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Chemical Reactions and Quantities chapter 7

Jul 8, 2025

Overview

This lecture covers Chapter 7: Chemical Reactions and Quantities, including writing and balancing chemical equations, types of reactions, oxidation-reduction, the mole, molar mass, stoichiometry, limiting reagents, percent yield, and energy changes in reactions.

Chemical Equations & Balancing (7.1)

  • Reactants are on the left, products on the right of the reaction arrow.
  • Subscripts in chemical formulas (e.g., O₂) cannot be changed; only coefficients (amounts) can be adjusted to balance equations.
  • A balanced equation has the same number of each type of atom on both sides.
  • Examples: H₂ + O₂ → H₂O must be balanced using coefficients, not by altering formulas.

Types of Chemical Reactions (7.2)

  • Combination: Two or more substances form one product (A + B → AB).
  • Decomposition: One compound breaks into two or more substances (AB → A + B).
  • Single Replacement: One element replaces another in a compound (A + BC → AC + B).
  • Double Replacement: Two compounds exchange parts (AB + CD → AD + CB).
  • Combustion: Substance reacts with O₂ producing CO₂, H₂O, and energy.

Oxidation and Reduction (7.3)

  • Oxidation: Loss of electrons ("Oil" in OIL RIG).
  • Reduction: Gain of electrons ("Rig" in OIL RIG).
  • The oxidized element increases in charge; the reduced element decreases in charge.

The Mole & Avogadro’s Number (7.4)

  • One mole = 6.02 × 10²³ atoms, molecules, or particles.
  • Moles relate the mass of a substance to the number of particles.
  • Example: 1 mole of H₂O = 18g = 6.02 × 10²³ molecules.

Molar Mass (7.5)

  • Molar mass is the sum of atomic masses (from the periodic table) in grams per mole.
  • Example: Glucose (C₆H₁₂O₆) molar mass = 6×12 + 12×1 + 6×16 = 180 g/mol.

Calculations Using Molar Mass (7.6)

  • Convert between grams and moles using molar mass.
  • Formula: grams = moles × molar mass; moles = grams ÷ molar mass.

Mole Relationships in Chemical Equations (7.7)

  • Use coefficients from balanced equations to calculate mole ratios between reactants and products.
  • Example: If the equation is 2 Fe + 3 S → Fe₂S₃, then 2 moles Fe react with 3 moles S.

Calculating Mass in Chemical Reactions (7.8)

  • Convert given mass to moles, use mole ratio, then convert back to mass as needed.
  • Always use conversion factors to move between mass and moles.

Limiting Reagents & Percent Yield (7.9)

  • Limiting reagent: The reactant that runs out first and limits the amount of product formed.
  • Percent yield = (actual yield ÷ theoretical yield) × 100%.
  • Identify limiting reagent by comparing moles that each reactant can produce.

Energy in Chemical Reactions (7.10)

  • Exothermic reaction: Releases heat (ΔH negative), products are lower in energy than reactants.
  • Endothermic reaction: Absorbs heat (ΔH positive), products are higher in energy than reactants.

Key Terms & Definitions

  • Reactants — Substances present before the reaction.
  • Products — Substances formed by the reaction.
  • Coefficient — Number before a formula, shows quantity.
  • Subscript — Small number in a formula, shows number of atoms.
  • Mole — 6.02 × 10²³ particles of a substance.
  • Molar mass — Grams per mole of a substance.
  • Limiting reagent — Reactant used up first in a reaction.
  • Percent yield — Actual yield as a percentage of theoretical yield.
  • Exothermic — Reaction that releases heat.
  • Endothermic — Reaction that absorbs heat.

Action Items / Next Steps

  • Practice balancing chemical equations and using coefficients.
  • Complete practice problems converting between grams, moles, and molecules.
  • Calculate limiting reagents and percent yields for given reactions.
  • Review energy diagrams for exothermic and endothermic reactions.
  • Read the textbook sections 7.1–7.10 and solve end-of-chapter problems.