons one valence electrons the group is first group because total number of valence electrons you have to see in s block case so it is group number is first right everyone now let us say for P block let us say for p block see in the case of P block what you have to do is very easy you have to calculate group as total valence electrons Plus 10. total valence electrons plus 10 let us take the previous case only over here in this previous case a case whether the total valence electron Automotive second shell it contains two plus three five five electrons now add 10 into it because it is p block once no so 15th is going to be the group number group comes out to be 15 group is it easy is it clear to each and every one of you yes everyone is it easy okay let us take more cases for example let us consider for oxygen let us take an example for oxygen oxygen has atomic number eight we are going to write to one is two two is two two P six now see 3 is to how many electrons sorry I went above uh not 3 S2 here it will be 2 plus 2 4 and 4 plus 4 will be 4 plus 4 will be eight so it is 2 is to 2 p 4 right it is 2 ways to 2 p 4 this is the outermost shell now it is p block element because last electron enters into P1 so total valence electrons that is two plus fours six you will say by y naught four why are you adding this 2 because second shell is the outermost shell no so outermost shell is the valence cell second shall contain two electrons of acid four of P so six plus 10 that means 16th group this belongs to which 16th group clear let us take few more examples let us take an example of carbon atomic number six so this comes out to be one is two two s two two P two yes so now how many electrons in the outermost shell four so four plus ten this comes out to be 14th group clear everyone so this was about P block let us talk about not d about the D ones that means when electron enters into last electron enters into d sub shell for that case group number is equivalent to number of total NS electrons plus total n minus 1 D electron okay so by this way you can uh you know find out the answer let us take the case of chromium whose atomic number is 24. what is the atomic number of chromium students 24 so you have to write the electronic configuration what will be the electronic configuration if you have to write for chromium yes what will be the electronic configuration it's very easy it's very easy students it is going to be 4 is to td4 or 3d5 this was assumed to be electronic configuration I guess you all have done this this you have assumed to be electronic configuration but it was not the configuration was 4s1 3d5 4s1 3d5 yeah so over here now observe now observe total NS electrons n value is 4 n minus 1 4 minus 1 is 3 so this is 3D electrons this is NS electron so NS electrons is one plus n minus 1 D electrons that means 3D electron is five so this comes out to be what sixth that means it belongs to which group it belongs to sixth group clear everyone this was assumed to be electronic configuration but there was an exception electronic configuration outermost electronic configuration came out to be 4 respond three D5 we are not outermost shell it is referred to as it is referred as total NS electrons plus total n minus 1 D electrons okay now one question has a homework calculate for atomic number 29 and 13. the group in the chart section tell me their group their block their period so this is question number first clear as a homework everybody write it down so that we can move on to the next part of the ours everybody please write this down so that now we can move on to the next topic of ours so students let me give you one more question as a homework that is question number two calculate the same period block everything for Fe and for Scandium okay this is question number second question first holds A and B part question second also holds A and B part these are two your homework questions which I have provided you over here only two homework questions everybody containing two two part each clear now students let us start about the classification of elements and the S block elements that we've already discussed in the previous class though but now we will be doing this in detail the S block elements contains two groups that is group number one and group number two group number one and group number two group number one contains your alkali metals and group number two contains your alkaline earth metals okay let us talk about the you know elements of this so these are the elements of group number first if I'll ask you the electronic configuration of all of them it is going to be one is one it is going to be outermost two S1 it is going to be 3s1 it is going to be 4 S1 it is going to be 5s1 it is going to be 6 is 1 and then 7 is 1. these are the outermost electronic shell configuration so if I'll ask you the electro automotional electronic configuration it comes out to be ns1 for which case for group number one similarly for this one okay if I'll talk about this one over here okay then you can see the electronic configuration is going to be what over here again if you are going to start with it is I am saying only outermost shell electronic configuration okay so this is again outermost shell electronic configuration which is basically ns2 so the general electronic configuration for S block elements if I'll talk about it is going to be ns122 this is the outermost configuration for this right and here n value n value indicates about period to which period does it belongs or the number of shell does it have for example let us talk about the case of hydrogen hydrogen this is the nucleus this is the first Shell First shell contains one electron now for lithium uh it is written 2s that means it is partial and then the second shell and second shell contains one electron now for the case of sodium this is your nucleus this is your first shell your sequential and then your third shell and third shell contains one electron so by this way you can clearly observe it right now let us talk about its Trend see basically it creates plus one and plus two ions over here okay that means if I'll talk about group number one it will be like lithium plus one n a plus one a k positive in order to attain the uh stable electronic configuration and they will obtain plus two electronic State plus two ions over here because they will lose two electrons then they will become more stable that means CA plus 2 mg plus two so they hold plus two charge they hold plus one charge next thing is metallic character metallic character increases down the group metallic character increases down the group that means when you are moving from Top towards bottom you will see that metallic character will increase okay moreover s block elements lie at left hand side of periodic table they contains Metals over there moreover as you can see metallic character increases down the group though I've already told you over here yes students and here the last electron enters into S Sub shell they have students high melting and boiling point as well and they are soft in nature if you want to write down and their size is also more size is also large everybody write down this about s block elements so that now I can start with about the next block that is the P block elements let us see the next one now I guess everybody has written this now starts with p block elements so last electron enters into P sub shell okay let us talk about the P block elements they lie from group number 13th to group number 18th yes group number 13th is boron family then is carbon family group number 14 then is nitrogen family group number 15 then is group number 16 oxygen family then comes group number 17 the halogen family and group number 18 the inertic acids yes moreover non metallic character non-metallic character increases when we move from left to right in a period left to right in a period that means you are moving in this direction so non-metallic character will increase that means the pre-block ones will contain more non-metals the P block one contains metals contains metals non-metals and metalloids all of these three but yes non-metallic character will increase from left to right again metallic character increases down the group this was about P block elements let us discuss about the D Block elements now let us everybody discuss about the D Block elements see if I'll talk about the Gaze of d block elements last electron will enter will enter into d sub shell into T sub shell a d orbital you can even mention it over here now the next thing that you need to know over here in D Block elements the block elements do contain you know uh the elements uh from where you can observe that in the sixth period and the seventh period there are two blocks which are kept separate the lanthanoids and the actinoid series which comes under the F block ones so here you can mention F block ones contain two kinds of series that is the lanthanoid one and the actinoid ones which are just present which are just present beneath the D Block one they are present at the center of the periodic table they are also called transition elements they are basically the colored compounds though there is an exception there are Exceptions there are exception students exception is the basically group number 12. exception is group number 12 over there okay they are colored complex okay they are they do form salt so this is about the D Block if I'll talk about the F block let me tell you here last electron will enter into D substitutional in other words you can say it will enter into the penultimate cell penultimate cell why because we never write D we always write n minus 1 D like this that's why and over here in F block when you will write you'll write n minus 2f so this is NT penultimate shell it is NT penultimate shell about F block one about F block one in F block last electron will enter into F sub shell quite clear everybody everybody kindly write it down everybody I guess everybody has written this now this I have written all together let us talk about now metals and non-metals with the help of ncrt highlight only what ncrt says whatsoever we have started we will read it so according to ncrt metal comprises more than 78 percent of all non-elements uh and often all non this is not the you know another non-metallic one I'm saying all the non-elements that we know and basically they are present on the left hand side of the periodic table that means the S block elements if we'll talk about Metals okay metals are usually solid at room temperature very important thing very important thing metals are usually solid at room temperature but yes there is an exception which is mercury is an exception over here and gallium and cesium also have very low melting points though I I've already told you when I was writing in s block elements that they do have high melting and boiling point but yes there are more exceptions such as gallium and cesium they have very low melting point over there so this is also an exception so see ncrt highlight with regard to metals non-metals and metalloids are really very important so I have written over here everybody please kindly Mark in your ncrt these important key points metal comprises 78 percent of which they are present on the left hand side and yes Metals basically if I'll talk over here about the melting point and high boiling point they are high but exception is in gallium and cesium moreover uh they are solid at room temperature but Mercury is an exception next metals have high melting boiling point already told you they are good conductors of heat and electricity they are malleable and they are ductile that means they can be hammered Into Thin sheets and thin wires respectively yes everyone malleability and ductility you have studied in your class 10 standard as well so this was about the metals as per ncrt let us read about non-metals again this is yet important ncrt highlight so non-metals are located at the top okay they are located at the top right hand side of the periodic table that means the P block elements right if you'll see this is your let me show you it over here only if this is your periodic table students these are your metals and these are your non-metals that you can clearly see the ones that are present on the right hand side they have mentioned it over here metals are this one these are your non-metals okay and other one they have shown you the transition elements that are the D Block elements okay let us come back to this topic non-metals are located at the top right hand side of the periodic table in fact a horizontal Row the property of element changes from metallic on the left to non-metallic on the right I already told you already told you that non-metallic character that non-metallic character increases when you move from left to right when you move from left to right so the non-metallic character will increase over there non-metals are usually solids or gaseous at room temperature metals were solid but yes they are solid or gaseous at room temperature and they do have low melting in boiling point but yes Boron and carbon have high melting and boiling point so this is again an exception do you remember in the previous case Mercury gallium cesium three exceptions Mercury had of the state and the melting point case was for gallium cesium over here again melting point case is for Boron and carbon which have high melting and boiling point though you know the non-metals do have low okay so they are poor conductor of heat and electricity most non-metallic solids are brittle and they are neither malleable nor ductile clear everyone now students let us see about the third one that are metalloids let us start with them now the elements become more metallic as as we go down a group I've already told you metallic character it will increase down the group so the non-metallic character increases as one goes from left to right across the period but from top to bottom metallic Rector will increase right the change from metallic to non-metallic characters not abrupt as shown by the thick zigzag line okay the elements now they have told you which elements silicon germanium Arsenic anti-money and tellurium even polonium okay bordering this line and running diagonally across the periodic table shows the property that they are characteristic both metals and non-metals they contain both of the characteristics of metals and non-metals that's why they are referred to as metalloids so what are they called when these elements are called semi metals or metalloids clear everyone kindly mention this in your ncrt my dear students clear everyone that's great now students comes the very first ncrt in-text question let us start this okay now comes what would be the IUPAC name and the symbol for the element with atomic number 120. see I've already told you students will be doing the topics now let me tell you I am not you know uh taking uh topics in a larger amount why because now only you have started your class 11th until now until class 10th you were at a space where you need you used to learn things but now you are at a space where you have to understand things right so I am going to create a habit of yours of you know understanding topic very few topic then and a bit more than a bit more than a bit more similar way if you have observed in the first lecture we have done very few questions then in second lecture more questions now in third lecture more questions will come in next more questions will come so buy one by one step by step I am going to create your habit not at a certain I will provide you so many questions you will be like oh my God ma'am this is so hectic this is so we are feeling so stressed out no not at all you will feel chemistry when you are going to study you have to feel chemistry you have to understand chemistry that's it so now one by one topic by Topic in detail I am explaining you with ncrt highlights so that you will be able to understand each and everything properly let us see the ncert in text question that means the questions that are provided topic to topic if you're going to read ncrt so problem 3.1 is that one what would be the IUPAC name and symbol for the element with atomic number 120. so if you know for one you use an for two you use buy and for 0 you use nil and at the end you have to use em so how you're going to do it is UN plus y plus nil plus e m so it is going to be n by nilium what will be the symbol u b n u b n easy easy okay shall we move on to the next question everybody has written this very good now comes the next question now now students one homework question this is third question as your homework two questions I've already given you see one normal teacher question of ncert index we have done now next is for you the elements with atomic number 117 and 120 have not been yet discovered okay in which family group would you place these elements and also give the electronic configuration in each case very interesting question the prediction question the electronic configuration question the nomenclature question all questions in a certain question yeah so this is question number third is the homework you have to write the answer in the comment section no need to worry we will be discussing each and every homework question at the last lecture of the chapter now many of you may think that when we are going to discuss we'll solve it that's part of time don't do that thing students do the things which I say you directly if I say you read it right now read it right now if I'm saying solve it right now solve it right now because your aim is not very small you have if you have you know Dreamed a very big dream and you think that yes you have to achieve something in life students but that you need to do hard work and now only you've started studying class 11th it's initial start so from if you are you know very confident from the start if you are doing hard work from the start it won't create a mess up at the end okay it will be very sorted but if you are skipping the things over here now it will you know affect you at the end of this uh you know uh the examination when examination would be approaching so this is question number third as a homework let us read the next question problem number three point four oh my God now yet again the most interesting one so this is again as a homework why because I have already told you the trend I will write the trend over here but answer you have to tell me so this is question number four as a homework problem 3.4 considering the atomic number and the position in the periodic table arrange the following elements in the increasing order of metallic character so metallic character is quite easy no metallic character see metallic character if you will see down the group down the group it is going to increase and across a period metallic character will decrease non-metallic character will increase non-metallic character from left to right is increasing but metallic from left to right is decreasing so now arrange them and write the order in the comment section this is a question number fourth as a homework everybody write it down I'm getting a side so that you can write it down and we can move on to the next question of ours shall we students everybody written this this is again your ncrt in text question I am here talking about okay let us see the next one now next comes the your ncrt back exercise now 3.1 and 3.2 question of theoretical questions so no need to solve it out you can read it it's very easy you can see the answer in the notes 3.3 question is what is the basic difference in approach between mendeleev's periodic law and the modern periodic law so students when the leaves periodic law you know basically it put emphasis on the thing that physical and chemical properties physical and chemical properties of elements are a periodic function of atomic mass atomic mass that means when you are going to arrange elements you are going to arrange in order of increasing atomic mass but modern periodic law faced emphasis on atomic number not atomic mass so this is the huge difference that you are going to observe let us see the next question next is 3.5 question in terms of period and group where would you locate the element with Z is equals to 14. yes Sirens where you are going to locate the element 114 so you very well know the answer because yes we have done the periodic table now only we have done the production section so this is question number five as your homework see I want you all to practice as many as questions as you can see I I will if I will be solving questions over here but until and unless you won't be able to do it you won't you won't you know try to solve it you won't get it more the questions you practice more the concept becomes clearer right this question number five next write the atomic number of the element present in the third period and the seventh group sorry 17th group of the periodic table 17th group so what are 17th group elements if you remember yes anybody so this lies under second period this lie on the third period the slide and the fourth and the Sun the fifth so third period 17th group is chlorine chlorine is your element so if you don't know the atomic number what you have to do you have to add eighteen eight into it you will get the atomic number that is 17 the magic numbers the atomic number is 17. clear 8 18 18 32 yes okay students moving on to the next question this was 3.6 now comes 3.7 which element do you think would have been named by Lawrence Berkeley laboratory and C boards group now see now see I will show you these elements you will get your answer um in the periodic table let me show you see really sorry students see over here see borgium to see borgium basically has an atomic number one zero six this we have already done in this similar way in the similar way you have to tell about the another one see Lawrence solarentium one zero three one zero three and one zero six so one zero three and one zero six clear easy question so this was 3.7 question now students here are few more tricks of the period number six and period number seven so I've told you to create your own trick but yes I have brought for you people as well so period number six starts from the element 57 and it ends it's 80. but over here there is a very you know simple basic difference that after 57th element you will be seeing 72 element because in between elements are your lanthanoid Series right from 58 to 71 they are the F block elements so not placed over here 57th is uh lanthiram then 72 is half nium then is tantalum tungsten rhenium osmium iridium platinum gold and Mercury so what is the trick in order to remember them that is Lady Lady for lanthanum have fun for HF then is for traveling it is T A tantalum then for world it is tungsten see tungsten is starts from T but yes the symbol is W so world is tungsten then and is an extra word underlining it rhenium is the reach re from osmium I am written out for IR I've written India and then for PT I've written please a you have written ask now don't consider that it is gold so you have to start with G you know I am representing symbol and then her it is mercury now Mercury starts with them but the symbol is actually so the trick is lady have fun traveling and reach out India please ask her okay so this is for uh the period number six now comes for period number seventh so it is basically again the same Trend after 89 you shall be observing elements in the uh your another series that is ectinoid series and then comes one zero four so we have actinium radophonium now only we have done sg1061 right and then comes bohorium hasium material okay then these are the elements these are more than uh you know 100 ones so more than 100 ones we have already done the nomenclature right guys so basically it is act really Dynamic so the best has met this is going to be the trick for this period clear everyone act really Dynamic so the best has met clear so these tricks I have already told you now I don't know whether you have done the homework question or not create a trick for lanthanoids and actinoids when we are going to study about lancinoids and actinoids in detail I will be telling you their tricks so you have to create a trick for this as well this is question number six as a Hoover creating trick for lanthanoids and actinides so now calcium says hi barium let's practice some questions and barium says yes I'm ready are you ready my shimmering Stars okay so here comes the very first question of us the third alkaline earth metal iron contains number of electrons and protons as now alkaline earth metals basically refers to your group number second ma'am now what were the elements so this is the third member that is calcium that is what is calcium calcium has an atomic number of 20 so calcium is atomic number 20 but I have told you that it creates plus two charge on it like this so 20 is z that means it is number of protons but how how much will be electrons 20 if it is written plus two you have to minus two if it is written minus two then you have to add it so this comes out to be 18 electrons so 20 protons and 18 electrons that means option number c is going to be the correct answer for this particular question clear everyone write down the answer so that I can move on to the next question of yours everybody done okay next question is a metal having electronic configuration is in which block so in order to see the block you need to see that to which basically last electron enters so obviously just see over here it is going to be first of all 4S to 3D 10. last electron enters into d sub shell not in s don't get confused when you're doing the electronic configuration when you are writing the electronic configuration first of all you will write 4 is 2 then it will be 3D 10 which is basically zinc this is basically zinc and it lies under d block elements so answer is going to be option number B if you are getting confused write down the electronic configuration the atomic number for zinc as 30 and then start writing it it will be 3D it will be 4 is to 3D 10 so last electron enters into D subshell students clear let us see the next question now the element having atomic number 33 lies in the group element with atomic number 33 lies under which group so nitrogen is an atomic number seven you will add eight you will get sorry 15 then you will add 18 you will get what 33 so arsenic is the one which has an atomic number 33. you will say mom how do you know it lies at nitrogen families this is done by practice if you practice more and more questions you'll get the answer or what you can do is write the electronic configuration if you don't want to write like this write the electronic configuration you will get your answer so it is basically arsenic to which group it lies it lies under the 15 group nitrogen is 15th group so answer comes out to be option number c clear everyone everybody please write it down so that we can move on to the next question of ours yes students done okay now comes the next question what will be the IUPAC name of the element having Z is equals to one zero six see for one it is an for 0 it is nil for six it is hex and at last you have to write em it is going to be Anil hexium let us check it is quadmium 104 heptiam not possible see an unhexium not possible it is 116 but it is one zero six so B option is going to be the right answer for this particular case clear everyone shall I move on to the next questions students okay let us see the next question an element has electronic configuration this predict the period group and the block see now last electron enters into P so the block is p block block is p block P block these two are wrong now next part is predict the group and the period see n value is 3 period is third period is third period of the third now let us see the group how are you going to see the group last electron enters into the P1 so in the case of P how do you go for it in the case of P total valence electrons is 2 plus 4 6 6 plus 10 is 16. so answer comes out to be a option group number is 16. answer comes out to be a option clear everyone shall I move on to the next question next question is an element with atomic number 36 belongs to dash Block in the periodic table so you very well know the 36 belongs to which ma'am d block 36 elements lie under the group number 18 quite easy so so not d block sorry sorry sorry P block group number 18 right the answer comes out to be a option D Block are the one with the present at the center P block on the right hand side yeah so it is p blog group number 18. answer comes out to be option number a an element with atomic number 21 is a yes everybody now this I will let you know what is the elements name element's name is candium you have to tell me the answer this is question number seven as your homework clear okay students now few more homework questions for you question number eight as your homework is in the long form of periodic table all the non-metals are placed under which block okay clear you can pause the video see the question moving on to the question number ninth question ninth is which is a metalloid that means which holds both the properties of metals and non-metals so you have four options over here this is your question number ninth then comes your last question question number tenth that is an element with atomic number 55 belongs to which block 55 clear so thank you so much my dear students this was all about today's session I hope so you enjoyed today's Class A lot now we will be meeting in the next class next class let me tell you is going to be very very important with regard to your examinations don't skip it out so let us meet in the next class till then keep smiling keep learning thank you so much and take care Maria students