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Essential Geometry Formulas and Problem Solving
May 11, 2025
Basic Geometry Review for SAT, HT, and Geometry Exams
Common Shapes and Formulas
Circle
Radius
: A line segment from the center of the circle to any point on the circle.
Circumference
:
Formula: ( C = 2\pi r )
Example: Given radius ( r = 5 ), ( C = 10\pi \approx 31.416 ) (using ( \pi \approx 3.1416 ))
Area
:
Formula: ( A = \pi r^2 )
Example: ( A = 25\pi \approx 78.54 )
Diameter
:
Definition: A line segment that passes through the center and touches two points on the circle.
Formula: ( D = 2r )
Example: ( D = 10 ) (if ( r = 5 ))
Square
All sides are equal.
Area
:
Formula: ( A = s^2 )
Example: ( A = 64 ) (if side ( s = 8 ))
Perimeter
:
Formula: ( P = 4s )
Example: ( P = 32 )
Rectangle
Area
:
Formula: ( A = \text{length} \times \text{width} )
Example: ( A = 50 ) (length 10, width 5)
Perimeter
:
Formula: ( P = 2L + 2W )
Example: ( P = 30 )
Solving Geometry Problems
Example Problem: Perimeter of a Square
Given: Area ( = 36 ) square feet
Solution: Find side ( s = \sqrt{36} = 6 ), ( P = 24 ) feet
Circle Problem: Given Circumference
Circumference ( = 16\pi )
Solution: ( r = 8 ), ( D = 16 ), Area ( = 64\pi )
Rectangle Problem
Given: Area ( = 40 ) and length ( = 8 )
Solution: Width ( = 5 ), Perimeter ( = 26 )
Solving for Missing Dimensions
Problem: Rectangle with Known Perimeter
Perimeter ( = 26 ), ( L = \text{width} + 3 )
Solution: Width ( = 5 ), Length ( = 8 ), Area ( = 40 )
Triangles
Right Triangle
Hypotenuse
: Side opposite the right angle.
Pythagorean Theorem
: ( a^2 + b^2 = c^2 )
Special Right Triangles
Common triangles:
3-4-5
5-12-13
7-24-25
8-15-17
9-40-41
11-60-61
Multiples: E.g., 6-8-10 is a multiple of 3-4-5
Example Problems
Finding missing sides using special triangles
Example: For ( 6, x, 10 ): ( x = 8 )
Additional Practice
Problem setup and solution for different geometric shapes using known equations.
Additional Resources
For ACT/SAT math preparation, search for specific practice videos on YouTube.
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